I'm trying to configure my database data that is being pulled with php to look like my homepage.
I can't figure out what I need to do.
This is for a project for school, and I have very limited knowledge on php.
Here is my php script.
<?php
include('mysql_connect.php');
$dbh = con();
foreach($dbh->query("SELECT * FROM `Product` WHERE `ProductType` = 'memory' ",PDO::FETCH_ASSOC) as $row){
$Pname = $row['ProductName'];
$description = $row['description'];
$price = $row['ProductPrice'];
$ID = $row['ProductID'];
echo <div class="row">;
echo <div class="col-sm-4 col-lg-4 col-md-4">;
echo <div class="thumbnail">;
<img src="/var/www/html/Pictures/gigb75m_home.jpg" alt="">
echo "<div class="caption">";
echo "<h4 class="pull-right">$price</h4>";
echo "<h4>$Pname</h4>";
echo "<p>$description</p>";
echo "<p>$ID</p>";
}
?>
</div>
</div>
</div>
Here is my index that has my desired results.
<div class="row">
<div class="col-sm-4 col-lg-4 col-md-4">
<div class="thumbnail">
<img src="/var/www/html/Pictures/gigb75m_home.jpg" alt="">
<div class="caption">
<h4 class="pull-right">$74.99</h4>
<h4>GIGABYTE GA-B75M
</h4>
<p>Micro ATX, LGA 1155, Intel B75 Express Chipset, 2200MHz DDR3 (O.C.), SATA III (6Gb/s), 7.1-CH Audio, Gigabit LAN, USB 3.0 - GA-B75M-D3H</p>
</div>
</div>
</div>
Picture of homepage: http://imgur.com/g72Wrxk
Any help/guidance is greatly appreciated, this is driving me crazy.
Use '.' for string concatinations.
For example:
echo '<h4 class="pull-right">' . $price . '</h4>';
You have to use single quote to echo content in your PHP script like this for instead :
echo '<div class="row">';
The single quotes are used to explain that it's a string to show. You have to do the same for your other echo part.
Or you can escape the HTML part from the PHP and replace by vars inside it like this :
<?php
include('mysql_connect.php');
$dbh = con();
echo '<div class="row">';
foreach($dbh->query("SELECT * FROM `Product` WHERE `ProductType` = 'memory' ",PDO::FETCH_ASSOC) as $row){
$Pname = $row['ProductName'];
$description = $row['description'];
$price = $row['ProductPrice'];
$ID = $row['ProductID'];
?>
<div class="col-sm-4 col-lg-4 col-md-4">
<div class="thumbnail">
<img src="/var/www/html/Pictures/gigb75m_home.jpg" alt="">
<div class="caption">
<h4 class="pull-right"><?php echo $price; ?></h4>
<h4><?php echo $Pname; ?></h4>
<p>$description</p>
<p>$ID</p>
</div>
</div>
</div>
<?php
}
?>
</div>
Also you have to be careful about the row system of bootstrap to echo col-md-4 inside a row, you can add 3 items like this per row. So you have to close and reopen a row each time you fetch 3 elements to get a correct HTML structure.
You didn't supplied any information about your database, yet the first problem that's visible is your echo's
To output HTML through PHP you have to output pure strings.
An example for that would be ""
In PHP when you want to connect different kinds of inputs like variables and "" or '' etc you connect them with a dot.
For example:
$string = ' hello3';
echo "Hello 1 ".' hello2 '.$string;
The outcome will be:
Hello 1 hello2 hello3
I hope you got it the hang of it.
Related
This is some Bootstrap HTML where I need to create multiple blocks like a table but it just grabs the first item in the DB and prints 50 of them. I'm having trouble figuring out how to mingle the php code and html code so it works correctly.
