How can I get the right row from the XP? - php

Question

I have a table in a MySQL database that has a list of levels (1-10) and has a XP_NEEDED column, I already have a number and I want to find the level from that number (the number is an XP), I know how to do this in the way below...
Example (Short):
if ($xpLookingFor >= 100 && $xpLookingFor < 200) // Checks if not high as level 2 {
return '1'; // Would be returning Level1
}
else if ($xpLookingFor >= 200 && $xpLookingFor < 300) // Checks if not high as level 3 {
return '2'; // Would be returning Level2
}
So it checks if its higher than the current level but not as high as the level aboves xp_needed, if its as high as the next level the next if statement will handle it.
But this way has a lot of code that could possibly be shortened, what is the best way to do this? is there a built in mysql feature for this?

Answer 1

Im not sure if this is what you need question is not too clear.
<?php
function getLevel($xp, $maxLevel) {
for($check = 1; $check < $maxLevel; $check++)
if ($xp >= ($check*100) AND $xp < ($check*100)+100) return $check;
return $maxLevel;
}
//Param #1 is the xp level and #2 is the max level
echo getLevel(503, 10); // returns 5
echo getLevel(123, 10); //returns 1
echo getLevel(1405, 20); //returns 14
echo getLevel(1405, 10); //returns 10
?>

Answer 2

Because you're using elseif, the first part of the if isn't needed, you could stack them something like this.
function getLevel($xpLookingFor){
if ($xpLookingFor < 100){
return 0;
}
else if ($xpLookingFor < 200){
return 1;
}
else if ($xpLookingFor < 300){
return 2;
}
else if ($xpLookingFor < 375){
return 3;
}
else if ($xpLookingFor < 400){
return 4;
}
else {
return 'MAX!';
}
}
See example on IdeOne