Laravel Model get all where $id = Auth::user()->id - php

How to List all rows from a DB where $id matches the logged user id.
I'm using default Auth from Laravel.
At the moment i can list them all with this method in my controller:
public function index(){
$invoices = Invoice::all();
return view('index', compact('invoices'));
}
But i just want the ones that are from this user which is logged in:
Something like
$invoices = Invoice::where('id', '=', Auth::user()->id);

Your code Seems almost right. I would do:
$invoice = Invoice::where('id', Auth::user()->id)->get();
So basically use the get in order to fetch a collection. And maybe I would separate the user id in a varaible in case that you change the authentication in the future ;)

When using any condition then of course you must need to add the get() method. Otherwise, you can't show your data.
$invoices = Invoice::where('id', '=', Auth::user()->id)->get();
This means that you want to see data on which user is logged in now

Related

LARAVEL: How to fetch id dynamically in a query builder?

I want to join multiple tables in laravel with query builder. My problem is that my code only works if I specify the id myself that I want like this:
$datauser = DB::table('users')
->join('activitates','users.id','=','activitates.user_id')
->join('taga_cars','taga_cars.id','=','activitates.tagacar_id')
->join('clients','users.id','=','clients.user_id')
->where('users.id','=','1')
->select('users.*','activitates.*','taga_cars.model','taga_cars.id','clients.name')
->get();
return response()->json($datauser);
But I would want something like this(which I just can't seem to figure out)
public function showuser($id)
{
$userid = User::findOrFail($id);
$datauser = DB::table('users')
->join('activitates','users.id','=','activitates.user_id')
->join('taga_cars','taga_cars.id','=','activitates.tagacar_id')
->join('clients','users.id','=','clients.user_id')
->where('users.id','=',$userid)
->select('users.*','activitates.*','taga_cars.model','taga_cars.id','clients.name')
->get();
return response()->json($datauser);
}
Am I making a syntax mistake? When I check the page for my json response in second page it just returns empty brackets, but when I specify the id it fetches me the right data
The findOrFail method will return the entire user model, with all its properties, since you already have the user id. You dont need to get the entire user model for that, you could just use the $id you receveid as a parameter like this:
$datauser = DB::table('users')
->join('activitates','users.id','=','activitates.user_id')
->join('taga_cars','taga_cars.id','=','activitates.tagacar_id')
->join('clients','users.id','=','clients.user_id')
->where('users.id','=',$id)
->select('users.*','activitates.*','taga_cars.model','taga_cars.id','clients.name')
->get();
return response()->json($datauser);
public function showuser($id)
{
$getUserByID = User::findOrFail($id); //not used
$userData = DB::table('users')
->join('activitates','users.id','=','activitates.user_id')
->join('taga_cars','taga_cars.id','=','activitates.tagacar_id')
->join('clients','users.id','=','clients.user_id')
->where('users.id','=',$id)
->select('users.*','activitates.*','taga_cars.model','taga_cars.id','clients.name')
->get();
return response()->json($userData);
}
But the best way is to have relations set on models
public function showuser($id)
{
$userData = User::where('id', $id)->with(['activitates','taga_cars','clients'])->first();
return response()->json($userData);
}

Laravel : How to get all the rows from a table except the first one?

I want to select all the users in my table "User" except the first One cause its the admin,
im using this function index in my controller but it doesn't work .
public function index()
{
// this '!=' for handling the 1 row
$user = User::where('id', '!=', auth()->id())->get();
return view('admin.payroll',compact('user'))->with(['employees' => User::all()]);
}
Better to used here whereNotIn Method
Note: first you find the admin role users and create a static array
$exceptThisUserIds = [1];
$user = User::whereNotIn('id', $exceptThisUserIds)->get();
It's not a good idea to specify the admin user with just id. A better design would be using some sort of a flag like is_admin as a property of your User model.
Still you can use the following code to get the users who have an id greater than 1:
User::where('id', '>', 1)->get()
For getting data skipping the first one you should use skip() method and follow the code like below
public function index()
{
$user = User::orderBy('id','asc')->skip(1)->get();
return view('admin.payroll',compact('user'))->with(['employees' => User::all()]);
}

laravel get list of users only email verified

When I try to get the list of users from User:all(), it shows me the users who also are not email verifed.
So to avoid the above situation, I am writing the following code.
$users = User::with('selfie')->whereNotNull('email_verified_at')->orderBy('created_at', 'desc')->get();
let me know if there is any other shorter way.
We can define scope https://laravel.com/docs/8.x/eloquent#local-scopes
in User Model
public function scopeVerified($query)
{
return $query->whereNotNull('email_verified_at');
}
and our query will looks like
$users = User::with('selfie')
->verified()
->orderBy('created_at', 'desc')
->get();
I hope it will work
$users = User::whereNOTNULL('email_verified_at')->get();
You get all list

Laravel 5.2 : Fetch records against logged in user id

I am fetching records in controller :
$tasks = Task::where('user_id', '=', Auth::user()->id);
return view('todo',compact('tasks'));
But it returns null.
And Auth::user()->id returns 2 Which is Okay.
Am i missing something ?
You need to actually retrieve the record. What you have is an instance of \Illuminate\Database\Eloquent\Builder, but not the actual record(s) associated with the query.
To tell Eloquent to fetch the data, you need to use either get().
Like:
$tasks = Task::where('user_id', '=', Auth::user()->id)->get();
As a side note, you can simplify your query to be:
$tasks = Task::where('user_id', Auth::user()->id)->get();
Furthermore, on your User model, you could do this:
public function tasks()
{
return $this->hasMany(Task::class) // make sure you use the full namespace here or use at the top of User.php
}
And then you can simply do:
$tasks = auth()->user()->tasks;
This is a Relationship in Eloquent as explained in the docs.

Laravel : How to use eloquent ORM to find information of NOT authenticated user?

So I have this function to get the info of a user who is currently logged in.
$users = User::get();
$loginuser = $users->find(Auth::user()->id);
How do I use Laravel's eloquent ORM to get other users and put it in an array variable? Maybe something like
$otherusers = $users->find(not(Auth::user()->id));
Of course, it will not work but you get what I mean. Bonus points for improvement of the first 2 lines above~! Thank you!
You may try this to get all the users other than the logged in user:
$otherusers = User::where('id', '!=', Auth::user()->id)->get();
If you use Auth::user() then you'll get only the currently logged in user. So for example:
// Logged In user, You can directly use
// Auth::user()->id or any property, no
// need keep it in a variable for that
$loggedInUser = Auth::user(); // Returns a single Model
// Other users (Returns a collection of user models)
// Check if a user is logged in before you use Auth::user()->id
$otherusers = User::where('id', '!=', Auth::user()->id)->get();

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