try .. catch with system() command php on laravel 5.0 - php

Question

I've a code for command app made on laravel 5.0 with try .. catch and use system command. When there a exception, my catch not work.
use Illuminate\Support\Facades\Log;
...
try {
system('.dump master | sqlite3 ' . $older . ' > ' . storage_path() . '/tmp/' . $tabla . '.sql' );
} catch ( \Exception $e) {
Log::alert('Problem import old table '. $tabla . $e->GetMessage());
}
I see my error on shell but not write on my own laravel log. (Log:alert)

Answer 1

You have to gain access over STDERR and, probably, STDOUT. Use proc_open, e.g.:
$desc = [
1 => ['pipe', 'w'], // STDOUT
2 => ['pipe', 'w'], // STDERR
];
$proc = proc_open('ls -l . something', $desc, $pipes);
if (is_resource($proc)) {
if ($out = stream_get_contents($pipes[1])) {
echo $out;
}
fclose($pipes[1]);
if ($err = stream_get_contents($pipes[2])) {
fprintf(STDERR, "Error: %s\n", $err);
}
fclose($pipes[2]);
// You can also check the process exit status
// 0 means success, otherwise error.
$exit_status = proc_close($proc);
}
Of course, there is no need in STDOUT pipe, if the command redirects it to a file.
And yes, system() won't throw exceptions. Obviously, you can implement your own class which will throw an exception in case if the process exit status is non-zero, or there is something caught in the STDERR pipe:
class MyShellException extends \Exception {}
class MyShell {
public static function execute($command, &$out = null) {
if (func_num_args() > 1) {
$desc[1] = ['pipe', 'w'];
} else {
$desc[1] = ['file', '/dev/null'];
}
$desc[2] = ['pipe', 'w'];
$proc = proc_open($command, $desc, $pipes);
if (is_resource($proc)) {
if (isset($pipes[1])) {
$out = stream_get_contents($pipes[1]);
fclose($pipes[1]);
}
if ($err = stream_get_contents($pipes[2])) {
fclose($pipes[2]);
throw new MyShellException("Command $command failed: $err");
}
if ($exit_status = proc_close($proc)) {
throw new MyShellException("Command $command exited with non-zero status");
}
}
}
}
try {
MyShell::execute('ls -l . something', $out);
echo "Output: $out\n";
} catch (MyShellException $e) {
if (!empty($out)) {
echo "Output: $out\n";
}
fprintf(STDERR, "MyShell error: " . $e->getMessage());
exit(1);
}

Answer 2

Use Throw Exception in php.
Here is the reference link to use and a sample example:
<?php
/*
*
* opcode number: 108
*/
try {
$error = 'Always throw this error';
throw new Exception($error);
// Code following an exception is not executed.
echo 'Never executed';
} catch (Exception $e) {
echo 'Caught exception: ', $e->getMessage(), "\n";
}
// Continue execution
echo 'Hello World';
?>