Cakephp find data in controller also can with sql syntax,
example :
$this->Post->find('all');
in sql :
select * from posts
convert query to cakephp find syntax is available at http://dogmatic69.com/sql-to-cakephp-find-converter
but whether there is any link for me if I wanna convert my cakephp find to query..
Thanks in advance...
If I got what you are asking, here is the answer
SQL calls that you can’t or don’t want to make via other model
methods can be made using the model’s query() method (though this
should only rarely be necessary).
query() uses the table name in the query as the array key for the returned data, rather than the model name. For example:
$this->POST->query("SELECT* from posts;");
Here is the link for cakephp documentation
Related
Care to put light to the subject. Issue is that when I do what ever to code I find that code does not go further to retrieve data from table Sectors and table courses. I have applied find() I use CakePHP 4.x to make clear that it is latest version of CakePHP called Strawberry. I also do not understand that why does my code get affected while I apply simple code structure to run my code.
Take a look at code snippet to run a simple find query with CakePHP Strawberry.
$Sectors is not defined but I need to know a way to define and apply $Sectors variable so that I have given value for relative table structure.
Table Does not load because of a problem I do not understand yet but guys help me out I'll update my code and make use of real code that is to determine a structure for code that will work for CakePHP Strawberry.
code:
$this->loadModel('Sectors');
$this->loadModel('Courses');
$Sectors = $Sectors->find('all')->contain('Sectors', 'Courses');
pr($sectors);
$this->contain(['Sectors', 'Courses']);
$this->set(compact('sectors'));
To retrieve data from table so that I get data relation from Sectors and Courses table.
error:
Call to a member function find() on null
Answer is simple but problem is CakePHP would keep single model with multiple query but not multiple model with single query.
Using Yii 1 and ActiveRecord -
I'm pretty new in both.
$types = CasinoSgTypes::model();
$types->findAll();
$types->findByPk(3);
I thought Yii AR will try to search in recently received data first instead of that I've got 2 calls to the database. Probably I'm using it in a wrong way?
sure i can walk through the array of results received by the first query (findAll) manually, but I'd like to do this by means of AR.
in other words is there a way to force AR search inside already received data and only then ask the database or smth like this. how to use AR+Yii models in a right way to avoid unnecessary queries ?
When you call $types->findAll(); the data isn't saved in the AR class and as such you cannot search using it. An easier alternative to searching in the data is to use query caching:
$types->cache(3600)->findByPk(3);
since my last question in SO, I've been reading a bit about how to prevent sql injection and many people mentioned active records class. but when I google it, it only exists in codeigniter 2.
so my questions are:
is Query Builder Class in codeigniter 3 the upgraded version of Active Record Class or do they serve different purposes?
is it enough (in general) to use Query Builder Class methods like $this->where('field', $foo); instead of $this->where("field = '$foo'"); to prevent sql injection?
P.S. I'm using codeigniter 3 and mysql
1- ActiveRecord was in Codeigniter 2, but in Codeigniter 3 you have QueryBuilder instead. The both classes do same work for you, maybe QueryBuilder is improved version of ActiveRecord. In other frameworks like Yii2, ActiveRecord is an ORM not only query string builder but in CI was simple query builder.
2- Codeigniter will escape all passed parameters automatically but I suggest you validate your inputs before running queries. For example, the value of a numeric id field should be a number, not a string so the rule of ID input should be INTEGER.
You can see Validation in Codeigniter 3 at official documentation: https://www.codeigniter.com/userguide3/libraries/form_validation.html
All works that you should do is pass your field value as a function parameter, not as a string (field and value together). If you want to run your query without QueryBuilder, you must escape your parameters manually. You can get more information about it in Codeigniter documentation:
https://www.codeigniter.com/userguide3/database/queries.html#escaping-queries
So I know that you can query a table using PHP as so:
$projectmanager=DB::table('Table_name')->distinct()->select('Table_Column')->get();
I want to know if you can do the same type of thing with a SQL Server View. I have tried the following:
$view=DB::view('View_Name')->select('View_Column')->get();
But I get the following error:
call_user_func_array() expects parameter 1 to be a valid callback, class 'Illuminate\Database\SqlServerConnection' does not have a method 'view'
Are you using Laravel by chance? Whatever the framework, you are calling a method DB::view that doesn't exist, so some class magic fails.
To answer question, yes. To PHP they are seen the same as a regular table, treat it as such for querying (though you cannot manually update them of course).
$projectmanager=DB::table('View_name')->distinct()->select('View_column')->get();
This is a follow-up to an earlier question here: CakePHP find statement for a sql query involving two models
I wasn't sure whether to add it on to there, but I figured this is a new question in itself. My apologies if this isn't correct!
Given a cakephp find subquery, is it possible to use paginate() on the results of the find? from the cake documentation, it seems that the paginate() function only works on Models, not on an array of data.
Thank you!
if you already have all the data in the array, I suggest output all that to your page (not the same as showing all the data) and use javascript to paginate it (just use a javascript grid plugin out there): more responsive app and less load on the server.