<section id="latest-news" class="latest-news-section">
<div class="container">
<?php
include_once ('mysql.inc.php');
$ix = $_POST['i'];
$sql = "SELECT * from deposits WHERE d_userid = '$ix' ORDER BY _productionid ASC";
$query = #mysql_query($sql);
$outcome = #mysql_fetch_array($query);
foreach ($outcome as $result1){
?>
This part comes out nicely formatted, but the only data is the first item in the DB, and there are 50 copies made
<div class="col-md-4 col-sm-4">
<div class="latest-post">
<img src="assets/images/<?php echo $outcome['d_picture'] ?>" class="img-responsive" alt="">
<h4>Your ST1 <?php echo $outcome['d_firstname'] ?></h4>
<p>Prod ID <?php echo $outcome['d_productionid'] ?></p>
<p>Color: <?php echo $outcome['d_color'] ?><br />
Equip: <?php echo $outcome['d_equip'] ?><br />
Custom: <?php echo $outcome['d_custom'] ?></p>
<a class="btn btn-primary">View More</a>
</div>
</div>
<?
}
#mysql_close;
?>
</div>
</section>
You should use $result1 and not $outcome
ex: $result1['d_picture']
I need tips or direction on how can I display data from mysql using echo. But I want to display it in html code. I want to display $row["title"] of first title in mysql instead title1 and $row["content"] of first content in mysql instead content1 and do that for all 3 divs. php code works fine I just can't figure out how to make that possible.
<div class="carousel-inner" style="background-size:cover;">
<div class="item active">
<img src="img/road1.jpg">
<div class="carousel-caption d-none d-md-block">
<h2>title1</h2>
<p>content1</p>
</div>
</div>
<div class="item">
<img src="img/road2.jpg">
<div class="carousel-caption d-none d-md-block">
<h2>title2</h2>
<p>content2</p>
</div>
</div>
<div class="item">
<img src="img/road3.jpg">
<div class="carousel-caption d-none d-md-block">
<h2>title3</h2>
<p>content3</p>
</div>
</div>-->
<?php
session_start();
include_once("db.php");
$sql = "SELECT * FROM news";
$query = mysqli_query($conn, $sql);
if (mysqli_num_rows($query) > 0) {
while($row = mysqli_fetch_assoc($query)) {
echo "<h2>" . $row["title"] . "</h2>";
echo "<p>" . $row["content"] . "</p>";
}
} else {
echo "0 results";
}
?>
You're almost there. Just move the html into the echo of the while loop.
echo '<div class="carousel-inner" style="background-size:cover;">';
$counter = 1;
while($row = mysqli_fetch_assoc($query)) {
echo '
<div class="item ' . ($counter == 1 ? 'active' : '') . '">
<img src="img/road{$counter}.jpg">
<div class="carousel-caption d-none d-md-block">
<h2>' . $row["title"] . '</h2>
<p>' . $row["content"] . '</p>
</div>
</div>';
$counter++;
}
echo '</div>';
The only issue is the image, realistically you'd save the image in the database with the title and content then use the same method but for this simple case lets just use a counter
please note that I change your entire code a little bit to make the desired results...
<div class="carousel-inner" style="background-size:cover;">
<?php
session_start();
include_once("db.php");
$sql = "SELECT * FROM news";
$query = mysqli_query($conn, $sql);
if (mysqli_num_rows($query) > 0) {
while($row = mysqli_fetch_assoc($query)) { ?>
<div class="item active">
<img src="img/road1.jpg">
<div class="carousel-caption d-none d-md-block">
<h2><?php echo $row["title"]; ?></h2>
<p><?php echo $row["content"]; ?></p>
</div>
</div>
<?php
}
} else {
echo "0 results";
}
?>
Also note that I'm repeating just the first image... You need an extra on planning to determine how to handle images in code and then update this one.
I would like to create a new containing <div> after 3 results, using PDO result loop.
For my self-study-project I have to made a product page with bootstrap and after every 3rd record I have to make a new row and show again 3 col-md-4's, etc, etc.
