Basically i have 3 forms.
I have one action in my form and i want create 3 steps form using session.
I want when i click the next button it validates the form1,if successful then redirects to form2..
like wise for form3 but keep all the data in session and in third step the action goes runs and add all the data to database.
I only need to check conditions from session before my insert goes run in my action addjob.
Plz help me to do this.
My main question is how to get all the post data in one session variable and check step by step before insert..
i am learner in cakephp and i have not enough idea about session.
if you are a expert then plz do this.
public function addjob($id = NULL) {
$this->layout = "layout_registration_old";
$this->loadcategory();
$this->loadcargo();
//$this->loadsubcategory();
$this->getCountries();
$this->getstates();
if ($this->request->is('put') || $this->request->is('post')) {
if (isset($id)) {
$this->Job->id = $id;
} else {
$this->request->data['Job']['status'] = 1;
$this->request->data['Job']['job_type'] = 1; //this is used to update the job type private or public.
$this->Job->create();
}
$this->Job->set($this->request->data);
if ($this->Job->AddEdit()) { // ADDEdit is the validation name in model
if ($this->Job->save($this->request->data['Job'], false)) {
if (isset($id)) {
$this->Session->setFlash(__('Job has been updated sucessfully.'));
} else {
$this->Session->setFlash(__('Job has been added succesfully.'));
}
$this->redirect(array('controller' => 'jobs', 'action' => 'index'));
}
} else {
$errors = $this->Job->validationErrors;
$this->Session->setFlash(__('Please check your entry.'), 'flash_error');
}
}
if (isset($id)) {
$this->request->data = $this->Job->find('first', array('conditions' => array('id' => base64_decode($id))));
}
}
form - 1
<?php echo $this->Form->create('Job', array('url' => array('controller' => 'jobs', 'action' => 'addjob')));?>
<?php echo $this->Form->input('customer_name',array('div' => false, 'label' => false));?>
<?php echo $this->Form->input('customer_no',array('div' => false, 'label' => false));?>
<?php echo $this->Form->input('customer_email',array('div' => false, 'label' => false));?>
<?php
echo $this->Form->input('transport_type', array(
'type' => 'select',
'label' => false,
'class' => 'select',
'options' => array(
1 => 'Road'
),
));
?>
<?php echo $this->Form->submit('Save', array('class' => "navigation_button btn btn-primary btn-sm", 'div' => false)); ?>
<?php echo $this->Form->end(); ?>
form - 2
<?php echo $this->Form->create('Job', array('url' => array('controller' => 'jobs', 'action' => 'addjob')));?>
<?php echo $this->Form->input('fname',array('div' => false, 'label' => false));?>
<?php echo $this->Form->input('lname',array('div' => false, 'label' => false));?>
<?php echo $this->Form->input('email',array('div' => false, 'label' => false));?>
<?php echo $this->Form->submit('Save', array('class' => "navigation_button btn btn-primary btn-sm", 'div' => false)); ?>
<?php echo $this->Form->end(); ?>
form - 3
<?php echo $this->Form->create('Job', array('url' => array('controller' => 'jobs', 'action' => 'addjob')));?>
<?php echo $this->Form->input('shop',array('div' => false, 'label' => false));?>
<?php echo $this->Form->input('business',array('div' => false, 'label' => false));?>
<?php echo $this->Form->input('status',array('div' => false, 'label' => false));?>
<?php echo $this->Form->submit('Save', array('class' => "navigation_button btn btn-primary btn-sm", 'div' => false)); ?>
<?php echo $this->Form->end(); ?>
Instead of saving the data from first 2 forms in a session, you should implement a multi part form using any javascript solution (Form wizard). Validate the data of each step using javascript or via ajax (if needs to be done dynamically) before moving to the next step and submit form at the end so that you don't have to play with sessions.
Example link
PS - This could go as a comment to the question but I haven't gained enough reputations to post comments yet :(
Related
I have 3 dependent dropdowns, and a textfield being dependent to the last dropdown. If one of the value in the last dropdown, I want the textfield value dynamically changes based on the selected value (it's from the same Database table).
