How to add new table and column by form input - php

Question

I wanted to add New table in my database and this table should have 5 columns but it should be done by filling up a form in the website Let's say I'm going to add Travel Order table with it's five columns. Now i have this code in my form and it gives me this error: Call to undefined method mysqli::mysqli_real_escape_string()
<input type="text" class="form-control1" onKeyPress= "return lettersOnly(event)" name= "categoryname" id="categoryname" placeholder="Category Name..." maxlength="30" reqiured> this for the table name.
<input type="text" class="form-control1" onKeyPress= "return lettersOnly(event)" name="firstattrib" id="firstattrib" placeholder="..." maxlength="30"> this for one of the column. (please don't mind my naming of variables)
`
$connect = mysqli_connect("localhost","root","","doctrack_db");
// Check connection
if ($connect->connect_error) {
die("Connection failed: " . $connect->connect_error);
}
// sql to create table
$sql = "CREATE TABLE ".$categoryname." (
id INT(6) UNSIGNED AUTO_INCREMENT NOT NULL,
file LONGBLOB(30) NOT NULL,
)";
$firstattrib = $connect->mysqli_real_escape_string($_POST['firstattrib']);
//query to add columns to table
$query = 'ALTER TABLE ' .$categoryname . '
ADD COLUMN '. $firstattrib .' VARCHAR(30) TINYINT NOT NULL DEFAULT \'0\' AFTER file';
if ($connect->query($sql)&$connect->query($query) === TRUE) {
echo "alert('Category created successfully!!')";
} else {
echo "alert('Error creating Category!!')" . $connect->error;
}
$connect->close();
?>`
Can you please tell me which part i got wrong or is it wrong as a whole?

Answer 1

try this
<?php
// Create connection
mysql_connect("localhost","root","","test") OR die("Server Connection error");
mysql_select_db("test") OR die("DB error");
$category = "category";
// sql to create table
$sql = "CREATE TABLE ".$category." (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL,
email VARCHAR(50),
reg_date TIMESTAMP
)";
if(mysql_query($sql)){
$sql1 = "INSERT INTO ".$category." (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
mysql_query($sql1);
}
?>
and it doesn't matter when you create table, what matter is when you inserting data into table have to has exist.