I have the following code which puts the content of a Wordpress post onto the page (the images were removed)
<?php
$content = preg_replace('/<blockquote>(.*?)<\/blockquote>/', '', get_the_content());
$content = preg_replace('/(<img [^>]*>)/', '', get_the_content());
$content = wpautop($content); // Add paragraph-tags
$content = str_replace('<p></p>', '', $content); // remove empty paragraphs
echo $content;
?>
I want to remove the blockquote as well, which it does, HOWEVER placed where it currently is it does not remove the blockquote.
Placed after the 'img' line it DOES remove the block quote but the images are put back in
You should use
strip_tags — Strip HTML and PHP tags from a string
$string = get_the_content();
// remove all html tags
echo strip_tags($string);
// Allow specific tags such as <p> and <a>
echo strip_tags($string, '<p><a>');
To remove the styled quotation mark in the blockquote element, you'll need to modify the ::before pseudo-element, which contains: content: "
CSS to add:
blockquote::before {
content:none;
}
Related
I have a set of <p></p> tags wrapping a set of data, that data includes other tags such as <script></script> however that content could contain any number of different tags.
I just need to remove any paragraph tags from the content
Example below
$text = "<p><script>example text inside script.<script></p>";
I see the strip_tags function but I believe that will remove all the tags.
How would I go about just removing the paragraph?
Thanks.
Try,
$text = "<p><script>example text inside script.<script></p>";
$formatted_text = str_replace(['<p>', '</p>'], '', $text);
You can allow tag with strip_tags()
like this example:
$text = "<p><script>example text inside script.<script></p>";
echo strip_tags($text, '<script>');
Try this.
<?php
$text = "<p><script>example text inside script.<script></p>";
$replace = array('<p>','</p>');
echo str_replace($replace,'',$text);
http://sandbox.onlinephpfunctions.com/code/43150c7af4e7e5f572827d91abca5756213ab7ba
Version 2 (works for classes)
echo preg_replace('%<p(.*?)>|</p>%s','',$text);
http://sandbox.onlinephpfunctions.com/code/6c5414773efc1317578b5f0581b68e5acabb9a2b
Hope this helps.
You can use str_replace(),
add this line -
$text = str_replace('<p>','',$text);
$text = str_replace('</p>','',$text);
It will remove both
<p> and </p>
I'm looking to separate the text and images in my Wordpress post. I want to be able to put them in different areas on my page.
I currently have only been able to get the content in tags but can't isolate and separate the content.
current html
<?php
$content = wpautop($content); // Add paragraph-tags
$content = str_replace('<p></p>', '', $content); // remove empty paragraphs
$content = preg_replace('/<p>\s*(<a .*>)?\s*(<img .* \/>)\s*(<\/a>)?\s*<\/p>/iU', '\1\2\3', $content); // remove paragraphs around img tags
echo $content;
?>
Updated based on your comment.
You can get all the content with no images.
$content = get_the_content();
$text = wp_strip_all_tags( $content );
And to get the images you can get all the URLs inside of an array.
$re = '/<img .+? src="(.+?)"/i';
preg_match_all( $re, $content, $images );
// images url are located on $images[1]
I want to pull out the list (ul) element from my wordpress post(s) so I can put it in a different location.
My current css pulls out the images and blockqute and puts just the text
html
<?php
$content = preg_replace('/<blockquote>(.*?)<\/blockquote>/', '', get_the_content());
$content = preg_replace('/(<img [^>]*>)/', '', $content);
$content = wpautop($content); // Add paragraph-tags
$content = str_replace('<p></p>', '', $content); // remove empty paragraphs
echo $content;
?>
Just a friendly reminder is that it is generally not recommended to parse html with regex.
If you would like to do that anyway you could try like this:
$pattern = '~<ul>(.*?)</ul>~s';
So in your code it would look like this:
preg_match_all('/(~<ul>(.*?)</ul>~s)/', $content, $ulElements);
And then for removing it from the original string:
preg_replace('/(~<ul>(.*?)</ul>~s)/', '', $content);
Trying to post the content of a post WITHOUT the blockquote or images. My code takes out the images but still puts in the block quote and text.
<?php
$content = preg_replace('/<blockquote>(.*?)<\/blockquote>/', '', get_the_content());
$content = preg_replace('/(<img [^>]*>)/', '', get_the_content());
$content = wpautop($content); // Add paragraph-tags
$content = str_replace('<p></p>', '', $content); // remove empty paragraphs
echo $content;
?>
Simple error here - your second call to preg_replace() is using get_the_content(), which is the unmodified content - so you're basically doing away with what you did on your first line.
For the second line to use the output of the first line, your second parameter needs to be $content:
$content = preg_replace('/(<img [^>]*>)/', '', $content);
I need to strip all html tags but retain comment lines to extract for info.
Is it even possible?
$content = strip_tags($content, '<!-->');
This doesn't work and i have tried a few different variants.
you can protect your comment before strip them using following code
// create a random string for using in replace strings
$random = strtoupper(dechex(rand(0,10000000000)));
// replace comment starts
$html = preg_replace('/<!--/', '#MARKER-START-'. $random.'#', $html);
// replace comment ends
$html = preg_replace('/-->/', '#MARKER-END-'. $random.'#', $html);
// strip all html tags
$html = strip_tags($html);
// replace back comment starts
$html = preg_replace('/#MARKER-START-'. $random.'#/', '<!--', $html);
// replace back comment ends
$html = preg_replace('/#MARKER-END-'. $random.'#/', '-->', $html);
Instead of using strip_tags() use this regular expression:
$szRetVal = preg_replace( '%</?[a-z][a-z0-9]*[^<>]*>%sim','',$szHTML );