I'm using the below code to query an access database using PHP.
<?php
// Create an instance of the ADO connection object
$conn = new COM ("ADODB.Connection") or die("Cannot start ADO");
// Define the connection string and specify the database driver
$connStr = "PROVIDER=Microsoft.Ace.OLEDB.12.0;Data Source=".realpath("HS_BE.accdb").";";
// Open the connection to the database
$conn->open($connStr);
// Declare the SQL statement that will query the database
$query = "SELECT TOP 20 * FROM Valuations WHERE Consultant = '1'";
// Execute the SQL statement and return records
$rs = $conn->execute($query);
$num_columns = $rs->Fields->Count ();
$arrColumns = array();
for ($i=0; $i < $num_columns; $i++) {
$arrColumns[] = $rs->Fields($i);
$newArr[] = $rs->Fields($i)->name;
}
$arrResult = array();
while (!$rs->EOF) {
$arrRow = array();
for ($i=0; $i < $num_columns; $i++) {
$arrRow[$newArr[$i]] = $arrColumns[$i]->value;
}
$arrResult[] = $arrRow;
$rs->MoveNext();
}
header('Content-Type: application/json');
echo json_encode($arrResult);
This is half working, all the text fields are returning fine but the date fields are returning as {} with nothing inside, does anyone know why its choosing to ignore the date fields?
EDIT
When i var_dump $arrResult before converting to json, this is what one of the dates is :
["Appointment"]=>
object(variant)#77 (0) {
}
You most likely need to add charset=utf8 to your connection or to utf8_encode() the date before you json_encode() it.
You could also use:
mysql_query('SET CHARACTER SET utf8')
before your SELECT query.
i did this :
$arrRow[$newArr[$i]] = (string)$arrColumns[$i]->value;
Converting it to a string and it worked
Related
This question already has answers here:
Building a HTML table using MySQL/PHP results
(3 answers)
Closed 5 years ago.
The following is a PHP code that I'm using to convert a MySQL table into csv output. However, I couldn't figure out how to convert MySQL_field_name to the equivalent in MySQLI. Can anyone assist?
<?php
/* vars for export */
// database record to be exported
$db_record = 'manufacturing_';
// optional where query
$where = 'WHERE 1 ORDER BY 1';
// filename for export
$csv_filename = 'db_export_'.$db_record.'_'.date('Y-m-d').'.csv';
// database variables
$hostname = "localhost";
$user = "XXXXXXXXX";
$password = "XXXXXXXXX";
$database = "XXXXXXXXX";
// Database connecten voor alle services
$connection = mysqli_connect($hostname, $user, $password) or die('Could not connect: ' . mysqli_error());
mysqli_select_db($connection, $database) or die ('Could not select database ' . mysqli_error());
// create empty variable to be filled with export data
$csv_export = '';
// query to get data from database
$query = mysqli_query($connection, "SELECT * FROM ".$db_record." ".$where);
$field = mysqli_num_fields($query);
// create line with field names
for($i = 0; $i < $field; $i++) {
$csv_export.= mysqli_field_name($connection, $query,$i).';';
}
// newline (seems to work both on Linux & Windows servers)
$csv_export.= '
';
// loop through database query and fill export variable
while($row = mysqli_fetch_array($connection, $query)) {
// create line with field values
for($i = 0; $i < $field; $i++) {
$csv_export.= '"'.$row[mysqli_field_name($connection, $query,$i)].'";';
}
$csv_export.= '
';
}
// Export the data and prompt a csv file for download
header("Content-type: text/x-csv");
header("Content-Disposition: attachment; filename=".$csv_filename."");
echo($csv_export);
?>
Error Message:
Fatal error: Call to undefined function mysqli_field_name()
You can get this infos from INFORMATION_SCHEMA with a query like this. you only must change the TABLE_SCHEMA and the TABLE_NAME
SELECT COLUMN_NAME
FROM information_schema.columns
WHERE TABLE_NAME ='owner' AND TABLE_SCHEMA='test'
ORDER BY ORDINAL_POSITION;
Hey guys im trying to pass some data from an (oracle) fetch_array to a variable array and then use that array data to check if the data exists on a mysql db and create any rows that dont currently exist.. this is what i have so far.
