Php PDO, Insert a changable varible - php

Question

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I've been looking into PDO, but it confuses me, i am only 14 and im not that knowledge about mysql in php all i know is to use PDO and some parts of databases, i was wondering how i would insert a changable value, such as balance, here is my information i want to insert into my table as rows
$conn->prepare("INSERT INTO users (64ID, BALANCE, AMOUNTBET) VALUES (?, ?, ?)");
$stmt->bind_param("sss", $64id, $balance, $amountbet );
// set parameters and execute
$_64id = "$steamprofile['steamid']";
$balance = "";
$amountbet = "";
$stmt->execute();
I Have connected to my mysql so all that is done, all i really need to know is how to insert rows? i know there is documentation about it but the topics on there differ to what i am trying to do?

Answer 1

Take from PHP documentation http://php.net/manual/en/pdostatement.bindparam.php
<?php
/* Execute a prepared statement by binding PHP variables */
$calories = 150;
$colour = 'red';
$sth = $dbh->prepare('SELECT name, colour, calories
FROM fruit
WHERE calories < :calories AND colour = :colour');
$sth->bindParam(':calories', $calories, PDO::PARAM_INT);
$sth->bindParam(':colour', $colour, PDO::PARAM_STR, 12);
$sth->execute();
?>
so your code will be:
$stmt = $conn->prepare("INSERT INTO users (64ID, BALANCE, AMOUNTBET) VALUES (:_64id, :balance, :amountbet)");
$_64id = $steamprofile['steamid'];
$balance = "";
$amountbet = "";
$stmt->bind_param(:_64id, $_64id);
$stmt->bind_param(:balance, $balance);
$stmt->bind_param(:amountbet, $amountbet);
$stmt->execute();