php mysqli command cannot be executed now error - php

Question

I am trying to update my SQL table with the help of this php code:
$description = "Something about myself";
$insert = $con->prepare("INSERT INTO kys_write (Author, writing , Title , Description , Assets) VALUES (?,?,?,?,?)");
$insert->bind_param("ssssi",$author,$data,$title,$description, $ImageExist);
$insert->execute();
$statement = $con->prepare("SELECT id FROM kys_write WHERE Title=?");
$statement->bind_param("s",$title);
$statement->execute();
$statement->bind_result($lastId);
//Everything works fine if this whole part is removed
$sql = "UPDATE kys_essentials SET LastId=".$lastId;
if ($con->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $con->error;
}
I am getting a error:
Error updating records:Commands out of sync, you cannot run this command now.
What causes this, and how can I avoid it?

Answer 1

It clear that the result sets of a prepared statement execution need to be fetched completely before executing another prepared statement on the same connection.
You can simplify you code using one query . no use of extra select query
$sql = "UPDATE kys_essentials SET LastId = (SELECT id FROM kys_write WHERE Title='$Title')";
if ($con->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $con->error;
}

Answer 2

Fetch your $lastId after the binding and put ' ' for value/s, like this:
//your codes
$statement->bind_result($lastId);
while ($statement->fetch()){
$sql = "UPDATE kys_essentials SET LastId='".$lastId."'";
if ($con->query($sql) === TRUE){
echo "Record updated successfully";
} else{
echo "Error updating record: " . $con->error;
}
}