MYSQL double table search with variables in query - php

Hi i want to acheive the following results for the purpose of a search script in php
i have 2 tables like this
Table 1 :
-----------------------------
id l name l url l image url l
-------------------------------
Table 2 :
-----------------------------------
id l tableoneid l desc l content l
------------------------------------
Note : (Table 1 --> id) = (Table 2 ---> tableoneid)
what i want to acheive is to get a MYSQL query that search :
Step 1 : The table 2 column [content] when i get the result i need
their [tableoneid] values,
Step 2 : Next i want to use that in order to search the Table 1 column 1
Step 3 : The final results would be the corresponding [image url] column of the Step 2 results
how can i acheive that with php/mysql
thank you very much !

Something like this:
SELECT * FROM <Table 1>
WHERE id IN (
SELECT DISTINCT(tableoneid) FROM <Table 2>
)
Change <Table 1> and <Table 2> with your actual table names.

This is one of the primary uses of JOINs.
SELECT t1.`image url`
FROM `Table 2` AS t2
INNER JOIN `Table 1` AS t1 ON t2.tableoneid = t1.id
WHERE [some condition involving t1.content]
;
I would strongly suggest not having any sort of non-alpha characters (other than _ in your table and field names.)

$query = "select
t1.`image url`
from
`Table 1` as t1
join
`Table 2` as t2 on t1.id = t2.tableoneid
where
t2.content = :table2ContentSearch";
$statement = $dbh->prepare($query);
$searchItem = "what you are searching for";
$statement->bindParam(':table2ContentSearch', $searchItem);
if($statement->execute()){
while($row = $statement->fetch()){
print_r($row);
}
}
you should also read up on sql joins. https://en.wikipedia.org/wiki/Join_%28SQL%29.

Related

How to retrieve data with 3 tables in mysql?

I am having 2 tables :
1.internal_employee_master
id employee_name unique_id
1 Noah ABCD
2 Liam ABCD
3 William ABCD
4 Benjamin ABCD
5 Jacob EFGH
2.external_employee_master
id name unique_id
1 Elijah ABCD
2 Ethan ABCD
3 Alexander EFGH
I am using UNION query to get both tables data into single table and display this data into html table.
select id
, employee_name
, unique_id
from internal_employee_master
where unique_id = 'ABCD'
union
select id
, employee_name
, unique_id
from external_employee_master
where unique_id = 'ABCD'
I want to store payslips of both employees into single table.
I have one table payslips with emp_id and emp_type columns.
I am storing data into payslips data like:
id pay_slip emp_id emp_type
1 Noah_payslip.pdf 1 internal
2 Liam_payslip.pdf 2 internal
3 Lia_payslip.pdf 1 External
as you can see in above table i am storing emp_id and emp_type of
both the tables in single columns each.
Now, i dont undestand how to split data of internal employee and
external employee from pay_slip table and show data in html table.
Currently, i am writing below sql joins to get employee_names of
internal and external employee tables but it doesnt work for me.
$id = $_GET['id];
SELECT ps.id,ps.pdf,ps.emp_id,ps.emp_type,external_employee.name as comemp,
internal_employee.comp_empl_name as comemp
FROM pay_slip as ps
INNER JOIN internal_employee_master as internal_employee ON internal_employee.comp_trad_id = ps.trade_id
INNER JOIN external_employee_master as external_employee ON external_employee.trad_id = ps.trade_id
where ps.is_deleted = 1 AND ps.id = '".$id."'"
Please help me to join query to get name and employee_name with respect to emp_type form pay_slip table.
How about using UNION again?
SELECT
ps.id,
ps.pdf,
ps.emp_id,
ps.emp_type,
external_employee.name AS comemp,
internal_employee.comp_empl_name AS comemp
FROM
pay_slip AS ps
INNER JOIN
internal_employee_master AS internal_employee ON internal_employee.comp_trad_id = ps.trade_id
WHERE
ps.is_deleted = 1 AND ps.id = '".$id."'
AND ps.type = 'internal'
UNION ALL
SELECT
ps.id,
ps.pdf,
ps.emp_id,
ps.emp_type,
external_employee.name AS comemp,
internal_employee.comp_empl_name AS comemp
FROM
pay_slip AS ps
INNER JOIN
external_employee_master AS external_employee ON external_employee.trad_id = ps.trade_id
WHERE
ps.is_deleted = 1 AND ps.id = '".$id."'
AND ps.type = 'external'
You could try this
SELECT ps.id, ps.pay_slip, ps.emp_type, COALESCE(i.employee_name, e.name) AS name
FROM payslips ps
LEFT JOIN internal_employee_master i ON i.id = ps.emp_id AND ps.emp_type = 'internal'
LEFT JOIN external_employee_master e ON e.id = ps.emp_id AND ps.emp_type = 'External'
AND ps.id = :ID
You can see this in action here http://sqlfiddle.com/#!9/53a195/7/0
I would mention that there are a number of issues in your included tables and queries. For example, irregular column names between tables (name vs. employee_name), you've missed the is_deleted column from your example schema, and you have capitalised and non-capitalised values in the emp_type column which is confusing.

