I'm using Laravel 5.2. In my application, if a user is an admin, he can see all groups. Otherwise, he can only see his groups.
Model
public function groups() {
if ($this->isAdmin()) {
return \App\Group::get();
}
return $this->belongsToMany('App\Group');
}
View
#foreach($user->groups as $group)
{{ $group->name }}
#endforeach
Result
The code above works if the user is not an admin, but I get this error if the user is an admin
Relationship method must return an object of type Illuminate\Database\Eloquent\Relations\Relation
I tried this instead: $user->groups() as $group, it works when the user is an admin, but show nothing when it's not an admin.
Question
I know when I call a relation as a property ($user->groups), it returns a collection of objects. Instead, if I call it as a function ($user->groups()), I get a QueryBuilder instance.
What can I do to use the same syntax as in my view ?
Note: I cannot add all groups in the database to the admin, as admins must have no group.
The way is not using directly relationship for this but using extra method to handle this.
First in your model create simple relationship:
public function groups()
{
return $this->belongsToMany('App\Group');
}
and then create extra method:
public function availableGroups()
{
if ($this->isAdmin()) {
return \App\Group::get();
}
return $this->groups;
}
Now in view you can use:
#foreach($user->availableGroups() as $group)
{{ $group->name }}
#endforeach
Related
I'm trying to display a tag that is selected by the user. The tag name is in the tags table. The tagpost table has the mapping between the tag and the user.
The following is the User model, where the primary key in users table is id, and var_id can be many types and 2 is for users (not sure if the below where condition is correct):
public function tagpost()
{
return $this->hasMany('App\tagpost', 'var_id')->where('type',2);
}
The following is the tagpost model:
public function tags()
{
return $this->belongsToMany('App\tag','id');
}
public function users()
{
return $this->belongsToMany('App\User');
}
The following is the tag model :
public function tagposts()
{
return $this->hasMany('App\tagpost', 'var_id');
}
The following query is not working in the blade :
<option>{{ Auth::user()->tagpost()->tags()->select('t_name')->first()->t_name}} </option>
Error in blade :
Call to undefined method Illuminate\Database\Query\Builder::tags()
You are calling the relations as method whereas they should be called as property like this. Also i suggest you the laravel documentation
<option>{{ Auth::user()->tagpost->tags->select('t_name')->first()->t_name}} </option>
If tagpost is just the relation table why don’t you define a method tags() on the User model, using the tagposts table as the pivot so you can just do Auth::user()->tags()?
Your code won’t work because ->tagpost() returns the Relation itself and not the tagpost models...
I have two table as sbj_topics and difficulty_level_sbj_topic so, I want to define relationship b\w them to fetch records, so to make relationship I have done this,
SbjTopic.php:
public function difficulty_level_sbj_topic() {
return $this->hasMany('App\DiffiLvlSbjTopic');
}
And in DiffiLvlSbjTopic.php:
protected $table = 'difficulty_level_sbj_topic';
public function sbj_topics() {
return $this->belongsTo('App\SbjTopic');
}
After that I returned the data to a view as:
$easy = DiffiLvlSbjTopic::where(['subject_id' => $id, 'difficulty_level_id' => 2])->get();
return view('diffi_lvls.show', compact('easy'));
Then in the view I done this:
#foreach($easy as $easy)
{{ $easy->sbj_topics }}
#endforeach
but the page is blank, and when I do this {{ $easy->sbj_topics->sbj_topic_name }} trying to get property of undefined! comes.
The main purpose of creating relationship is to display Subject Topic Name because I have foreign key as sbj_topic_id in difficulty_level_sbj_topic table so if anyone has any other idea to do this without relationship that will be awesome.
Break this down:
SbjTopic - has many difflevels
a difflevel belongs to aSbjTopic
With this understanding, I can see you are getting the difflevels (DiffiLvlSbjTopic). This is actually what you are passing to your blade.
So first off: complete your relationship by specify the foreign keys. i.e:
In the SbjTopics model:
public function difficulty_level_sbj_topic() {
return $this->hasMany('App\DiffiLvlSbjTopic', 'subject_id');
}
with this, you know that in the 'difficulty_level_sbj_topic' you must have the column subject_id.
Now define the reverse relationship in your DiffiLvlSbjTopic model:
public function sbj_topics() {
return $this->belongsTo('App\SbjTopic', 'subject_id');
}
With all these in place in your controller or route all you need to do is fetch the DiffiLvlSbjTopic model properties. For instance:
public function index () {
$easy = DiffiLvlSbjTopic::all();
return view('diffi_lvls.show', compact('easy'));
}
Finally in your view:
#foreach($easy as $difflevel)
<div>{{ $difflevel->sbj_topics->name }} </div>
#endforeach
That's it.
