sql search with 2 or more fields - php

Question

Created an sql search query with having multiple fields I created using if else condition it is working fine but if 1 and 2nd field is emty and 3rd field is not then it dies not work just because of OR keyword please advise how I would be able to correct this
<form method="POST" action="search.php?action=go">
<li>
<h3>Player</h3>
<input type="text" class="form-control" placeholder="Dylan Scout" name="playername" value="<?php if(isset($_POST["playername"])) {echo $_POST["playername"];} ?>">
</li>
<li>
<h3>Age</h3>
<input type="text" class="form-control" placeholder="25" name="age" value="<?php if(isset($_POST["age"])) {echo $_POST["age"];} ?>">
</li>
<li>
<h3>Country</h3>
<input type="text" class="form-control" placeholder="Wallabies" name="country" value="<?php if(isset($_POST["country"])) {echo $_POST["country"];} ?>">
</li>
<li>
<h3>Club</h3>
<input type="text" class="form-control" placeholder="Eagle" name="club" value="<?php if(isset($_POST["club"])) {echo $_POST["club"];} ?>">
</li>
<li>
<button type="submit" name="search">Search</button>
</li>
</form>
And here is my sql php query
<?php
if(isset($_GET["action"]) == 'go') {
$stmt = "SELECT * FROM users WHERE";
if($_POST["playername"]) {
$stmt .= " OR fname LIKE '%".$_POST["playername"]."%' OR lname LIKE '%".$_POST["playername"]."%'";
}
if($_POST["age"]) {
$stmt .= " OR age LIKE '%".$_POST["age"]."%' ";
}
if($_POST["country"]) {
$stmt .= " OR country LIKE '%".$_POST["country"]."%' ";
}
if($_POST["club"]) {
$stmt .= " OR club LIKE '%".$_POST["club"]."%' ";
}
} else {
$stmt = "SELECT * FROM users ";
}
echo $stmt . "<br />";
$sql = mysqli_query($connection, $stmt);
?>
Please let me know how would I be able to make it work properly as if i write on 3rd fields and leave other fields empty then it will become asWHERE OR which will become obviously wrong query and won't work
Thank You

Answer 1

The function implode will help you.
Add them into an array and connect them after.
<?php
$array = array();
if (isset($_POST["playername"]))
$array[] = "fname LIKE '%".$_POST["playername"]."%' OR lname LIKE '%".$_POST["playername"]."%";
if (isset($_POST["age"]))
...
$stmt = "SELECT * FROM users";
if (count($array) > 0)
$stmt .= " WHERE " . implode(" OR ",$array);
$sql = mysqli_query($connection, $stmt);
?>

Answer 2

Try this. Using implode() you can achieve this.
<?php
if(isset($_GET["action"]) == 'go') {
$where = array();
if($_POST["playername"]) {
$where[] = " OR fname LIKE '%".$_POST["playername"]."%' OR lname LIKE '%".$_POST["playername"]."%'";
}
if($_POST["age"]) {
$where[] = " OR age LIKE '%".$_POST["age"]."%' ";
}
if($_POST["country"]) {
$where[] = " OR country LIKE '%".$_POST["country"]."%' ";
}
if($_POST["club"]) {
$where[] = " OR club LIKE '%".$_POST["club"]."%' ";
}
if(!empty($where))
{
$stmt = "SELECT * FROM users WHERE " . implode(" AND ", $where) ." ";
}
else
{
$stmt = "SELECT * FROM users ";
}
} else {
$stmt = "SELECT * FROM users ";
}
echo $stmt . "<br />";
$sql = mysqli_query($connection, $stmt);
?>

Answer 3

add where condition to an array, and next use implode function, for example:
<?php
if(isset($_GET["action"]) == 'go') {
$stmt = "SELECT * FROM users";
if($_POST["playername"]) {
$where[] = "fname LIKE '%".$_POST["playername"]."%' OR lname LIKE '%".$_POST["playername"]."%'";
}
if($_POST["age"]) {
$where[] = "age LIKE '%".$_POST["age"]."%' ";
}
if($_POST["country"]) {
$where[] = "country LIKE '%".$_POST["country"]."%' ";
}
if($_POST["club"]) {
$where[] = "club LIKE '%".$_POST["club"]."%' ";
}
if(count($where))
$stmt .= " WHERE " . implode(" OR ", $where);
echo $stmt . "<br />";
$sql = mysqli_query($connection, $stmt);
?>