Select distinct column from table

I have the database structure as shown in the below image:
I want to retrieve variant_id that belongs to particular product_id
Example :
lets say 1 and Size = L , Color = Green.
I expect mysql query to return variant_id = 7.
What is the expected query to be used in this scenario?
You can use following query.
I'm assuming your table name is table1
select variant_id from (select * from table1 where
product_id=1 and ((attribute_name='Size' and value='L')
or (attribute_name='Color' and value='Green'))) as temp
group by variant_id having count(*)>1

get all rows having common parents

id parent_id child_id
1 1 1
2 2 2
3 2 2
4 1 1
I have a table from which i need to get the common values from data when i query it with id... for eg if id=2 and id=3 then return
id parent_id
2 2
3 2
i have tried this after hunting a lot through various examples :
SELECT ta.user_id,ta.interest_parent_id,ta.interest_child_id
FROM user_interest ta
WHERE ta.user_id=2 AND
(SELECT COUNT(*) FROM user_interest tb
WHERE ta.interest_parent_id=tb.interest_parent_id
AND tb.user_id=3 )>1
but it responds with only:
id parent_id
2 2
any help :( im using a mysql database with php/codeigniter to do the scripting
You can give it a try:
SELECT
tOne.id,
tOne.parent_id
FROM
(
SELECT
*
FROM user_interest A
WHERE A.id IN (2,3)
) tOne
INNER JOIN
(
SELECT
*
FROM user_interest A
WHERE A.id IN (2,3)
) tTwo
ON tOne.parent_id = tTwo.parent_id
AND tOne.id <> tTwo.id
ORDER BY tOne.parent_id;
SQL FIDDLE DEMO
Any suggestion towards optimization of the query is welcome.
EDIT: SQL FIDDLE
You can make a sub SELECT:
SELECT * FROM table WHERE Name IN (SELECT Name FROM table GROUP BY Name HAVING count(*) > 1)

string split and subquery in mysql

first of all i have 1 table in database.
1)tags :
id name
1 theme1=test1
2 theme1=test2
3 theme1=test3
4 theme2=test1
5 theme2=test2
6 theme2=test3
And i have bunch of id of tags in array. like 1,3.
Now,
1)select name from tags where id=1
result: theme1=test1
(now using wildcard)
2)select id from tags where name like 'theme_test1'
result : 1,4
(here 'theme_test1' need to take from query1)
I am getting output proper but need to use 2 query.I want to do this in single query.
Thanks
SELECT id FROM tags WHERE name LIKE (
SELECT CONCAT(SUBSTRING(name,1,5),'__',SUBSTRING(name,8)) FROM tags WHERE id=1
)
Returns 1,4
But Two queries (or a refactor) might be a better option
If you whant to get the id with the same value you can try this:
SELECT t2.* FROM yourtable t1
JOIN youtable t2 on ON t2.name like concat(substr(t1.name,1,5), '%', substr(t1.name,8))
WHERE t1.id=1;
For performance better use this:
SELECT t.id
FROM r
INNER JOIN r AS t ON t.name LIKE CONCAT('theme_=test', SUBSTRING(r.name,-1))
WHERE r.id = '1'
r is your table in this case.
NOTE: this answer isn't valid in case that you have theme1=test1 and theme1=test10 values.
maybe you can use query :
select id from tags where name = (select name from tags where id = 1 ).
You can try that query.

trying to output the correct value from SQL query from comparing a different table

I'm very new with SQL and need assistance on how I can accomplish this task using the correct query.
I have 2 tables that I need to use. Table "TB1" has:
id Name
1 bob
2 blow
3 joe
table "TB2" has:
compid property
1 bob
2 blow
I am trying to get which compid is missing in "TB2" and insert it from "TB1"
the query I am doing is:
SELECT id, name from TB1, TB2 where id <> compid
what I get is 2 ouputs of Id 1, and 2, and 3 outputs from id 3. by using php:
for($i=0;$i <= mysql_num_rows($comp)-1; $i++)
{
echo mysql_result($comp, $i, 0)."<br>";
}
and I expected the ouput 3 but instead got this:
1
1
2
2
3
3
3
I understand its comparing all the rows within the table but is there a way to achieve what I am looking for?
Thanks for your time.
You are performing an implicit Cartesian JOIN which results in every row against every other row. You need to specify what attribute JOINs the two tables.
Using implicit syntax (not recommended):
SELECT id, name
FROM TB1, TB2
WHERE id <> compid
AND TB1.Name = TB2.property <-- Column join
Using explicit syntax:
SELECT id, name
FROM TB1
JOIN TB2
ON TB2.property = TB1.Name <-- Column join
WHERE id <> compid
To accomplish your goal you would need something along the lines of:
SELECT TB1.id, TB1.name
FROM TB1
LEFT JOIN TB2
ON TB2.property = TB1.Name
WHERE TB2.compid IS NULL
See it in action
It's best practice to always alias the columns you select to prevent ambiguity.
To select it you can do:
SELECT *
FROM TB1
WHERE id NOT IN (
SELECT compid
FROM TB2
);

Categories