Array to string conversion in - php

Question

Somebody solve my problem. Update query not work.
Error in Update query this step... Array to string conversion $query .= "image = '{$image}' "; ------------------------------------------------------------------------------------------------------------------------------------
if (isset($_POST['submit'])) {
$file = rand(1000,100000)."-".$_FILES['image']['name'];
$file_loc = $_FILES['image']['tmp_name'];
$folder="uploads/";
$new_file_name = strtolower($file);
$image =str_replace(' ','-',$new_file_name);
move_uploaded_file($file_loc,$folder.$image);
$firstname = $_POST["firstname"];
$lastname = $_POST["lastname"];
$address1 = $_POST["address1"];
$address2 = $_POST["address2"];
$city = $_POST["city"];
$state = $_POST["state"];
$zipcode = $_POST["zipcode"];
$email = $_POST["email"];
$country = $_POST["country"];
$phone = $_POST["phone"];
$image = $_FILES["image"];
$username = $_POST["username"];
$passwordold = $_POST["oldpassword"];
$passwordone = $_POST["passwordone"];
$passwordtwo = $_POST["passwordtwo"];
$sessions = $_SESSION['admin_id'];
$query = "UPDATE user SET ";
$query .= "firstname = '{$firstname}', ";
$query .= "lastname = '{$lastname}', ";
$query .= "addressone = '{$address1}', ";
$query .= "addresstwo = '{$address2}', ";
$query .= "city = '{$city}', ";
$query .= "state = '{$state}', ";
$query .= "zipcode = '{$zipcode}', ";
$query .= "email = '{$email}', ";
$query .= "country = '{$country}', ";
$query .= "phone = '{$phone}', ";
$query .= "image = {$image} ";
$query .= "WHERE id = {$sessions} ";
$query .= "LIMIT 1";
$result = mysqli_query($connection, $query);
echo "<pre>";
print_r($_FILES);
print_r($_POST);
echo "</pre>";
}

Answer 1

$_FILES["image"] is an array. You can only pass string in sql queries. May be you need to serialize the array and then store it in the database.