Create php array from one of all column that retrieve from mysql - php

Question

I am a newbie on PHP,MySQL and HTML.
I have one question about php array.
I create MySQL query that joins 2 tables in php. From this join, I will get information about one product, but have multiple JIG.
$sql = "SELECT product.product_number,product.product_name,product.product_jitqty,product.product_desc,jit.jit_number,jit.jit_name,jit.jit_drawer,jit.jit_port,jit.jit_specpath
FROM product
JOIN production_jit
ON production_jit.product_number = product.product_number
JOIN jit
ON jit.jit_number = production_jit.jit_number
WHERE product.product_number = '$productnumber'";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result))
{ }
from above query, I will get result like picture below.
So I want to create an array for column jit.jit_number. for easy to transfer both or only one data to another page.
I have tried below code.
$sql = "SELECT product.product_number,product.product_name,product.product_jitqty,product.product_desc,jit.jit_number,jit.jit_name,jit.jit_drawer,jit.jit_port,jit.jit_specpath
FROM product
JOIN production_jit
ON production_jit.product_number = product.product_number
JOIN jit
ON jit.jit_number = production_jit.jit_number
WHERE product.product_number = '$productnumber'";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
?>
<?php
while($row = mysqli_fetch_assoc($result))
{
$jig = array ($row['jit_number']);
echo "This is JIG " . $jig[0] . ", " . $jig[1] . ".";
}
But the result is like picture below.
Can anyone help me? So if I want to transfer both data to another page, I just can use $jig[0] and $jig[1]. Or anyone can advise me the better way to transfer multiple data form mysql to another page.

Answer 1

I'm not really sure what you're trying to achieve, but $jig is not going to have two indices because $row['jit_number'] ist just a number itself. If you're trying to store all jit_numbers in a separate array, you could try something like this:
$numbers = array();
while($row = mysqli_fetch_assoc($result))
{
$numbers[] = $row['jit_number'];
}
You shall also try to prevent MySQL injection, WHERE product.product_number = '$productnumber'"; is rather horrible from a security point of view. Using a prepared statement or at least some sanitization / escaping is recommendable.

Answer 2

Try this->
$jig = array();
array_push($jig, $row['jit_number']);