I am working on a php form using POST and use dynamic HTML tables. I truncate the DB table every time before inserting the data in to the table which seems fine.
Select query when the page loads (to update UI part)
$query = 'SELECT * FROM TABLENAME';
$result = mysqli_query($dbConnection, $query);
$rows = array();
if(!$result)
{
//log error
}
if ($result->num_rows > 0)
{
while($row = $result->fetch_assoc())
{
print_r( $row);
$rows[] = $row;
}
}
Insert part
if(isset($_POST['u']))
{
foreach($_POST['u'] as $key => $value)
{
$ky = $_POST['x'][$key];
$query = "INSERT INTO TABLENAME (ID,KY) VALUES ($value, '$ky')";
$result = mysqli_query($dbConnection, $query);
}
}
However, upon posting, when using select query, it seems to not get the latest records inserted, I made sure to check the records are inserted properly in PhpMyadmin.
When I reload the page, it works fine. Only thing is it's not getting the updated records when it's POSTed, but works the subsequent times.
I thought it could be due to connection object and tried to use different connections objects with no luck.
INFO: Not sure if it has any impact, the database is a wordpress and I created new table in this database for this.
Thanks in advance...
The problem is that you need to do a SELECT query after your INSERT query in order to get the full data set.
You might consider posting to a separate page, and then redirect the user back to the original page after the INSERT. This will cause the SELECT to run again, since the page reloads.
Related
I'm not sure if I am asking this the correct way, but I want to run a query on an Oracle database, fetch the result, and then run additional queries on that result dataset. Is that possible? I am trying to avoid another call to the database.
$query = "SELECT * FROM MY.TABLE ";
$stid = oci_parse($connection, $query);
oci_execute($stid);
while ($row = oci_fetch_array($stid, OCI_ASSOC+OCI_RETURN_NULLS_OCI_RETURN_LOBS)) {
//my code for the full dataset
}
Then I would like to do something like
PSUEDO-CODE
$newDataset = runThisQuery("SELECT * FROM [oci dataset from above(what is that syntax?)] WHERE my_value = 1");
while($newRow = loop through $newDataset){
//my code for the subquery
}
Any suggestions?
To further describe my problem: I am getting a table of fields, and from that table I would like to extract the unique values of certain fields into their own php arrays.
How do I echo the latest values in column1? The below code echos the values before the update.
while($line = mysql_fetch_array($result)) {
$Student = $line["calss8"];
$querySf = "SELECT SUM(ABC) AS val1 FROM tbl1 WHERE student = '$Student'";
$resultSf = mysql_query($querySf);
$rSf = mysql_fetch_array($resultSf);
$totalSf = $rSf['val1'];
$totTMonth = $totalSf;
mysql_query("UPDATE tbl4 SET column1 = $totTMonth WHERE student = '$Student' LIMIT 1");
}
echo $line["column1"].",,";
As far as I know, you'll have to make a separate query to see what was just updated. I mean, run your select, perform your update, then do another select. You can get general information like how many rows were updated, but I don't think you can get specific information like the changed values in a column. Phil was right in suggesting that you should just print out the '$totTMonth' value since that is what you are updating your column with. That would be less overhead than doing another query to the database.
I think that problem starts before the code above. This code line will display the select results :echo $line["column1"].",,";. The variable $line is set before the code above. My solution is to do the following:
$result1 = mysql_query("SELECT column1 FROM student ..."); /* I insert the select query here */
While($row= mysql_fetch_array($result)) {
echo $row['column1'].",,";
}
It was working before and maybe someone made changes to the code and I cant detect the problem after much debugging so hopefully someone can help.
I have an html form that lets a user choose a set of option and then on form submit, POSTS these options in an array which works perfectly fine. Then I am writing the elements of an array to a MySQL table and this is where the problem occurs. My code was working fine before but now its all weird. The outputs mix up for some reason.
Below is the array values passed and then the output below the arrays.
Here is my code that writes the array values to MySQL:
error_reporting(-1);
$arr=$_POST["itemsToAdd"];
$cal=$_POST["calendar"];
print_r($arr);
// Make a MySQL Connection
//empty table first to remove any previous old on-calls stored.
$query = "truncate table ProdOnCallSetup";
if(mysql_query($query)){
}
else{
}
foreach ($arr as &$value) {
// Insert a row of information into the table "ProdOnCallSetup"
mysql_query("INSERT INTO ProdOnCallSetup
(Email) VALUES('$value') ")
or die(mysql_error());
}
Here is the code giving the output or displaying the rows in MySQL:
<ol class=”list_style”>
<?php
//make MySQL connection
$query = "SELECT * FROM ProdOnCallSetup";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<li>".$row['Email']."</li>";
echo "<br />";
}
?>
</ol>
See the problem here? Even though I write them in the correct order in MySQL when I display them the order mixes up. Order is Justin, Achau, Chellatamby but when I echo is out from the DB its Achau, Chellatamby, Justin
Unless you specifically use an ORDER BY clause in your SELECT statement, the order in which rows are returned is indeterminate and may change.... it doesn't matter what order you added the records in, this is irrelevant... use ORDER BY...