the problem is its only checks/creates 1 entry of the array and doesn't check/created the entire array data. i think i would need to use a for loop to process all the array data concurrently
<?php
$conn = oci_connect('asdsdfsf');
$req_number = array();
if (!$conn) {
$e = oci_error();
trigger_error(htmlentities($e['message'], ENT_QUOTES), E_USER_ERROR);
}
$stid = oci_parse($conn, " SELECT WR.REQST_NO
FROM DEE_PRD.WORK_REQST WR
WHERE WR.WORK_REQST_STATUS_CD = 'PLAN' AND WR.DEPT_CD ='ISNG'
");
oci_execute($stid);
while (($row = oci_fetch_array($stid, OCI_BOTH+OCI_RETURN_NULLS)) != false) {
// Use the uppercase column names for the associative array indices
$req_number[]= $row['REQST_NO'];
}
oci_free_statement($stid);
oci_close($conn);
//MYSQL
//Connection Variables
//connect to MYSQL
$con = mysqli_connect($servername,$username,$password,$dbname);
if (!$con)
{
die('Could not connect: ' . mysqli_error());
}
// lets check if this site already exists in DB
$result = mysqli_query($con,"
SELECT EXISTS(SELECT 1 FROM wr_info WHERE REQST_NO = '$req_number') AS mycheck;
");
while($row = mysqli_fetch_array($result))
{
if ($row['mycheck'] == "0") // IF site doesnt exists lets add it to the MYSQL DB
{
$sql = "INSERT INTO wr_info (REQST_NO)VALUES ('$req_number[0]')";
if (mysqli_query($con, $sql)) {
$created = $req_number." Site Created Successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($con);
}
}else{ // if site is there lets get some variables if they are present...
$result = mysqli_query($con,"
SELECT *
FROM wr_info
WHERE REQST_NO = '$req_number[0]'
");
while($row = mysqli_fetch_array($result))
{
$do some stuff
}
}
}
mysqli_close($con);
?>
You create an array:
$req_number = array();
And loop over records to assign values to the array:
while (($row = oci_fetch_array($stid, OCI_BOTH+OCI_RETURN_NULLS)) != false) {
$req_number[]= $row['REQST_NO'];
}
But then never loop over that array. Instead, you're only referencing the first record in the array:
$sql = "INSERT INTO wr_info (REQST_NO)VALUES ('$req_number[0]')";
// etc.
(Note: There are a couple of places where you directly reference the array itself ($req_number) instead of the element in the array ($req_number[0]), which is likely an error. You'll want to correct those. Also: You should be using query parameters and prepared statements. Getting used to building SQL code from concatenating values like that is a SQL injection vulnerability waiting to happen.)
Instead of just referencing the first value in the array, loop over the array. Something like this:
for($i = 0; $i < count($req_number); $i++) {
// The code which uses $req_number, but
// referencing each value: $req_number[$i]
}
I have a fairly basic script (i'm used to mysql but i'm moving to mysqli)
<?php
include("../includes/functions.php");
/////////////////////////////////////////////////////////////////////////
$debugMode = 1;
/////////////////////////////////////////////////////////////////////////
if (isset($_GET['u']))
{
// database connection
$c = mysqli_connect("localhost", "xxx", "xxx", "xxx");
// initial query to check if the domain is already in the database
$q = $c->query("SELECT * FROM `domains` WHERE `domain_name`='".trim($s[0])."'");
$v = $q->fetch_assoc();
$r = $q->num_rows;
// check if the string exists in the database
if ($r > 0)
{
// do not enter if greater than 0
} else {
// vars
$u = $_GET['u'];
// DEBUG
if ($debugMode)
{
$fp = fopen('u.txt', 'a');
fwrite($fp, "$u" . "\n");
fclose($fp);
}
// do a split of "|"
$s = explode("|", $u);
// check alexa rank and update
$alexa = alexa_rank($s[0]);
// check connection
if (mysqli_connect_errno())
{
echo mysqli_connect_error();
} else {
// insert query if there is no errors
$i = $c->query("INSERT INTO `domains` (`domain_id`,`domain_name`,`domain_pr`,`domain_alexa_rank`,`domain_moz_da`,`domain_moz_pa`,`domain_date`) VALUES ('','".$s[0]."','".$s[1]."','".$alexa."','".$s[2]."','".$s[3]."',NOW())");
}
}
} else {
header("Location: http://www.site.info/");
}
?>
It looks fairly simple, the problem is the count part isn't working, it's still adding to the database duplicate entries, i also tried:
mysqli_num_rows($q);
This still doesn't seem to work, am i missing something simple?
thanks guys
You should first be sure your query is right.