Now I have this as my code:
<div class="row">
<?php
while ($row = $stmt->fetch(PDO::FETCH_OBJ)) {
?>
<div class="col-md-4">
<div class="product">
<div class="title"><?php echo $row->pname ?></div>
<div class="img"><img
src="../product/img/<?php echo $row->pnumber ?>/<?php echo $row->pthumbnail ?>.jpg?$pop210x210$"/>
</div>
<div class="vijftien"></div>
<div class="deliver">Levertijd: <strong><?php echo $row->pdelivertime ?></strong></div>
<div class="vijf"></div>
<div class="other"></div>
<div class="row">
<div class="col-md-6">
<div class="price"><?php echo $row->pprice ?></div>
</div>
<div class="col-md-6">
<div class="order">
<button class="log_in" id="doLogin">Meer informatie</button>
</div>
</div>
</div>
</div>
</div>
<?php } ?>
</div>
I have visited and studied other questions but I do not really get the idea of how they are doing it and how I can implement the correct method into my code.
As tadman stated in the comment under your question. The best approach should use a modulus operator (%) with 3.
Place your separating condition at the start of each iteration. (Demo)
Like this:
$x=0; // I prefer to increment starting from zero.
// This way I can use the same method inside a foreach loop on
// zero-indexed arrays, leveraging the keys, and omit the `++` line.
echo "<div class=\"row\">";
foreach($rows as $row){
if($x!=0 && $x%3==0){ // if not first iteration and iteration divided by 3 has no remainder...
echo "</div>\n<div class='row'>";
}
echo "<div>$row</div>";
++$x;
}
echo "</div>";
This will create:
<div class="row"><div>one</div><div>two</div><div>three</div></div>
<div class='row'><div>four</div><div>five</div><div>six</div></div>
Late Edit, here are a couple of other methods for similar situations which will provide the same result:
foreach(array_chunk($rows,3) as $a){
echo "<div class=\"row\"><div>",implode('</div><div>',$a),"</div></div>\n";
}
or
foreach ($rows as $i=>$v){
if($i%3==0){
if($i!=0){
echo "</div>\n";
}
echo "<div class=\"row\">";
}
echo "<div>$v</div>";
}
echo "</div>";
To clarify what NOT to do...
Sinan Ulker's answer will lead to an unwanted result depending on the size of your result array.
Here is a generalized example to expose the issue:
Using this input array to represent your pdo results:
$rows=["one","two","three","four","five","six"];
Sinan's condition at the end of each iteration:
$i=1;
echo "<div class=\"row\">";
foreach($rows as $row){
echo "<div>$row</div>";
if($i%3==0)echo "</div>\n<div class='row'>"; // 6%3==0 and that's not good here
// 6%3==0 and will echo the close/open line after the content to create an empty, unwanted dom element
$i++;
}
echo "</div>\n\n";
Will create this:
<div class="row"><div>one</div><div>two</div><div>three</div></div>
<div class='row'><div>four</div><div>five</div><div>six</div></div>
<div class='row'></div> //<--- this extra element is not good
You need to add a new closure tag and open new one every 3th iteration.
<div class="row">
<?php
$sql = "SELECT * FROM products";
$stmt = $conn->query($sql);
$stmt->execute();
$i=1;
while ($row = $stmt->fetch(PDO::FETCH_OBJ)) {
?>
<div class="col-md-4">
<div class="product">
<div class="title"><?php echo $row->pname ?></div>
<div class="img"><img
src="../product/img/<?php echo $row->pnumber ?>/<?php echo $row->pthumbnail ?>.jpg?$pop210x210$"/>
</div>
<div class="vijftien"></div>
<div class="deliver">Levertijd: <strong><?php echo $row->pdelivertime ?></strong>
</div>
<div class="vijf"></div>
<div class="other"></div>
<div class="row">
<div class="col-md-6">
<div class="price"><?php echo $row->pprice ?></div>
</div>
<div class="col-md-6">
<div class="order">
<button class="log_in" id="doLogin">Meer informatie</button>
</div>
</div>
</div>
</div>
</div>
<?php
if($i%3==0)echo "</div><div class='row'>";
$i++;
} ?>
$x = 0;
echo "";
foreach($rows as $row)
{
/* added one more condition for removing empty div.... */
if ($x != 0 && $x % 3 == 0 && $x < count($rows))
{
echo "</div>\n<div class='row'>";
}
echo "<div>$row</div>";
++$x;
}
echo "";
my code is not displaying the first result in the while loop.
my query is working right on phpmyadmin but somethings going wrong on index page.