SELECT * FROM ProdOnCallSetup ORDER BY Email
(or whatever column id you want to order them on)
If you want to order them in the order you added them to the database, you'll need an autoincrement column on the table, and order by that column
I'm not sure how to accomplish this issue which has been confusing me for a few days. I have a form that updates a user record in MySQL when a checkbox is checked. Now, this is how my form does this:
if (isset($_POST['Update'])) {
$paymentr = $_POST['paymentr']; //put checkboxes array into variable
$paymentr2 = implode(', ', $paymentr); //implode array for mysql
$query = "UPDATE transactions SET paymentreceived=NULL";
$result = mysql_query($query);
$query = "UPDATE transactions SET paymentdate='0000-00-00'";
$result = mysql_query($query);
$query = "UPDATE transactions SET paymentreceived='Yes' WHERE id IN ($paymentr2)";
$result = mysql_query($query);
$query = "UPDATE transactions SET paymentdate=NOW() WHERE id IN ($paymentr2)";
$result = mysql_query($query);
foreach ($paymentr as $v) { //should collect last updated records and put them into variable for emailing.
$query = "SELECT id, refid, affid FROM transactions WHERE id = '$v'";
$result = mysql_query($query) or die("Query Failed: ".mysql_errno()." - ".mysql_error()."<BR>\n$query<BR>\n");
$trans = mysql_fetch_array($result, MYSQL_ASSOC);
$transactions .= '<br>User ID:'.$trans['id'].' -- '.$trans['refid'].' -- '.$trans['affid'].'<br>';
}
}
Unfortunately, it then updates ALL the user records with the latest date which is not what I want it to do. The alternative I thought of was, via Javascript, giving the checkbox a value that would be dynamically updated when the user selected it. Then, only THOSE checkboxes would be put into the array. Is this possible? Is there a better solution? I'm not even sure I could wrap my brain around how to do that WITH Javascript. Does the answer perhaps lie in how my mysql code is written?
--
Edit: Ok, just more information. The SQL Queries I have going on - the first two are to wipe everything clean (in case a checkbox is UNCHECKED) and then next they are updating the SQL queries based on which checkboxes are checked upon post.
However, I'm thinking this is a bad way to do it. Why force the database to first wipe out ALL data for paymetreceived, paymetdate? The problem with this, also, is that *all the subsequent checkboxes, regardless of how long ago they were checked, get updated in the SQL query as it is now.*There's got to be a way to update it better. I'm just not sure HOW to do it. any ideas?
You are not filtering by id in this queries:
$query = "UPDATE transactions SET paymentreceived=NULL";
$query = "UPDATE transactions SET paymentdate='0000-00-00'";
Try adding: WHERE id IN ($paymentr2)";
The problem is in your first 2 sql UPDATE statements. You don't provide a WHERE clause, so that's going to update all your records. You could add:
WHERE id IN ($paymentr2)
to your first two UPDATE statements
I'm trying to write my first PHP script with mySQL and I desperately need some help. I'm sure this is relatively simple, but if I have one field in my table (username, for example), and I want to fetch another field (name, for example), that is in the same row as the given username, how do I do that?
Again, I'm sure this is easy, but I'm lost, so I'd really appreciate any help. Thanks!
$sql = "SELECT username, name FROM table";
$result = mysql_query($sql);
while($row = mysql_fetch_assoc($result)) {
echo "This {$row['username']} has the name {$row['name']}\n";
}
halfdan's answer sort of works, but it fetches all rows and displays them. What you want is a WHERE clause, which lets you filter the contents of the table so the query only returns the row(s) you want:
SELECT username, name
FROM sometable
WHERE (username = 'johndoe');
This will return only the rows where the username field is equal to 'johndoe'. Conceptually, it's equivalent to:
$results = mysql_query("SELECT username, name FROM table");
while($row = mysql_fetch_assoc($results)) {
if ($row['username'] == 'johndoe') {
// do something, this is a row you want
} else {
// not a row you want. ignore it, or deal with it some other way
}
}
the main difference is that for large data sets in the database, doing client-side filtering like this is expensive, as the entire contents of the table has to be transferred over. Using a WHERE clause to limit things to just what you want is far more efficient in the long run.