So please debug your code like that;
$SQL = "SELECT * FROM `domains` WHERE domain_name`='".trim($s[0])."'";
echo "My Query: ". $SQL;
$q = $c->query($SQL);
I guess you have problem on your $s variable. If your sql query is right you can check $v variable have any record if $v variable is an array and have value you have more than one record and you can pass to insert statements if not you can add.
ahh thank you! i found my top query was failing because i was using the explode further down the code! thanks guys.
I have a Microsoft Access Database, and I am trying to query the table using PHP, and output valid JSON. I have an equivalent code for a MSSQL database, am I am trying to make my code do the same thing, but just for the Access database.
Here is the MSSQL code
$myServer = "server";
$myDB = "db";
$conn = sqlsrv_connect ($myServer, array('Database'=>$myDB));
$sql = "SELECT *
FROM db.dbo.table";
$data = sqlsrv_query ($conn, $sql);
$result = array();
do {
while ($row = sqlsrv_fetch_array ($data, SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
} while (sqlsrv_next_result($data));
$json = json_encode ($result);
sqlsrv_free_stmt ($data);
sqlsrv_close ($conn);
Here is what I tried for the MDB file
$dbName = "/filename.mdb";
if (!file_exists($dbName)) {
die("Could not find database file.");
}
$db = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", $user, $password);
$sql = "SELECT *
FROM cemetery";
$data = $db->query($sql); // I'm getting an error here
$result = array();
// Not sure what do do for this part...
do {
while ($row = fetch($data, SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
} while (sqlsrv_next_result($data));
$json = json_encode ($result);
I kind of followed this to try to connect to the database: http://phpmaster.com/using-an-access-database-with-php/
Currently this is giving me a 500 Internal Server Error. I'm expecting a string such as this to be saved in the variable $json
[
{
"col1":"col value",
"col2":"col value",
"col3":"col value",
},
{
"col1":"col value",
"col2":"col value",
"col3":"col value",
},
{
etc...
}
]
Can someone help me port the MSSQL code I have above so I can use it with an MDB database? Thanks for the help!
EDIT: I'm commenting out the lines one by one, and it throws me the 500 error at the line $data = $db->query($sql);. I looked in the error log, and I'm getting the error Call to a member function query() on a non-object. I already have the line extension=php_pdo_odbc.dll uncommented in my php.ini file. Anyone know what the problem could be?
You only need 1 loop,
fetchAll is your iterable friend:
while ($row = $data->fetchAll(SQLSRV_FETCH_ASSOC)) {
$result[] = $row;
}
odbc_connect doesn't return an object, it returns a resource. see (http://php.net/manual/en/function.odbc-connect.php) so you would need to do something like this.
$db = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", $user, $password);
$oexec = obdc_exec($db,$sql);
$result[] = odbc_fetch_array($oexec);
and then you can iterate over results..
see also:
http://www.php.net/manual/en/function.odbc-fetch-array.php
http://www.php.net/manual/en/function.odbc-exec.php
I finally figured it out.
<?php
// Location of database. For some reason I could only get it to work in
// the same location as the site. It's probably an easy fix though
$dbName = "dbName.mdb";
$tName = "table";
// Throws an error if the database cannot be found
if (!file_exists($dbName)) {
die("Could not find database file.");
}
// Connects to the database
// Assumes there is no username or password
$conn = odbc_connect("Driver={Microsoft Access Driver (*.mdb)};Dbq=$dbName", '', '');
// This is the query
// You have to have each column you select in the format tableName.[ColumnName]
$sql = "SELECT $tName.[ColumnOne], $tName.[ColumnTwo], etc...