Your both variables should not be $easy it can be something like $easy as $easySingle. And add a loop inside like
#foreach($easy as $easySingle)
foreach ($easySingle->sbj_topics as $topic) {
$topic->property;
}
#endforeach
I would like to known how to get data from database in blade like from User table:
{{ Auth::user()->name }}
I have table user_settings
I would like to get record from this table by logged user id like this:
{{ UserSettings::user()->my_field }}
How can I do that?
Try this on your blade view
{{ \App\UserSettings::where('user_id',Auth::user()->id)->first()->my_field }}
In default, model file is inside App folder.
Such direct access to database table is not preferred though, you can return this as a variable from controller function like,
$field = \App\UserSettings::where('user_id',Auth::user()->id)->first()->my_field;
return view('view_name',comapact('field'));
and use in blade like
{{$field}}
Another good way is posted by Orkhan in another answer using eloquent relationship.
Hope you understand.
You need to retrieve the UserSettings associated to the authenticated user:
UserSettings::where('user_id', Auth::id())->first()->my_field
You can defined a method named current() to return that for you.
class UserSettings extends Model
{
public static function current()
{
return UserSettings::where('user_id', Auth::id())->first()
}
}
Then use:
UserSettings::current()
On the other had it would better to use one-to-one relationship on user model:
class User extends Model
{
public function settings()
{
return $this->hasOne('App\UserSettings');
}
}
Then use:
Auth::user()->settings->my_field
I am using Laravel 5.3 along with Twig templating engine (Not Blade). I am trying to generate a list of drop-down list in the form. Instead of showing just the values. It is showing the keys as well.
For example:
{"display_name":"Admin"}
In my view the code is
{{ form_select('roles', roles, input_get('role'), {id:'user_type',class:'form-control'}) }}
In the controller
public function create()
{
$roles = Role::all('display_name');
return view('users.user-add')->with(['roles' => $roles]);
}
What am I missing?
I would suggest you to create a helper for this so that there is no requirement for you to pass roles from every controller to every view. Create a helper function like this :
if(!function_exists('getRoles'))
{
function getRoles()
{
$roles = Role::get();
foreach ($roles as $role)
{
$results[$role->id] = $role->name;
}
return $results;
}
}
and now in your template do :
{{ form_select('roles', getRoles(), input_get('role'), {id:'user_type',class:'form-control'}) }}
I hope I understood your question as intended and this helps you achieve what you are looking for.
I get all items owned by authenticated user.
$items=Auth::user()->with('items')->get();
In my view i can access items collection, but instead of title_id want to retrieve item_title value.
Currently i'm able to get item_title value using code below:
$item->title->title
Is it possible to simplify it to retrieve title like this:
$item->title
?
Here is my models and relations:
Users
id
username
Item
id
user_id
title_id
Item_Titles
id
title
User model:
public function items()
{
return $this->hasMany('Item', 'user_id', 'id');
}
Item model:
public function user(){
return $this->belongsTo('User', 'user_id', 'id');
}
public function title()
{
return $this->belongsTo('ItemTitle','title_id','id');
}
ItemTitle model:
public function item()
{
return $this->hasMany('Item', 'title_id', 'id');
}
UPDATE
Excuse me probably I wasn't clear. To be precise - I just want to find Eloquent alternative to:
$items=Item::where('user_id','=',Auth::id())->leftJoin('item_titles', 'item.title_id', '=', 'item_titles.id')->get();
#foreach ($items as $item)
{{ $item->title }}
#endforeach
Just change your relationship function to
Item model:
public function title()
{
return $this->belongsTo('ItemTitle','title_id','id')->first()->title;
}
You will need to call it as $item->title() unless you also do
public function getTitleAttribute(){
return $this->title();
}
You might get some funny stuff with everything being called 'title' but with this $item->title should also work I think
Yes it is. It looks like you setup a many-to-many relationship with the Item model being the pivot table.
User Model
public function titles()
{
return $this->belongsToMany('ItemTitle', 'items');
}
Note: Change ItemTitle to the correct namespace. Also, change items to the Item model's table name.
You can also define the inverse relationship like this:
ItemTitle Model
public function users()
{
return $this->belongsToMany('User', 'items');
}
From there, you can get all the authenticated user's ItemTitles like this:
$titles = Auth::user()->titles;
Link to the documentation: https://laravel.com/docs/5.1/eloquent-relationships#many-to-many
Editing based on the comments below (thanks to #ash for helping clarify and for his suggestion):
The other answer is more along the lines of what you are trying to achieve so I would recommend taking a look at that. However, there is an error in your question. This does not return items:
$items=Auth::user()->with('items')->get();
That returns all users with their items eager loaded. To see proof of this, if you dd($items), you will most likely see every single user in the database.
That is most likely not what you want to do. To get all items for the authenticated users, you should do this:
$items = Auth::user()->items;
It's that simple to get a collection of items. This will run 2 queries - 1 to get the user and another to get all of his items.