I am getting this string from CURL response
{status: 'false',description:'5400'}
I want to extract description parameter only.
I want $description = 5400 ;
How to do this ?
You have a bad json response, you have to change your json code and than using the following code you can access the variable.
<?php
$response = '{"status":false,"description":5400}';
$response_array = json_decode($response);
echo $response_array->description;
?>
And if you want to get the value of description with the existing bad json, you can do following thing.
<?php
$response = "{status:'false',description:'5400'}";
$r = explode("description:'", $response);
$description = rtrim($r[1],"'}");
echo $description;
?>
That response is json. Turn it into a PHP array:
$response = "{status: 'false',description:'5400'}";
$response_array = json_decode($response, true);
$description = $response_array['description'];
echo $description;
# Nirali Joshi
If Your JSON with space then it will be write solution
$response = "{status : 'false', description : '5400'}";
$response = str_replace(" ","",$response);
OR
$response = preg_replace('/\s+/', '', $response);
$t_repsonse = explode("description:", $response);
$i_description = str_replace("}","",str_replace("'","",$t_repsonse [ 1 ] ));
OR
$i_description = str_replace("}","",preg_replace('([ "\' ])', '', $t_repsonse [ 1 ]));
$description = $i_description;
Sorry and improve if any mistake founds and thanks
Related
How can I read a JSON data response using php?
This is Code :
$response = Unirest\Request::get("https://montanaflynn-spellcheck.p.mashape.com/check/?text=This+sentnce+has+some+probblems.",
array(
"X-Mashape-Key" => "MY X-Mashape-Key",
"Accept" => "application/json"
)
);
and give me this json data :
{
"original": "This sentnce has some probblems.",
"suggestion": "This sentence has some problems.",
and ...
}
I want to return "suggestion" in a url with $
this is an example :
$user_id = '123456789'
$mytext = '?' // I WANT RETURN "suggestion" HERE !
$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$mytext
file_get_contents($url);
You can use json_decode().
See:
http://php.net/manual/en/function.json-decode.php
You just need to do:
$response = json_decode($response,1);
echo $response['suggestion'];
Setting the second parameter of json_decode() to 1 (true) will return an associative array of the JSON data.
If you want to include it in a URL using your code example:
$user_id = '123456789'
$json = json_decode($response,1);
$mytext = $json['suggestion'];
$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$mytext
file_get_contents($url);
Use json_decode to convert json_response to array.Add second parameter of 'true' to make it an array that you should be familiar with.
Access suggestion variable by specifying it.
$response = Unirest\Request::get("https://montanaflynn-spellcheck.p.mashape.com/check/?text=This+sentnce+has+some+probblems.",
array(
"X-Mashape-Key" => "MY X-Mashape-Key",
"Accept" => "application/json"
)
);
$data=json_decode($response,true);
$url = 'https://api.telegram.org/mytoken/sendMessage?chat_id='.$user_id.'&text='.$data['suggestion'];
echo $url;
I'm trying to get video urls from dailymotion.
i got JSON results and its valid tested with online tools but when I use js_decode & print_r it shows warning like
<?php
$content = file_get_contents("http://www.dailymotion.com/embed/video/x49oyt5");
$content = explode(',"qualities":', $content);
$json = explode(',"reporting":', $content[1]);
$json = $json[0];
$mycontent = file_get_contents($json);
$response = json_decode($mycontent, true);
print_r($response);
?>
I want to get video quality and video url from JSON.
You're using file_get_contents on what is actually already a JSON.
updated code, tested ;)
<?php
$content = file_get_contents("http://www.dailymotion.com/embed/video/x49oyt5");
$content = explode(',"qualities":', $content);
$json = explode(',"reporting":', $content[1]);
$json = $json[0];
$videos = json_decode($json,true);
//Cycle through the 1080 videos and print the video urls
foreach($videos[1080] as $video){
printf("Video type:%s URL:%s\n", $video['type'], $video['url']);
}
//Cycle through the 720 videos and print the video urls
foreach($videos[720] as $video){
printf("Video type:%s URL:%s\n", $video['type'], $video['url']);
}
?>
With array_keys($array) you can get all the keys from array, it will return an array with the keys.
