Add Arrays from database in a json encode [duplicate] - php

Question

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Use PHP to dump mysql values into JSON file
(3 answers)
Closed 6 years ago.
I wanted to add all arrays from my database in one json encode and decode it later on.. but I ran into a thing which I don't know how to fix.
I'm trying to add all arrays from the sql query in one array and then encode that one array with all the arrays inside it.
My current code:
$dbh = new PDO('mysql:host='.$this->server.';dbname='.$this->database.'', $this->user, $this->pass);
$result = array();
foreach($dbh->query('SELECT * from bier') as $row) {
$result[] += $row;
}
print json_encode($result);
Updated code:
function getData()
{
try {
$dbh = new PDO('mysql:host='.$this->server.';dbname='.$this->database.'', $this->user, $this->pass);
$result = array();
foreach($dbh->query('SELECT * from bier') as $row) {
$result[] = $row;
}
$json = json_encode($result, JSON_PRETTY_PRINT);
var_dump($json);
} catch (PDOException $e) {
print "Error!: " . $e->getMessage() . "<br/>";
die();
}
}
Currently returns: Boolean False

Answer 1

In PHP, the += compound operator is used to "add & assign"; however, this does not work as you'd expect for inserting items into an array.
Your code should work if you remove the + from that line as #Rajdeep pointed out.
Here is your code, updated with some changes for clarity:
try
{
$data = new PDO('mysql:host='.$this->server.';dbname='.$this->database.'', $this->user, $this->pass);
$data->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$list = [];
foreach($data->query('SELECT * from bier') as $item)
{ $list[] = $item; }
$json = json_encode($list, JSON_PRETTY_PRINT);
echo $json;
}
catch (PDOException $fail)
{
echo $fail->getMessage();
exit;
}
As you probably notice; the [] = character sequence after a variable name (that is an array) inserts the new item in the array being assigned.
The try --> catch block should indicate if there was a problem.
Here's more info on how to check for errors: http://php.net/manual/en/pdo.connections.php