I need to make queries to my partners website, which, after htaccess authentication, force downloads XML file. I then need to save that data into a database.
I tried doing it like this
$context = stream_context_create(array(
'http' => array(
'header' => "Authorization: Basic " . base64_encode("$username:$password")
)
));
$data = file_get_contents($url, false, $context);
but it returns a boolean with the value FALSE.
I havent found any information regarding te getting XML content after forced download
Related
So my client needs a REST API using PHP that provides output as per the conditions on the URL parameters
So now there are three URL's basically which is currently needed and they are done.
so they are
localhost/newapi/client/<AuthKey> - for authorizing
localhost/newapi/client/<clientid>/categories/ - to get all the categories
localhost/newapi/client/<clientid>/categories/<categoryid> - to get all items in a category
used .htaccess for fancy URL
So now he requested that AuthKey need to be added to HTTP header not the URL. So the AuthKey must be passed as header and the rest as URL parameters
So my question is how this can be done. and how to retrieve the AuthKey from the request?
Any tutorials or comments regarding this question is welcome
you can tell the client when he request your api he add a header as below:
AuthKey: your-api-auth-key
or
Token: your-api-token
and then in your php code make
$headers = getallheaders();
$token = $headers['Token'] or ['AuthKey'];
then you check if the key in database and then process your code
Note:
your client can add Header with PHP cURL
curl_setopt($curl-handle, CURLOPT_HEADER, array(
'Token' => 'client-auth-token', //or
'AuthKey' => 'client-auth-token'
));
you can use this code to connect with rest in php
$url = 'localhost/newapi/client/';
$opts = array('http' =>
array(
'method' => 'POST',
'header' => "Content-Type: application/json\r\n"."Authorization: Basic ".<authkey>."\r\n",
'content' => $data,
'timeout' => 60
)
);
$context = stream_context_create($opts);
$result = file_get_contents($url, false, $context, -1, 40000);
return $result;
I am trying to call a web service which basicaly looks like this:
http://10.10.10.10:8080/gw/someAction?amount=10&description='Some description'
So this is how i call this web service:
$endpoint = "http://10.10.10.10:8080/gw/someAction?amount=10&description='Some description'";
$opts = array('http' =>
array(
'method' => 'GET',
'header' => 'Content-type: application/xml'
)
);
$context = stream_context_create( $opts );
$result = file_get_contents( $endpoint, false, $context );
$xml_result = simplexml_load_string( $result );
echo $xml_result->success;
So here, i got nothing, the xml_result is empty. And here is the interesting part - when i remove the blank space from the description:
http://10.10.10.10:8080/gw/someAction?amount=10&description='Somedescription'
Everything is just fine, I got the answer from the web service. Also tried to call the web service with the chrome rest client WITH the blank space in the description and everything is OK, i have response. So this leads me to some kind of PHP problem here with the blank spaces in the web service. Please, help !
UPDATE:
print_r($result)
results in
1
This is not a valid URL, spaces must be escaped:
http://10.10.10.10:8080/gw/someAction?amount=10&description='Some%20description'
You might want to take a look at How to properly URL encode a string in PHP?.
I have the following code:
<?php
$ids = 'ids=com.hugogames.hugotrollwars';
$opts = array('http' =>
array(
'method' => 'POST',
'header' => 'Content-type: application/x-www-form-urlencoded',
'content' => $ids
)
);
$context = stream_context_create($opts);
$result = file_get_contents('https://play.google.com/store/xhr/getdoc', false,
$context);
$convert = explode("\n", $result);
Basically its pulling permissions from the Playstore and displaying it as a string. The issue I am having is removing the un needed data (image links, description) and only show the permissions and the permissions description. I tried using the json_decode function with php and it returned NULL.
Is there something i'm missing?
Any help is greatly appreciated!
$result is not valid json. Google Play API is using a protobuf variant.
http://www.segmentationfault.fr/publications/reversing-google-play-and-micro-protobuf-applications/
There are also php libraries to talk to google play.
https://github.com/splitfeed/android-market-api-php
https://github.com/thetutlage/Google-Play-Store-API
I'm retrieving a PHP file using file_get_content(), cURL() or fopen() all return PHP code itself. It's not retrieving just the HTML code itself that PHP is outputting. How can I overcome this please?
It's basically generating an HTML newsletter preview for my customer that is generated from their CMS. However I want them to be able to copy and paste the HTML it generates into Mailchimp or such like. It just fetches the entire PHP source code though as well as the HTML :(
Hope you can help.
Thanks in anticipation.
Pete
Trying to read a local PHP file will return its source code, since its a "local" file, and is not parsed by the server.
If you wish to read the result of the PHP file you must request it from the server.
Meaning instead of doing:
$data = file_get_contents('x.php');
You should be doing
$data = file_get_contents('http://mysite.com/path/x.php');
Which will be parsed in the server, and then returned to you.
Cheers! :)
Shai.
This will work in localhost. Try this one: $url = "http://localhost/box.php";
function isAllBoxContents($boxid,$pageNum)
{
$postdata = http_build_query( array('myBoxid' => "$boxid", 'isAllBoxContents' => "all",'pageNum' => "$pageNum",'innerReq' => true ));
$opts = array('http' => array( 'method' => 'POST', 'header' => 'Content-type: application/x-www-form-urlencoded', 'content' => $postdata ));
$context = stream_context_create($opts);
$url = "http://localhost/box.php";
$result = file_get_contents( $url, false, $context);
$cacheFileName = "isAllBoxContents".$boxid.$pageNum;
cacheMe($cacheFileName,$result);
}
$post_data = array(
'url' => $all[2],
'op' => 'sv',
'sid' => 1
);
// Send a request to example.com
$result = post_request('http://www.yahoo.com', $post_data);
function PostRequest($url) {
$opts = array('http' =>
array(
'method' => 'GET',
'header' => "Content-type: application/x-www-form-urlencoded\r\n"."Accept-language: en\r\n" .
"Cookie: member_id=8593099\r\n" .
"Cookie: pass_hash=fad917fe75e1059f85fc6d9bb6f7a19f\r\n".
"Cookie: session_id=279fe56fd87e5371dc7e1c9f66c27522"
)
);
$context = stream_context_create($opts);
$result = file_get_contents($url, false, $context);
return $result;
}
I am able to send the request, but my action needs login to be performed.
Even once I'm logged in, it classifies me as not logged in.
I'm using localhost to send out the request. Is that because of the different domain?
I already copied the login cookies for my localhost, but it is still not working.
Any ideas?
What I tried to do is send http request with php.
My request has sent out, but my destination cannot detect cookies, and claim I am not login.
I'm not too sure what you're trying to accomplish, as the code you've posted isn't quite clear. post_request() isn't a native PHP-function, so you'd have to give us a sample of it for us to be able to help you further.
I would however recommend that you've check that you've put session_start(); way up top in your PHP-files - it ensures that you're able to access the session/cookie.