This is the view of the third dropdown:
<div class="row" id="id_subkeg">
<?php echo $form->labelEx($model, 'id_subkeg'); ?>
<?php
echo $form->dropDownList($model, 'id_subkeg', array(), array(
'style' => 'width: 100%',
'ajax' => array(
'type' => 'POST',
'url' => CController::createUrl('dynamicSatuan'),
'update' => '#' . CHtml::activeId($model, 'satuan'),
//'update'=>'#seksi',
'data' => array('id_subkeg' => 'js:this.value'),
)
)
);
?>
<?php echo $form->error($model, 'id_subkeg'); ?>
</div>
This is the textfield view:
<div class="row" id="satuan">
<?php echo $form->labelEx($model, 'satuan'); ?>
<p class="hint" style="font-size: 80%">Contoh: Dokumen.</p>
<?php echo $form->textField($model, 'satuan', array('style' => 'width: 98%;', 'readonly' => FALSE)); ?>
<?php echo $form->error($model, 'satuan'); ?>
</div>
And this is the action in the controller:
public function actionDynamicSatuan() {
//$data = Subkegiatan::model()->findByPk($_POST['id_subkeg']);
$data = Subkegiatan::model()->findByPk('id_subkeg=:id_subkeg', array(':id_subkeg' => (int) $_POST['id_subkeg']));
echo $data->satuan;
}
But it's not been working for days. I don't know which part I've missed. My guess is that the dropdown is a dependent dropdown to the one above it. So I must have missed at some part.
Any help is highly appreciated.
UPDATE:
After days of searching, finally got it:
public function actionDynamicSatuan() {
$param_country = (int) $_POST['id_subkeg'];
$maxOrderNumber = Yii::app()->db->createCommand()
->select('satuan')
->from('subkegiatan')
->where('id_subkeg = ' . $param_country)
->queryScalar();
echo '<b>SATUAN: '. $maxOrderNumber.'</b>';
//echo CHtml::tag('input', array('type' => 'text', 'value' => $maxOrderNumber));
}
Instead of update, use success callback:
echo $form->dropDownList($model, 'id_subkeg', array(), array(
'style' => 'width: 100%',
'ajax' => array(
'type' => 'POST',
'url' => CController::createUrl('dynamicSatuan'),
'data' => array('id_subkeg' => 'js:this.value'),
'success'=> 'function(data) {
$("#your_id_here").empty();
$("#your_id_here").append(data);
}'
)
)
);
Using cakephp 1.3 I fill out a form, and upon debugging the submit, I notice that
data:$("#submit-478065271").closest("form").serialize()
is empty. Why would something like that happen? I've checked that the form actually has data, which I can serialize manually. Here is the submit code:
echo $this->Js->submit(
'Sign up',
array(
'class' => 'btn btn_submit fr register_submit register_btn_align',
'url' => array('controller' => 'email_guides', 'action' => 'subscribe'),
'before' => '$(".error-message").remove();' . $this->Js->get('#loading')->effect(
'fadeIn',
array('buffer' => false)
),
'complete' => $this->Js->get('#loading')->effect(
'fadeOut',
array('buffer' => false)
) . 'debugger;',
'success' => 'if(data.success) {
$("#CustomUserFirstName").val("");
$("#CustomUserEmail").val("");
$("#EmailGuidesUserStartDate").val("' . date('d/m/Y', strtotime('+1 Weekday')) . '");
$("#EmailGuidesUserTerms").attr("checked", false);
$("#signupModal").hide();
} else {
$("#signupModal").hide();
}
'type' => 'json'
)
);
?>
<?php echo $this->Form->end(); ?>
UPDATE: I've noticed that the form is not a parent of the submit element ... which is very bizarre. This would explain why .closest("form") returns an empty array.
I have a form to add a new user. Only an admin who is logged in may access this form. Unfortunately, the username and the password of the admin are filled into the form fields which are expected to be completely clear. And one really strange thing is: The username is printed into the birthday field!
I really cannot explain myself how it works. And I could not found in the WWW any post from a person who has got the same problem - I only found questions and answers about pre-filled form data that is wanted.
This is the View /Users/add.ctp
<h1>Add a new Member</h1>
<?php echo $this->Form->create('User', array('url' => BASE_URL.'/users/add', 'action'=>'post')); ?>
<table class="form">
<tr><td>Username:</td><td><?php echo $this->Form->input('User.username', array('label' => false, 'div' => false, 'value' => ''));?></td></tr>
<tr><td>Name:</td><td><?php echo $this->Form->input('User.name', array('label' => false, 'div' => false, 'value' => ''));?></td></tr>
<tr><td>Lastname:</td><td><?php echo $this->Form->input('User.lastname', array('label' => false, 'div' => false, 'value' => ''));?></td></tr>
<tr><td>E-Mail:</td><td><?php echo $this->Form->input('User.email', array('label' => false, 'div' => false, 'value' => ''));?></td></tr>
<tr><td>Birthday:</td><td><?php echo $this->Form->input('User.birth', array('label' => false, 'div' => false, 'value' => ''));?></td></tr>
<tr><td>Password:</td><td><?php echo $this->Form->input('User.password', array('label' => false, 'div' => false, 'value' => ''));?></td></tr>
</table>
<?php
echo $this->Form->submit('Submit', array('formnovalidate' => true));
echo $this->Form->end();
?>
And here is the Controller /UsersController.php
public function add() {
$this->layout = 'admin';
if ($this->request->is('post')) {
// Saving the data
$this->User->create();
if ($this->User->save($this->request->data)) {
$this->Session->setFlash(__('Data saved.'));
return $this->redirect(array('action' => 'view'));
}
$this->Session->setFlash(__('Data could not be saved.'));
}
}
By the way: Saving works fine.