FROM $dbName.$tName";
// Runs the query above in the table
$rs = odbc_exec($conn, $sql);
// This message is displayed if the query has an error in it
if (!$rs) {
exit("There is an error in the SQL!");
}
$data = array();
$i = 0;
// Grabs all the rows, saves it in $data
while( $row = odbc_fetch_array($rs) ) {
$data[$i] = $row;
$i++;
}
odbc_close($conn); // Closes the connection
$json = json_encode($data); // Generates the JSON, saves it in a variable
?>
I use this code to get results from an ODBC query into a JSON array:
$response = null;
$conn = null;
try {
$odbc_name = 'myODBC'; //<-ODBC connectyion name as is in the Windows "Data Sources (ODBC) administrator"
$sql_query = "SELECT * FROM table;";
$conn = odbc_connect($odbc_name, 'user', 'pass');
$result = odbc_exec($conn, $sql_query);
//this will show all results:
//echo odbc_result_all($result);
//this will fetch row by row and allows to change column name, format, etc:
while( $row = odbc_fetch_array($result) ) {
$json['cod_sistema'] = $row['cod_sistema'];
$json['sistema'] = $row['sistema'];
$json['cod_subsistema'] = $row['cod_subsistema'];
$json['sub_sistema'] = $row['sub_sistema'];
$json['cod_funcion'] = $row['cod_funcion'];
$json['funcion'] = $row['funcion'];
$json['func_desc_abrev'] = $row['desc_abreviada'];
$json['cod_tipo_funcion'] = $row['cod_tipo_funcion'];
$response[] = array('funcionalidad' => $json);
}
odbc_free_result($result); //<- Release used resources
} catch (Exception $e) {
$response = array('resultado' => 'err', 'detalle' => $e->getMessage());
echo 'ERROR: ', $e->getMessage(), "\n";
}
odbc_close($conn);
return $response;
And finnally encoding the response in JSON format:
echo json_encode($response);
I'm learning PHP and I'm well versed with Java and C. I was given a practice assignment to create a shopping project. I need to pull out the products from my database. I'm using the product id to do this. I thought of using for loop but I can't access the prod_id from the database as a condition to check! Can anybody help me?! I have done all the form handling but I need to output the products. This is the for-loop I am using. Please let me know if I have to add any more info. Thanks in advance :)
for($i=1; $i + 1 < prod_id; $i++)
{
$query = "SELECT * FROM products where prod_id=$i";
}
I would suggest that you use PDO. This method will secure all your SQLand will keep all your connections closed and intact.
Here is an example
EXAMPLE.
This is your dbc class (dbc.php)
<?php
class dbc {
public $dbserver = 'server';
public $dbusername = 'user';
public $dbpassword = 'pass';
public $dbname = 'db';
function openDb() {
try {
$db = new PDO('mysql:host=' . $this->dbserver . ';dbname=' . $this->dbname . ';charset=utf8', '' . $this->dbusername . '', '' . $this->dbpassword . '');
} catch (PDOException $e) {
die("error, please try again");
}
return $db;
}
function getproduct($id) {
//prepared query to prevent SQL injections
$query = "SELECT * FROM products where prod_id=?";
$stmt = $this->openDb()->prepare($query);
$stmt->bindValue(1, $id, PDO::PARAM_INT);
$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
return $rows;
}
?>
your PHP page:
<?php
require "dbc.php";
for($i=1; $i+1<prod_id; $i++)
{
$getList = $db->getproduct($i);
//for each loop will be useful Only if there are more than one records (FYI)
foreach ($getList as $key=> $row) {
echo $row['columnName'] .' key: '. $key;
}
}
First of all, you should use database access drivers to connect to your database.
Your query should not be passed to cycle. It is very rare situation, when such approach is needed. Better to use WHERE condition clause properly.
To get all rows from products table you may just ommit WHERE clause. Consider reading of manual at http://dev.mysql.com/doc.
The statement selects all rows if there is no WHERE clause.
Following example is for MySQLi driver.
// connection to MySQL:
// replace host, login, password, database with real values.
$dbms = mysqli_connect('host', 'login', 'password', 'database');
// if not connected then exit:
if($dbms->connect_errno)exit($dbms->connect_error);
$sql = "SELECT * FROM products";
// executing query:
$result = $dbms->query($sql);
// if query failed then exit:
if($dbms->errno)exit($dbms->error);
// for each result row as $product:
while($product = $row->fetch_assoc()){
// output:
var_dump($product); // replace it with requied template
}
// free result memory:
$result->free();
// close dbms connection:
$dbms->close();
for($i=1;$i+1<prod_id;$i++) {
$query = "SELECT * FROM products where prod_id=$i";
$result = mysqli_query($query, $con);
$con is the Database connection details
you can use wile loop to loop thru each rows
while ($row = mysqli_fetch_array($result))
{
......
}
}
Hope this might work as per your need..
for($i=1; $i+1<prod_id; $i++) {
$query = "SELECT * FROM products where prod_id = $i";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
print_r($row);
}
}
I think you want all records from your table, if this is the requirement you can easily do it
$query = mysql_query("SELECT * FROM products"); // where condition is optional
while($row=mysql_fetch_array($query)){
print_r($row);
echo '<br>';
}
This will print an associative array for each row, you can access each field like
echo $row['prod_id'];