In my php file, this is how i run a bash script file.
$run=popen("/var/www/html/work/bashfile.sh","r");
and inside bashfile.sh i have something like this
#! /bin/bash
cd /var/www/html/work/prepare
./runfile 0.3 180 username
This code works perfect by producing pictures in order username1.jpg, username2.jpg
But when i try to do the same thin by passing variable to the bash script using php it does nor work and this is how i was writing the code
In my php file
$vari="name1";
$run=popen("/var/www/html/work/bashfile2.sh $vari","r");
and inside my bashfile2.sh i do
#! /bin/bash
$vari=$1
cd /var/www/html/work/prepare
./runfile 0.3 180 $vari
But this is not working. Please any idea how to work things around to end up getting the results of the first code
popen() is interpreting your variable as a part of the string you send. Try using {} to enclose your variable when using them directly in strings.
$vari = "name1";
$run = popen("/var/www/html/work/bashfile2.sh {$vari}","r");
Related
I hope you can help me.
I am dealing with a problem that I cannot solve. This is my issue. I am trying to exec a bash script through PHP. I tried with the method
exec()
with 3 arguments, arg1, arg2, and arg3.
php code
<?php exec("./randomScript.sh arg1 arg2 arg3"); ?>
randomScript.sh
.... # random code which exploits the three arguments -> executed normally..
.... # random code which exploits the three arguments -> executed normally..
./secondScript.sh $arg1 $arg2 $arg3 #<- this is the script that is not running (is not even started).
I have tried to change the permission (I've got full permission), change the way I call the randomScript.sh (through absolute path), but nothing occurred. Besides, I tried with:
shell_exec()
method, but nothing changed. Of course, if I run the secondScript.sh via terminal everything works fine.
I cannot understand which is the problem. Could you please help me?
Thanks in advance.
In the inner shell, the arguments are not called like that (because it is invoked by the shell, not by PHP).
./secondScript.sh "$1" "$2" "$3"
or just
./secondScript.sh $*
At this stage, just remember that spaces, quotes, and dollar signs in the arguments you pass must be avoided at all costs (the solution is escaping them, but how to do it exactly is tricky).
You also might want to do instead:
$ret = shell_exec("./randomScript.sh 'arg1' 'arg2' 'arg3' 2>&1");
so that in $ret you might find error messages and output from the inner shell.
You should escape your string command before passing it in exec function, i think it may help you
Escapeshellcmd()
...
$escaped_command = escapeshellcmd("./randomScript.sh arg1 arg2 arg3");
exec($escaped_command);
...
Escapeshellarg()
For system command, i recommand using system
...
$escaped_command = escapeshellarg("./randomScript.sh arg1 arg2 arg3");
system($escaped_command);
...
You also need to make sure that your PHP code does not change working dir, and both shell scripts have execute permissions, and filesystems allows to exec files on it.
I would avoid exec("./script $arg ...");, I would rather specify the interpreter to use and full path to the script like exec("sh /home/user/project/script.sh $arg ...");
I have installed SymPi in the server and from the command line, I am able to execute the following.
python ./sympy-0.7.5/bin/isympy
(this will open a console where I can type mathematical expressions. then the following expression)
1 + 2
(will give 3 as output)
My aim is to do the same from php using shell_exec. I have written a php file as given below, but is not working.
$command = escapeshellcmd('python ./sympy-0.7.5/bin/isympy');
shell_exec($command);
$output = shell_exec('1 + 2');
Can anybody help me to figure out why this is not working?
Please note that the following script works fine which just execute a python script and retrieve the output.
$command = escapeshellcmd('python C:\PythonPrograms\test3.py');
$output = shell_exec($command);
echo $output;
My guess is that the working directory (cwd) of shell_exec is different from the one you're in when you execute it manually.
Your working example specifies a hard path that will work from anywhere. Whereas your not-working example specifies a relative path (./ is the cwd).
Convert your call to isympy to give its full path on disk. Or figure out how to set the cwd of shell_exec.
(If this doesn't solve it, say more than "is not working." What happens? An error? What is the full text of the error?)
Each time you run shell_exec, it opens a completely new instance of the shell.
Edit:
You can pass a command for python to execute like this:
$expression = '1 + 2';
$cmd = 'python -c \'print "%f" % (' . $expression . ')\'';
$output = shell_exec($cmd);
This, admittedly is not using sympy, but for simple mathmatical expressions you may not need to. If you do, you would just need to import the library in the same command, like this: python -c 'import sympy; print "%f" % sympy.sqrt(3)'
I could manage the desired result in a different way.
Created a python script which accepts the expression as the command line argument , execute and display the output.
Call this script from php by passing the expression as the command line argument.
I'm calling a php script using exec and I'm trying to make a simple log.
Currently I have this :
exec("php script.php $options > temp/log.txt");
If I execute once the result is wrote, but if I execute this multiple times it's always replaced by the last call.
Is there a way to just add the output at the end of the .txt, without replacing all the file ?
Thanks
This has nothing to do with php, you are looking for a shell feature:
exec("php script.php $options >> temp/log.txt");
Note the double >> in there. It appends the redirection instead of overwriting the target.
How can I convert/decode html entities of a file's contents (XML) in PHP.
I tried to run this on a command line:
perl -MHTML::Entities -ne 'print decode_entities($_)' /apps/www/mydir/xmlfiles/p34580600.xml >> /apps/www/mydir/xmlfiles/p34580600_1.xml
It works fine running it on command line but when I try to call it within PHP:
system("perl -MHTML::Entities -ne 'print decode_entities($_)' /apps/www/mydir/xmlfiles/p34580600.xml >> /apps/www/mydir/xmlfiles/p34580600_6.xml");
It creates the file but it is empty. I tried to use html_entity_decode but the XML file is just too big. 20megs at least.
Any help or suggestion is greatly appreciated.
Thanks,
try escaping the $ in the system call. It is possible php is looking for a variable $_ since you are using double quotes for the string command.
I'd like to run something like (in myProgram.sh):
java -cp whatever.jar com.my.program $1
within PHP and read the output.
So far I have something like:
$processOrderCommand = 'bash -c "exec nohup setsid /myProgram.sh ' . $arg1 . ' > /dev/null 2>&1 &"';
exec($processOrderCommand);
But what I'd really like is to be able to get the output of the java program within the PHP script and not just execute it as another thread.
How can this be done?
You can do this :
exec($processOrderCommand, $output);
From the documentation :
If the output argument is present, then the specified array will be filled with every line of output from the command. Trailing whitespace, such as \n, is not included in this array. Note that if the array already contains some elements, exec() will append to the end of the array. If you do not want the function to append elements, call unset() on the array before passing it to exec().
For a better control on your execution you can take a look at proc_open()
Resources :
php.net - exec()
php.net - proc_open()
The key is that the classpaths need to be absolute within the shell_exec
PHP script.
Or at least that's the only way I could get it to correctly work. Basically it's almost impossible to tell from environment to environment what the relative directory is that the php script is running the JVM.
As well, it helped to put the absolute path location for java, such as usr/.../bin/java