When I try to add an image to a product I don't get any errors, but the image doesn't get added.
This is my code:
function addImage($idProduct)
{
$key = 'XXXXXXXXXXXXXXXXXXX';
$url = "http://192.168.1.81/api/images/products/".$idProduct;
$image_path = 'image2.jpg';
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_USERPWD, $key);
curl_setopt($ch, CURLOPT_POSTFIELDS, array('image' => '#'.$image_path.';type=image/jpg'));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);
curl_close($ch);
echo '<h2>Image Added</h2>';
}
I also made a change on PSWebServiceLibrary.php, because Prestashop Web Service API keeps asking for authentication. This is the link where I got the code Prestashop Web Service API keeps asking for authentication .
This is the code I added:
$url .= '&ws_key=' . $this->key;
The problem is that the code to add an image was working before I made that change on PSWebServiceLibrary.php, and I don't know how to solve it.
I am using prestashop 1.6.1.5
Any help will be appreciated.
Greetings!
I think it's only a missing of "?" in your url.
If I follow your $url logic the result will be for product of ID 1234567 by example :
http://192.168.1.81/api/images/products/1234567&ws_key=ZOEJFD3429JD209AZJX0DJF20
So your server waits this url to hanlde ws_key as GET parameter :
http://192.168.1.81/api/images/products/1234567?ws_key=ZOEJFD3429JD209AZJX0DJF20
You need to add this "?" at the end of you URL like this :
$url = "http://192.168.1.81/api/images/products/".$idProduct."?";
Best Regards,
TGA
For me works like this:
curl_setopt($ch, CURLOPT_POSTFIELDS, array('image' => curl_file_create($image_path)));
Related
I have thist problem with Discogs API.
In this code:
echo $stats->get('songtitle');
$ch = curl_init('https://api.discogs.com/database/search?q=');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, 'GET');
$headers = array();
I need do something to first line:
echo $stats->get('songtitle');
Works before ?q=
Screenshot
Thanks for help.
If I understand what you want to do,
You're trying to concatenate you 2 strings like this :
$ch = curl_init('https://api.discogs.com/database/search?q=' . $stats->get('songtitle'));
Hello and thanks in advance, now I'm trying to upload a image to a prestashop 1.7 via webservice and I'm unable to insert a image in a product. I don't know what fails, because I don't get any response of the webservice, even with the debug enabled (I get the xml responses of the rest of the files, but not the ones from curl).
The variable $idProduct is a value passed to the function and is defined.
My code is the following:
$url = PS_SHOP_PATH."api/images/products/".$idProduct;
$dir_path_to_save = 'img/import/';
$img_path = getFile($remoteImageURL, $dir_path_to_save);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_USERPWD, PS_WS_AUTH_KEY.':');
curl_setopt($ch, CURLOPT_POSTFIELDS, array('image' => '#'.$img_path));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
$response = curl_exec($ch);
echo print_r($response);
curl_close($ch);
The getFile function downloads the image to the server where is installed the prestashop and returns the path (returns a string with the real path where the image is stored, already tested).
I tried to make a form to upload the image (just for testing), but it returns "code 66 - unable to save this image". I don't know if this helps.
Thanks
UPDATE
A fellow programmer told me to use curl_file_create()
So I changed the $img_path declaration this way:
$img = curl_file_create($dir_path_to_save.'/'.basename($img_path));
Now everything works as intended.
I am new at programming Slash commands in Slack. For one of my commands, I have a username and need to retrieve the user icon URL. I am using PHP to code them.
I was planning on using users.profile.get, since the tutorial here shows that one of the fields returned is the user icon URL.
However, I am trying to find examples on how to make a call to this method and have not found any. Could anybody give me a quick example of the call, including how to send the parameters?
This is how far I got:
$slack_profile_url = "https://slack.com/api/users.profile.get";
$fields = urlencode($data);
$slack_call = curl_init($slack_profile_url);
curl_setopt($slack_call, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($slack_call, CURLOPT_POSTFIELDS, $fields);
curl_setopt($slack_call, CURLOPT_CRLF, true);
curl_setopt($slack_call, CURLOPT_RETURNTRANSFER, true);
curl_setopt($slack_call, CURLOPT_HTTPHEADER, array(
"Content-Type: application/x-www-form-urlencoded",
"Content-Length: " . strlen($fields))
);
$profile = curl_exec($slack_call);
curl_close($slack_call);
I basically have $token and $user_name and need to get the profile picture URL. How do I format $token and $username as $data? Is the call correct?
If anybody recommends doing this a different way, I would appreciate any advice as well.
