PHP form in HTML, won't connect - php

Question

So I am very new to PHP,and databases in general, so please be indulgent! :)
I created a simple form in an HTML file:
<h1> Créez votre compte ici</h1>
<form action="form.php" method="post">
<p id="textdone"> </p>
<input type= "text" name="Surname" autocomplete="on" placeholder="Votre nom" required/> <br> <br>
<input type= "text" name="Name" autocomplete="on" placeholder ="Votre prenom" required/> <br> <br>
<input type= "email" name="Email" autocomplete="on" placeholder ="Adresse mail" required/> <br><br>
<input type= "text" name="Pseudo" autocomplete="off" placeholder ="Votre pseudo" maxlength="20" required/> <br>
<p>Ajoutez une photo de profil: <input type= "file" /> <br><br></p>
<p> Entrez un mot de passe: <input type="Password" name="Passwird" autocomplete="off" maxlength="20" required placeholder="Mot de passe"/> <br><br>
Validez votre mot de passe: <input type="password1" autocomplete="off" maxlength="20" required placeholder="Mot de passe"/> <br><br>
</p>
<input type="submit" value="Soumettre"/>
</form>
</body>
And so my action file, the form.php file, saved in the same folder (I made sure) is as follows:
<?php
define('DB_NAME', 'Matchy');
define('DB_USER', 'root#localhost');
define('DB_PASSWORD', '');
define('DB_HOST', 'localhost');
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if (!$link){
die('Could not connect: ' .mysql_error());
}
$db_selected = mysql_select_db(DB_NAME, $link);
if (!$db_selected){
die('Can\'t use' . DB_NAME. ':'. mysql_error());
}
echo 'Successful connection';
$surname = $_POST['Surname'];
$name = $_POST['Name'];
$email = $_POST['Email'];
$pseudo = $_POST['Pseudo'];
$password = $_POST['Password'];
$sql = "INPUT INTO users (Name) VALUES ('$name')";
$sql1 = "INPUT INTO users (Surname) VALUES ('$surname')";
$sql2 = "INPUT INTO users (Pseudo) VALUES ('$pseudo')";
$sql3 = "INPUT INTO users (Email) VALUES ('$email')";
$sql4 = "INPUT INTO users (Password) VALUES ('$password')";
if (!mysql_query($sql)) {
die ('Error: ' .mysql_error());
}
if (!mysql_query($sql1)) {
die ('Error: ' .mysql_error());
}
if (!mysql_query($sql2)) {
die ('Error: ' .mysql_error());
}
if (!mysql_query($sql3)) {
die ('Error: ' .mysql_error());
}
if (!mysql_query($sql4)) {
die ('Error: ' .mysql_error());
}
mysql_close();
?>
But every time I fill out my form and hit submit, I get this message:
Cannot Post /form.php.
I get this code from this following video (https://www.youtube.com/watch?v=wp6Ngpk5XiY&index=2&list=PL530D33D6E548481F), which was very useful. But I really can't connect. I created my table on my database, with all the right columns.
I use phpMyAdmin.
Thank you so much to anyone who can help!! :)

Answer 1

Let's outline the errors here.
INPUT INTO isn't a valid MySQL expression, the syntax is INSERT INTO.
Then you have name="Passwird" and $_POST['Password'] which do not match and error reporting http://php.net/manual/en/function.error-reporting.php would have told you about it.
Then as outlined in comments by another member:
<input type="password1" autocomplete="off" maxlength="20" required placeholder="Mot de passe"/> this one is providing no love too. No inputtype password1 – Hendra Nucleo
which should have been password and not password1.
Best to use the right and official references http://dev.mysql.com/doc/en/insert.html and switch to PDO with prepared statements or mysqli_* with prepared statements, as the mysql_* functions are deprecated. The official manuals are the best references.
They won't steer you wrong ;-)
That tutorial probably didn't mention anything about SQL injection, so that's a good read in its own right.
Nor did it mention anything about passwords.
I noticed that you may be storing passwords in plain text. This is not recommended.
Use one of the following:
CRYPT_BLOWFISH
crypt()
bcrypt()
scrypt()
On OPENWALL
PBKDF2
PBKDF2 on PHP.net
PHP 5.5's password_hash() function.
Compatibility pack (if PHP < 5.5) https://github.com/ircmaxell/password_compat/
Other links:
PBKDF2 For PHP
Important sidenote about column length:
If and when you do decide to use password_hash() or the compatibility pack (if PHP < 5.5) https://github.com/ircmaxell/password_compat/, it is important to note that if your present password column's length is anything lower than 60, it will need to be changed to that (or higher). The manual suggests a length of 255.
You will need to ALTER your column's length and start over with a new hash in order for it to take effect. Otherwise, MySQL will fail silently.
Edit:
That whole block of code could have easily been done in a few lines, such as and without so many calls to the same table:
$sql = mysql_query("
INSERT INTO users (Name, Surname, Pseudo, Email, Password)
VALUES ('$name', '$surname', '$pseudo', '$email', '$password')
");
if($sql){
echo "Success!";
}
else { "Error: " . mysql_error(); }

Answer 2

Yeah, #gmiley raised a good question, check whether you can use input or not and instead use insert query with all the values in single statement. For syntax, you can refer the following link:http://www.w3schools.com/sql/sql_insert.asp