date('H:i',$ans) returns wrong value - php

Question

I have to calculate a time difference in php script. There are in time and out time values. I wrote following code to get the difference. But it always returns correct answer + 1 value.
$inTime = '08:30:00';
$outTime = '17:48:00';
$difference = date('H:i',((strtotime($outTime) - strtotime($inTime))));
echo $difference;
The out put is printed as 10:18. But the output should be 09:18. I use Codeigniter framwork. I run this code with online php tester (http://phptester.net/) and it returns the correct value.

Answer 1

check out this method...
<?php
$time1 = new DateTime('08:30:00');
$time2 = new DateTime('17:48:00');
$interval = $time2->diff($time1);
echo "Time Difference : ".$interval->format('%H hours %i minutes %s seconds');
?>
This will output :
Time Difference : 09 hours 18 minutes 0 seconds

Answer 2

function datediff( $date1, $date2 )
{
$diff = abs( strtotime( $date1 ) - strtotime( $date2 ) );
return sprintf
(
"%d Days, %d Hours, %d Mins, %d Seconds",
intval( $diff / 86400 ),
intval( ( $diff % 86400 ) / 3600),
intval( ( $diff / 60 ) % 60 ),
intval( $diff % 60 )
);
}
$inTime = '08:30:00';
$outTime = '17:48:00';
print datediff( $inTime, $outTime ) . "\n";
Online Demo : Click Here
For only Minutes:
function datediff( $date1, $date2 )
{
$diff = abs( strtotime( $date1 ) - strtotime( $date2 ) );
return sprintf
(
"%d Mins",
intval(((( $diff % 86400 ) / 3600) * 60))
);
}
$inTime = '08:30:00';
$outTime = '17:48:00';
print datediff( $inTime, $outTime ) . "\n";
Output
558 Mins
Online Demo: Click Here

Answer 3

There are lots of ways you can do this, personally I would use PHP's built in time difference functions.
$inTime = date_create('08:30:0');
$outTime = date_create('17:48:00');
$difference = date_diff($inTime, $outTime);
echo $difference->format('%H:%I:%S');
outputs:
09:18:00
example