Thank you so much!
To get data into the right format to post to Slack is pretty straight forward. There's two options (POST body or application/x-www-form-urlencoded).
The query string for application/x-www-form-urlencoded is formatted like a get URL string.
https://slack.com/api/users.profile.get?token={token}&user={user}
// Optionally you can add pretty=1 to make it more readable
https://slack.com/api/users.profile.get?token={token}&user={user}&pretty=1
Just request that URL and you will retrieve the data.
The POST body format will use a similar code to what you have above.
$loc = "https://slack.com/api/users.profile.get";
$POST['token'] = "{token}";
$POST['user'] = "{user}";
$ch = curl_init($loc);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $POST);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);
if ($error = curl_errno($ch)) { echo $error; }
//close connection
curl_close($ch);
echo $result;
always: https://www.google.com/accounts/o8/ud
i got wordpress openid ok. so i think is is just discovery phase got some probelms..
<?php $ch = curl_init();
$url = 'https://www.google.com/accounts/o8/id';
$url = $url.'?';
$url = $url.'openid.mode=checkid_setup';
$url = $url.'&openid.ns=http://specs.openid.net/auth/2.0';
$url = $url.'&openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select';
$url = $url.'&openid.identity=http://specs.openid.net/auth/2.0/identifier_select';
$url = $url.'&openid.return_to='.site_url().'/user/openid/login_callback';
$url = $url.'&openid.realm=http://www.example.com/';
// set url
curl_setopt($ch, CURLOPT_URL, $url);
//return the transfer as a string
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HTTPHEADER,array("Accept: */*"));
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
// $output contains the output string
$xdr = curl_exec($ch);
if (!$xdr) {
die(curl_error($ch));
}
// close curl resource to free up system resources
curl_close($ch);
$xml = new SimpleXMLElement($xdr);
$url = $xml->XRD->Service->URI;
$request = $connection->begin($url);
$request always null...
Take a look at https://blog.stackoverflow.com/2009/11/google-offers-named-openids/ where Jeff explains this behavior and what the user can do about it:
Well, the good news is, now you can! Google just gave us a fantastic Thanksgiving Day present in the form of Google Profiles supporting OpenID. And with a Google Profile, you get to pick a named URL of your choice!
Your question has the right endpoint URL (the one ending in /ud), but your example code is sending the request to the identifier URL (/id), not the endpoint URL.
My above code do return https://www.google.com/accounts/o8/ud in $url, which is correct actually
the problem is, you do not need to use openid php lib, just redirect the user to https://www.google.com/accounts/o8/ud with query string like:
https://www.google.com/accounts/o8/ud?openid.mode=checkid_setup&......
I'm having a little trouble updating backgrounds via Twitter's API.
$target_url = "http://www.google.com/logos/11th_birthday.gif";
$ch = curl_init();
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Expect:'));
curl_setopt($ch, CURLOPT_USERAGENT, $userAgent);
curl_setopt($ch, CURLOPT_URL,$target_url);
curl_setopt($ch, CURLOPT_FAILONERROR, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_AUTOREFERER, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch, CURLOPT_TIMEOUT, 10);
$html = curl_exec($ch);
$content = $to->OAuthRequest('http://twitter.com/account/update_profile_background_image.xml', array('profile_background_image_url' => $html), 'POST');
When I try to pull the raw data via cURL or file_get_contents, I get this...
Expectation Failed The expectation given in the Expect request-header
field could not be met by this server.
The client sent
Expect: 100-continue but we only allow the 100-continue expectation.
OK, you can't direct Twitter to a URL, it won't accept that. Looking around a bit I've found that the best way is to download the image to the local server and then pass that over to Twitter almost like a form upload.
Try the following code, and let me know what you get.
// The URL from an external (or internal) server we want to grab
$url = 'http://www.google.com/logos/11th_birthday.gif';
// We need to grab the file name of this, unless you want to create your own
$filename = basename($url);
// This is where we'll be saving our new file to. Replace LOCALPATH with the path you would like to save the file to, i.e. www/home/content/my_directory/
$newfilename = 'LOCALPATH' . $filename;
// Copy it over, PHP will handle the overheads.
copy($url, $newfilename);
// Now it's OAuth time... fingers crossed!
$content = $to->OAuthRequest('http://twitter.com/account/update_profile_background_image.xml', array('profile_background_image_url' => $newfilename), 'POST');
// Echo something so you know it went through
print "done";
Well, given the error message, it sounds like you should load the URL's contents yourself, and post the data directly. Have you tried that?