<?php
$content = file_get_contents("http://www.dailymotion.com/embed/video/x49oyt5");
$content = explode(',"qualities":', $content);
$json = explode(',"reporting":', $content[1]);
$json = $json[0];
$mycontent = file_get_contents($json);
$response = json_decode($mycontent, true);
$qualities = array_keys($response)
print_r($qualities);
?>
I am working in Symfony2 and I want to se the content of a Request with a JSON string and use i.e.: $request->get('name') to access the content.
JSON string:
$string = '{
"name":"Bob",
"surname":"White",
"email":"bobwhite#gmail.com",
"nationality":"",
}';
$request = new Request ($query = array(), $request = array(), $attributes = array(), $cookies = array(), $files = array(), $server = array(), $content = $string);
var_dump($request->get('name'));die;
To me the above is a valid way but the var dump gives me null... can anyone see where I m going wrong here...?
You want something like this?
use Symfony\Component\HttpFoundation\Request;
$input = '{
"name":"Bob",
"surname":"White",
"email":"bobwhite#gmail.com",
"nationality":""
}';
$data = json_decode($input, true);
$request = new Request (array(), $data);
var_dump($request->request->get('name'));
die;
I have probably spent all day trying to figure this out. I have read multiple questions here on stack and also have been reading articles and checking on documentation, but I can't seem to figure out why this batch of code just produces a null output. Am I missing brackets, calling something wrong, ect?
<?php
$url = "http://api.openweathermap.org/data/2.5/weather?id=4879890&units=imperial";
$str = file_get_contents($url);
$json = json_decode($str);
$temp = $json['main']['temp_min'];
$content = $temp;
$array = array(
"content" => $content,
refresh_requency => 30
);
echo json_encode($array);
?>
Again what I'm asking is can someone point out to me or tell me what I'm doing wrong. Is it my server that's just not handling the data correctly? That could be a possibility.
One other thing I've tried is to just print out $temp and/or the other variable like $str. When I do that though they don't even show up so that's what I think my problem is just not sure how to fix it.
Update
I've come to the conclusion that it's my web hosting service. As if I add var_dump($json) I get a null output null output.
Also to confirm that its my webhost if I run error_reporting(E_ALL); ini_set('display_errors', 1); it points to the file php.ini not allowing outgoing connections. I edited that same file on my local home server(raspberry pi) ran the same file and it works fine.
Below is the working solution for your above code:
<?php
$url = "http://api.openweathermap.org/data/2.5/weather?id=4879890&units=imperial";
$str = file_get_contents($url);
$json = json_decode($str, true);
$temp = $json['main']['temp_min'];
$content = $temp;
$array = array(
"content" => $content,
"refresh_requency" => 30
);
echo json_encode($array);
?>
When I executed your code, I found 2 problem into your code snippet:
1) You were trying to use object of type stdClass as array.
Solution:
<?php
$url = "http://api.openweathermap.org/data/2.5/weather?id=4879890&units=imperial";
$str = file_get_contents($url);
$json = json_decode($str);
$temp = $json->main->temp_min;
$content = $temp;
$array = array(
"content" => $content,
"refresh_requency" => 30
);
echo json_encode($array);
?>
2) You did not put array key into quotes:
$array = array(
"content" => $content,
refresh_requency => 30
);
It should be :
$array = array(
"content" => $content,
"refresh_requency" => 30
);
Access $temp like this
$temp = $json->main->temp_min;
you will get the desired output.
Also, you need to allow allow_url_fopen in your php.ini config file. Some hosts disallow it for security reasons
$json = json_decode($str, true);
You need second argument to convert json string into associative array instead of the object. And you are trying to use array ($json['main']['temp_min']), not object. Also
$array = array(
"content" => $content,
"refresh_requency" => 30
);
The code looks like
<?php
$url = "http://api.openweathermap.org/data/2.5/weather?id=4879890&units=imperial";
$str = file_get_contents($url);
$json = json_decode($str, true);
$content = $json['main']['temp_min'];
$array = array(
"content" => $content,
"refresh_requency" => 30
);
echo json_encode($array);
And result is http://codepad.viper-7.com/euBNAk :
{"content":44.6,"refresh_requency":30}
The second parameter of json_decode() is assoc (associative). By default it is 0. When it is 0 (default) the json_decode() will return an object, not an array. That's why you are unable to access temp_min by using $json['main']['temp_min'];
However If you use with the value 1 as second parameter, the function will return an array. Parameter 1 means setting associative to 1 (true). So use $json = json_decode($str, true); instead of $json = json_decode($str);. You will be able to access with $json['main']['temp_min']; now.
