PHP MySql fetch json no content - php

Question

I have problem fetching my result from db and convert to json. In my API call, It gives me empty content(total blank) of returned body with status 200.
This is my code:
$weekAndYear = $year."/".$week; // incoming params as e.g "2016/19"
$stmt = $this->db->prepare("SELECT r.*, p.code FROM report r, product p WHERE "
. "r.pid=p.pid AND r.product=:productCode "
. "AND r.status='Published' AND r.pid=25 AND r.week=:weekAndYear");
$stmt->bindparam(":productCode", $productCode);
$stmt->bindparam(":weekAndYear", $weekAndYear);
$stmt->execute();
while($price=$stmt->fetch(PDO::FETCH_ASSOC)) {
//echo $price;
$arr_price[] = $price;
}
$data['priceReport'] = $arr_price;
//echo $weekAndYear;
$data['status'] = "OK";
return json_encode($data);
When I tested the query in my phpmyadmin mysql server and it works fine.
On my php side, different $weekAndYear params will have some working well and some are not. Anything wrong on array part?
My API response headers:
Cache-Control →no-store, no-cache, must-revalidate, post-check=0, pre-
check=0
Connection →Keep-Alive
Content-Length →0
Content-Type →application/json
Date →Thu, 05 May 2016 06:49:28 GMT
Expires →Thu, 19 Nov 1981 08:52:00 GMT
Keep-Alive →timeout=5, max=100
Pragma →no-cache
Server →Apache/2.4.18 (Unix) LibreSSL/2.2.6 PHP/5.5.31
X-Powered-By →PHP/5.5.31
I've been scratching my head for few days and now I just have few hairs left.
Please help. Thank you.

Answer 1

I'm assuming (maybe wrongly) that your code snippet isn't a function.
Change the last line from return to echo as follows:
echo json_encode($data);

Answer 2

Unless the first code snippet is a function, you need to use json_encode not a return statement.
What happens is that Fetch can fetch any type of content, even HTML. What PHP does is it generates content writes it to a file and sends it to the browser. When you generate HTML with PHP you do not return it, you echo it to the page.
The same thing happens with AJAX. You use PHP to write data to a file and serve it.
So replace this:
return json_encode($data);
with this:
echo json_encode($data);