I need only to display the last values in the row. Now its displaying
Message for: Rocha : gff
Message for: Rocha :
Message for: Rocha : hi my name is kenny
I only need it to display Message for: Rocha : hi my name is kenny.
Thank you
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "company";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, className, lastname, messages FROM Mymesages";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
if("CPS210-CompSci-I (4)"==$row["className"] && $lastname== $row["lastname"]){
echo "Message for: " . $row["lastname"]. " : " . $row["messages"]. "<br>";
}
}
}
$conn->close();
?>
If you're looking for only one record, that too the last one, you just need to modify your query a little. Also, there's no need for the loop in that case.
$sql = "SELECT id, className, lastname, messages FROM Mymesages ORDER BY id DESC LIMIT 1";
Replace this line:
while($row = $result->fetch_assoc()) {
With simply:
$row = $result->fetch_assoc();
If you want to display the last row, then your query should be like this:
$sql = "SELECT id, className, lastname, messages FROM Mymesages ORDER BY id DESC LIMIT 1";
And later, instead of while loop simply fetch the row like this:
$row = $result->fetch_assoc();
Related
i want to take the result of an sql query "user_id"and search using it in
in another query in another table
for example :
main query select * from tracker
second query: take the id from the first query to replace it with the name of the user found in another table "user table".
something like :
select user_name from vtiger_users where id = $row["id"]
here is my code below
<?php
$servername = "localhost";
$username = "x";
$password = "xyz";
$dbname = "dbname";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, module, whodid,changedon FROM vtiger_modtracker_basic";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table style='float: left'><tr><th>ID</th><th>Module</th><th>Who Did</th><th>Time Of Action</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
$user_id=$row["id"];
$username_sql="SELECT user_name FROM vtiger_users where id=".$user_id." ";
$result_username=$conn->query($username_sql);
$row2 = $result_username->fetch_assoc();
echo "<tr><td>".$row["id"]."</td><td>".$row["module"]."</td><td>".$row2["user_name"]."</td><td>".$row["changedon"]."</td></tr>";
//echo "<p>".$row2["user_name"]."</p>"
//echo $row2["user_name"];
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
I guess you should use whodid column when you set $user_id = $row['whodid'] or you can use JOIN query. It will return you user_name from vtiger_users table.
SELECT
a.id,
a.module,
a.whodid,
a.changedon
b.user_name
FROM vtiger_modtracker_basic a
JOIN vtiger_users b ON a.whodid = b.id
thanks all ,that query did the job for me
SELECT vtiger_modtracker_basic.id, vtiger_modtracker_basic.module, vtiger_modtracker_basic.whodid ,vtiger_modtracker_basic.changedon ,vtiger_users.user_name FROM vtiger_modtracker_basic ,vtiger_users where vtiger_modtracker_basic.whodid = vtiger_users.id
I am calculating AGE by DATE from DOB field, then I want to push it into AGE with correct age based on DOB . So As I debug The DOB calculating to AGE is works, but it cannot update AGE the code:
<?php
$servername = "localhost";
$username = "usernameexmaple";
$password = "passworking";
$dbname = "dbnameworking";
// Create connection
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id as ID, YEAR(CURRENT_TIMESTAMP) - YEAR(dob) - (RIGHT(CURRENT_TIMESTAMP, 5) < RIGHT(dob, 5)) as age
FROM regio_users";
$sql2 = ("UPDATE regio_users SET age = '$newage' WHERE id ='$newid' ");
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$newage = $row['age'];
$newid = $row['ID'];
$sql2 = ("UPDATE regio_users SET age = '$newage' WHERE id ='$newid' ");
$result2 = $conn->query($sql);
if ($result2){
echo "done"."<br>";
}
}
}
else {
echo "0 results";
}
$conn->close();
?>
It echos DONE for every ID but not updating anything at all.
You have used $result2 = $conn->query($sql); which is incorrect. You have to use $result2 = $conn->query($sql2); as $sql2 is the new query you formed.
This can be done with a single line SQL, rather than using PHP to loop through all the rows to only update the age:
UPDATE `regio_users` SET `age` = YEAR(CURRENT_TIMESTAMP) - YEAR(`dob`) - (RIGHT(CURRENT_TIMESTAMP, 5) < RIGHT(`dob`, 5));
As saty pointed, use correct variable name.
Check if autocommit is on. If not, make sure you commit the data. Check for its syntax in PHP.
$servername = "localhost";
$username = "root";
$password = "admin";
$dbname = "register";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT email FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<br> email: " . $row["email"] . "<br>";
}
}
I am trying to get only the last row and the email column. The method that I am doing takes every row, with the email column. If somebody could adjust my code and comment it, I would really appreciate it.
You want to
To get the LAST row sort the results descending on a fields that gets incremented with every new row like the auto increment field [I am assuming that id] ( ORDER BY id DESC)
limit the rows returned to 1 ( LIMIT 1 )
So try this query instead
SELECT email FROM users ORDER BY id DESC LIMIT 1
In your code
$sql = "SELECT email FROM users ORDER BY id DESC LIMIT 1";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
$row = $result->fetch_assoc();
echo "<br> email: " . $row["email"] . "<br>";
}
Quick & Simple:
$sql = 'SELECT U.email FROM users AS U ORDER BY U.id DESC LIMIT 1';
$result = $conn->query($sql);
$row = $result->fetch_object();
echo 'Email ID>> '.$row->email;
I am new at this and learning the code.
I want to create the php code which select the particular row.
say 5th row or 6th row any row.
I create the code like this
<?php
$servername = "localhost";
$username = "test1";
$password = "pass";
$dbname = "test1";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT FIELD1, FIELD2 FROM mytable ";
$result = $conn->query($sql);
if ($result->num_rows > 0)
{
// output data of each row
while($row = $result->fetch_assoc()) {
echo "id: " . $row["FIELD1"]. " - Name: " . $row["FIELD2"]. " <br>";
}
} else
{
echo "0 results";
}
$conn->close();
?>
THis code works fine but it give the all data of the table.I want to just select particular row number data.how to do this??
You can do it with the LIMIT statement, say LIMIT 3,1 to select the 4th row. First number is the starting row, second number is the count of rows to select.
$sql = "SELECT FIELD1, FIELD2 FROM mytable LIMIT $row_index, 1";
will give you row $row_index + 1
You can do it using WHERE condition in query as SELECT FIELD1, FIELD2 FROM mytable WHERE id = 1.
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "comp4";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT OrderID, id, items FROM orders WHERE id= $user";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$results = $row["OrderID"]. " " . $row["id"]. $row["items"]. "<br>" ;
}
$loop = implode( " ", $items );
echo $loop;
}
?>
So, I have this code and I'm trying to display OrderID, id and items from the user thats logged in $user=whoever's logged in that's in a different part of my code, however I keep getting an error
Notice: Trying to get property of non-object in C:\xampp\htdocs\myorders.php on line 35
After looking around, I'm still not quite sure how to fix this. Any help is appreciated
I'm guessing your error lies in this line of code:
$sql = "SELECT OrderID, id, items FROM orders WHERE id= $user";
It could be that ID is a reserved keyword of SQL, or that $user is undefined and/or not a numeric value.
Try the following:
$sql = "SELECT `OrderID`, `id`, `items` FROM `orders` WHERE id = $user";
The reason for the error is your query fails. Then you later do the following:
if ($result->num_rows > 0) {
And since the query failed, $result is not an object, and you try to access num_rows of this non-object.
Of course I am only guessing because we need more information :)