How to fix the following error in php? - php

Question

I have a two piece of code for Regions and Categories. They are exactly the same. The code for Category works, but "Region" returns the following error:
Fatal error: Call to a member function getRegion() on null in C:\wamp64\www\site\catalog\controller\module\latest.php on line 81
// Region
$product_region = array();
$regions = $this->model_profile_profile->getProductRegions($result['product_id']);
foreach ($regions as $region_id) {
print_r($region_id); // !!! ($region_id = 2) !!! $region_id is not empty !!!
$region_info = $this->model_account_region->getRegion($region_id); // LINE 81
if ($region_info) {
$product_region[] = array(
'name' => ($region_info['path']) ? $region_info['path'] . ' > ' . $region_info['name'] : $category_info['name'],
'href' => $this->url->link('account/profile', '&path=' . $region_info['region_id'])
);
}
}
And here is the code which probably causes the error:
public function getRegion($region_id) {
$query = $this->db->query("SELECT DISTINCT *, (SELECT GROUP_CONCAT(cd1.name ORDER BY level SEPARATOR ' > ') FROM " . DB_PREFIX . "region_path cp LEFT JOIN " . DB_PREFIX . "region_description cd1 ON (cp.path_id = cd1.region_id AND cp.region_id != cp.path_id) WHERE cp.region_id = c.region_id AND cd1.language_id = '" . (int)$this->config->get('config_language_id') . "' GROUP BY cp.region_id) AS path, (SELECT DISTINCT keyword FROM " . DB_PREFIX . "url_alias WHERE query = 'region_id=" . (int)$region_id . "') AS keyword FROM " . DB_PREFIX . "region c LEFT JOIN " . DB_PREFIX . "region_description cd2 ON (c.region_id = cd2.region_id) WHERE c.region_id = '" . (int)$region_id . "' AND cd2.language_id = '" . (int)$this->config->get('config_language_id') . "'");
return $query->row;
}
I'd appreciate if you help me by giving a piece of code, because I'm dummy in PHP.

Answer 1

$this->model_account_region //This property is null
Check
echo 'FILE : '.__FILE__ .'<br/>';
echo 'LINE : '.__LINE__ .'<br/>';
echo '<pre>';
var_dump( empty( $this->model_account_region ) );
echo '</pre>';
exit;

Answer 2

model_account_region model class is messed up. Since you are running out of time. I suggest you copy the function
public function getRegion($region_id) {
$query = $this->db->query("SELECT DISTINCT *, (SELECT GROUP_CONCAT(cd1.name ORDER BY level SEPARATOR ' > ') FROM " . DB_PREFIX . "region_path cp LEFT JOIN " . DB_PREFIX . "region_description cd1 ON (cp.path_id = cd1.region_id AND cp.region_id != cp.path_id) WHERE cp.region_id = c.region_id AND cd1.language_id = '" . (int)$this->config->get('config_language_id') . "' GROUP BY cp.region_id) AS path, (SELECT DISTINCT keyword FROM " . DB_PREFIX . "url_alias WHERE query = 'region_id=" . (int)$region_id . "') AS keyword FROM " . DB_PREFIX . "region c LEFT JOIN " . DB_PREFIX . "region_description cd2 ON (c.region_id = cd2.region_id) WHERE c.region_id = '" . (int)$region_id . "' AND cd2.language_id = '" . (int)$this->config->get('config_language_id') . "'");
return $query->row;
}
into model_profile_profile then call it from there ie
$region_info = $this->model_profile_profile->getRegion($region_id); // LINE 81
if that fails its the db class failing to load properly so you add this line before calling your function on line 81
$this->load->database();
let me know if you are facing more challenges. I am a bit bored over here.