Of course, the admin is of Object User, as is the new member to be added. I think, here lies the problem, but I really do not know... I am thinking about this problem the whole day :( Does anybody know what to do?
Thanks in advance.
Is not your browser? (saved username/password when you type for the first time)
So, you can turn of the autocomplete.
<?php echo $this->Form->create('User', array('url' => BASE_URL.'/users/add', 'action'=>'post', 'autocomplete' => 'off')); ?>
This option => 'autocomplete' => 'off'
Check your $this->data.
CakePHP autocompletes forms with data found there because it guesses that is data already submitted by the user.
In you example, if you have some value in $this->data['User']['birth'] it should show that value in the Birthday input.
I have a simple delete function. Here is where I set the custom data:
<?php echo $this->Html->link(
__('Delete'),
'#CoursesModal',
array(
'class' => 'btn-remove-modal',
'data-toggle' => 'modal',
'role' => 'button',
'data-uid' => $course['Course']['id'],
'data-uname' => $course['Course']['name']
));
?>
It shows in the element fine:
Delete
But when it comes to deleting this object (here's the code for it:)
<?php echo $this->Html->link(__('Delete'),'/courses/delete/#{uid}',array('class' => 'btn btn-danger delete-course-link')) ?>
For some reason the {uid} doesn't translate to 5 - which causes it not to work.
What am I doing wrong?
I am a new cake php developer.I am trying to insert multiple record but i cant.My table Structure is given below:
Table Name :
agents
==============================================
id | Contact | Name | email_add | Address
==============================================
Controller Code :
public function send_money()
{
$this->layout='agent';
$this->Agent->create();
$this->Agent->set($this->data);
if(empty($this->data) == false)
{
if($this->Agent->save($this->data))
{
$this->Session->setFlash('Information Added Successfully.');
$this->redirect('send_money');
}
}
else
{
$this->set('errors', $this->Agent->invalidFields());
}
}
Model Code Is :
<?php
App::uses('AppModel', 'Model');
/**
* Admin Login Model
*
*/
class Agent extends AppModel
{
public $name='Agent';
public $usetables='agents';
public $validate = array(
'contact' => array(
'contact_not_empty' => array(
'rule' => 'notEmpty',
'message' => 'Please Give Contact No',
'last' => true
),
),
'name' =>array(
'rule' => 'notEmpty', // or: array('ruleName', 'param1', 'param2' ...)
'allowEmpty' => false,
'message' => 'Please Enter Name.'
),
'email_add' => array(
'email_add' => array(
'rule' => 'email',
'allowEmpty' => true,
'message' => 'Please Enter Valid Email',
'last' => true
)),
);
}
?>
Its not possible to insert records with this code.What should I do?
Let me explain everything.
First of all your html form must be looks like following.
<?php echo $this->Form->create('User'); ?>
<tr>
<td>
<?php
echo $this->Form->input('User.0.address',array
(
'div' => null,
'label' => false,
'class' => 'span required'
));
?>
<?php
echo $this->Form->input('User.1.address',array
(
'div' => null,
'label' => false,
'class' => 'span required'
));
?>
<?php
echo $this->Form->input('User.2.address',array
(
'div' => null,
'label' => false,
'class' => 'span required'
));
?>
</td>
<td>
<input type="submit" value="Add" >
</td>
</tr>
<?php echo $this->Form->end(); ?>
As you can see to save many record at same time using cakephp you must define it as above it will parse input fields as array this is cakephp convention.
I mean User.0.address for first array element
User.1.address for second array element
User.2.address for third array element and so on.
Now.
In Controller file.
<?php
function add()
{
$this->User->saveAll($this->data['User']);
}
And yes here you are done saving multiple record at same time.
I just gave you how cakephp works all you need to do is set above hint as per your need.
Best of luck...
Cheers...
Feel Free to ask... :)
Try this saveall() in your query except save, hope this helps
if($this->Agent->saveall($this->data))
Let me know if it work.
I think this
php echo $this->Form->create('Agents', array('action' => 'send_money'));?>
should be replaced with
php echo $this->Form->create('Agent', array('action' => 'send_money'));?>
and use saveall() in place of save.