I have the following code:
<?php
$test=mysql_query("SELECT * FROM newsites");
$deneme=mysql_fetch_row($test);
?>
<div class='container'>
<div class='row'>
<?php
while ($deneme=mysql_fetch_assoc($test)) {
extract($deneme);
echo '<div class="col-md-3 col-sm-6 col-xs-12 back-colour">';
echo '<td><img class="img-responsive" src="images/'.$deneme['site_pic'].'" width="120" height="20"/></td>';
echo '<p class="box-design">'.$deneme['site_name'].'</p>';
echo '<p class="box-design">'.$deneme['site_link'].'</p>';
echo '<p class="box-design">'.$deneme['site_ref'].'</p>';
echo '<p class="box-design">'.$deneme['site_type'].'</p>';
echo '</div>';
}
?>
</div>
</div>
It looks like the first row is already taken from the resultset outside the while loop.
On line 3 you have $deneme=mysql_fetch_row($test);
I'd say remove it and you're good to go.
I'm trying to generate dynamic contents fill from mysql db
here is my php code:
<?php
include 'header.php';
error_reporting(1);
$user = "root";
$pass = "";
$dbName = "haimi";
mysql_connect('localhost', $user, $pass) or
die("Could not connect: " . mysql_error());
mysql_select_db($dbName);
$sql = "SELECT * FROM Projects ";
$result = mysql_query($sql);
?>
<?php
while ($line = mysql_fetch_array($result)) {
?>
<li class="filter" data-filter=".cat<?php echo $line['Category'];?>"><?php echo $line['Category'];?></li>
<?php
}
?>
The li displays correctly, but the following does not:
<div class="row projects m0">
<?php
while ($line = mysql_fetch_array($result)) { ?>
<div class="project mix catHouses">
<div class="tint"></div>
<a href="images/projects/".<?php echo $line['ProjectImage1']; ?> data-
lightbox="project" data-title="Central Hospital (building)">
<img src="images/projects/".<?php echo
$line['ProjectImage1']; ?> alt="<?php echo $line['ProjectTitle'];?>"
class="projectImg"> </a>
<div class="projectDetails row m0">
<div class="fleft nameType">
<div class="row m0 projectName"><?php echo $line['ProjectTitle'];?></div>
<div class="row m0 projectType"><?php echo $line['ProjectType'];?></div>
</div>
<div class="fright projectIcons btn-group" role="group">
<a href="images/projects/<?php echo $line['ProjectImage1']; ?>" data-lightbox="project" data-title="Central Hospital (building)" class="btn btn-default">
<i class="fa fa-link"></i></a>
<i class="fa fa- search"></i>
</div>
</div>
</div>
<?php
}
?>
</div>
It data in the divs doesn't appear.
You're making a single call, but trying to loop through it twice. To do so, you need to reset the pointer back to the beginning:
//Add this after the first loop, but before the second
mysql_data_seek( $result, 0 );
The way you have it now, it's while($line = mysql_fetch_array($result)), but the second loop is never entered since it has already reached the end. Since the loop is ended, it never displays the contents.
Important Note
The mysql_* functions are deprecated, and is removed in PHP 5.5. You should use Mysqli or PDO. They have better protections against mysql injections (see Bobby Tables).
You have some HTML mistakes here:
<a href="images/projects/".<?php echo $line['ProjectImage1']; ?>
First, there is no need to use . operator (as you are in HTML, not PHP),
Also you shoud put your <?php ?> tag inside the href quotations, here is the correct code:
<a
href="images/projects/<?php echo $line['ProjectImage1']; ?>"
data-lightbox="project"
data-title="Central Hospital (building)"
>
<img
src="images/projects/<?php echo $line['ProjectImage1']; ?>"
alt="<?php echo $line['ProjectTitle']; ?>"
class="projectImg"
>
</a>
You will get older fast writing code like that ;)
How about this:
while ($line = mysql_fetch_array($result)) {
$category = $line['Category'];
echo <<< LOB
<li class="filter" data-filter="$category">$category</li>
LOB;
}
Like what Mr #matthew said
I was making a single call, and I was trying to loop through it twice.
The problem solved with this code before the while loop:
$result = mysql_query($sql);