Also you forgot double quote on line 13 (refresh_requency). Goodluck.
<?php
$url = "http://api.openweathermap.org/data/2.5/weather?id=4879890&units=imperial";
$str = file_get_contents($url);
$json = json_decode($str, true);
$temp = $json['main']['temp_min'];
$content = $temp;
$array = array(
"content" => $content,
"refresh_requency" => 30
);
echo json_encode($array);
Just want help
I change your code like this and that be correctly
<?php
$url = "http://api.openweathermap.org/data/2.5/weather?id=4879890&units=imperial";
$str = file_get_contents($url);
$json = json_decode($str, TRUE); // Wrong here
$temp = $json['main']['temp_min'];
$content = $temp;
$array = array(
"content" => $content,
"refresh_requency" => 30 // And wrong here, it's must string
);
echo json_encode($array);
?>
More information about json decode in php to array or object http://php.net/manual/en/function.json-decode.php
I would like to be able to extract a title and description from Wikipedia using json. So... wikipedia isn't my problem, I'm new to json and would like to know how to use it. Now I know there are hundreds of tutorials, but I've been working for hours and it just doesn't display anything, heres my code:
<?php
$url="http://en.wikipedia.org/w/api.php?action=query&prop=extracts|info&exintro&titles=google&format=json&explaintext&redirects&inprop=url";
$json = file_get_contents($url);
$data = json_decode($json, TRUE);
$pageid = $data->query->pageids;
echo $data->query->pages->$pageid->title;
?>
Just so it easier to click:
http://en.wikipedia.org/w/api.php?action=query&prop=extracts|info&exintro&titles=google&format=json&explaintext&redirects&inprop=url&indexpageids
I know I've probably just done a tiny thing wrong, but its really bugging me, and the code... I'm used to using xml, and I have pretty much just made the switch, so can you explain it a bit for me and for future visitors, because I'm very confused... Anything you need that I haven't said, just comment it, im sure I can get it, and thanks, in advance!
$pageid was returning an array with one element. If you only want to get the fist one, you should do this:
$pageid = $data->query->pageids[0];
You were probably getting this warning:
Array to string conversion
Full code:
$url = 'http://en.wikipedia.org/w/api.php?action=query&prop=extracts|info&exintro&titles=google&format=json&explaintext&redirects&inprop=url&indexpageids';
$json = file_get_contents($url);
$data = json_decode($json);
$pageid = $data->query->pageids[0];
echo $data->query->pages->$pageid->title;
I'd do it like this. It supports there being multiple pages in the same call.
$url = "http://en.wikipedia.org/w/api.php?action=query&prop=extracts|info&exintro&titles=google&format=json&explaintext&redirects&inprop=url";
$json = file_get_contents($url);
$data = json_decode($json, TRUE);
$titles = array();
foreach ($data['query']['pages'] as $page) {
$titles[] = $page['title'];
}
var_dump($titles);
/* var_dump returns
array(1) {
[0]=>
string(6) "Google"
}
*/
Try this it will help you 💯%
This code is to extract title and description with the help of Wikipedia api from Wikipedia
<?php
$url = 'http://en.wikipedia.org/w/api.php?action=query&prop=extracts|info&exintro&titles=google&format=json&explaintext&redirects&inprop=url&indexpageids';
$json = file_get_contents($url);
$data = json_decode($json);
$pageid = $data->query->pageids[0];
$title = $data->query->pages->$pageid->title;
echo "<b>Title:</b> ".$title."<br>";
$string=$data->query->pages->$pageid->extract;
// to short the length of the string
$description = mb_strimwidth($string, 0, 322, '...');
// if you don't want to trim the text use this
/*
echo "<b>Description:</b> ".$string;
*/
echo "<b>Description:</b> ".$description;
?>