i have a div and also on same page i have some data which is show on web page i just want data show on div how can i do this? i am very very new in php .thanks here is the php file.
<?php
define('HOST','xxxxxxxxxxx');
define('USER','xxxxxxxxxxxxx');
define('PASS','xxxxxxxx');
define('DB','androidapi2');
$con = mysqli_connect(HOST,USER,PASS,DB);
$sql = "select * from users WHERE status = 1";
$res = mysqli_query($con,$sql);
$result = array();
while($row = mysqli_fetch_array($res)){
array_push($result,
array(
// 'id'=>$row[0],
'email'=>$row[3],
));
}
echo json_encode(array("result"=>$result));
mysqli_close($con);
?>
<html>
<head>
<title>DIC ChatBox Beta 1</title>
<style>
#usersOnLine {
font-family:tahoma;
font-size:12px;
color:black;
border: 3px teal solid;
height: 525px;
width: 250px;
float: right;
overflow-y:scroll;
}
.container{
width:970px;
height:auto;
margin:0 auto;
}
</style>
</head>
<body>
<div class="container">
</div>
<h2> all contacts</h2>
<div id="usersOnLine">
</div>
</div>
</body>
</html>
here is the div id usersonline where i want all data show . how to made it.
There is no need to use json_encode(array("result"=>$result));, directly use $result
<div id="usersOnLine">
<?php
foreach($result as $key => $val)
{
echo $val['email'];
echo "<br>";
}
?>
</div>
If you want to use it on another page
Creating New Session In php file
<?php
session_start(); ///at the top of this file
///after your query and creating array
$_SESSION["result"]= $result;////set $result in session
?>
Getting Session on another page
<?php
session_start();
if(isset($_SESSION["result"]))
{
$result = $_SESSION["result"];
///your foreach loop to print data
}
?>
READ SESSION DOCUMENTAION
Related
I want my page to automatically redirect to another page when the data is fetch on the page so how can I do it ? i have this code
here is my code here is where the data is fetched but once it fetch i want to redirect it automatically.
<div>
<?php
$data = mysqli_query($con,"SELECT * FROM announcement");
$count = mysqli_num_rows($data);
if ($count != 0) {
//IVE ASSUMED THAT THIS WILL WORK BUT IT DIDNT
header("location:../addRedirect.php");
while($row = mysqli_fetch_array($data)) {
echo '<div id="myModal" class="modal" style="position:fixed; display: none; padding-top: 100px;
left: 0; top: 0; width: 100%; height: 100%; overflow: auto; background-color: rgb(0,0,0); background-color: rgba(0,0,0,0.9); ">
<div class="container" style="width: 100%">
<div class="card col-12" style="background-color: red; color: white;">
<div class="card-header">
<p><h3 class="text-center">Announcement</h3></p>
</div>
<div class="card-body text-center">
<h5>'.$row['additional_info'].'</h5>
<p>Please click refresh button to resume after the announcement</p>
</div>
</div>
</div>
<img class="modal-content" id="img01">
</div>';
$dataid = $row['id'];
}
}
?>
</div>
and on my second page i want to redirect it back.. so what i have is an auto refresh when im just fetching data.. thanks guide me pls this is a huge help for me as a starter of php and codings thanks.
<?php
header("location:../home.php");
?>
You can refresh your page using javascript instead of PHP, if the headers are already set.
<div>
<?php
$data = mysqli_query($con,"SELECT * FROM announcement");
$count = mysqli_num_rows($data);
if ($count != 0) {
echo "<script>setTimeout(\"location.reload()\",1000);</script>";
// Other stuff ...
}
?>
</div>
If you want to navigate to an other page you can do this:
<div>
<?php
$data = mysqli_query($con,"SELECT * FROM announcement");
$count = mysqli_num_rows($data);
if ($count != 0) {
echo "<script>setTimeout(\"location.href = '../addRedirect.php';\",1000);</script>";
// Other stuff ...
}
?>
</div>
Both examples have a delay of 1 second (1000 milliseconds)
Following is the table i created for displaying the Restaurant Name, Location and Menu for table owners.
Now each of the row for the column Menu have Button as values.
My table is ready with perfect values.
NOW MY PROBLEM IS HOW TO DO:-
Upon clicking the button corresponding to the each Restaurant, a new File(openmenu.php) will open and will echo the Restaurant Name, Mobile Number of that Restaurant and the menu.
But so far, on clicking every Button ,I can only display above entries of the Last row of the table. Help Me Out. I am new to php.
table.php
<?php
include 'nav.php';
$sql = 'SELECT * FROM owners';
$query = mysqli_query($con, $sql);
if (!$query) {
die ('SQL Error: ' . mysqli_error($con));
}
?>
<html>
<head>
<link rel = "stylesheet" type = "text/css" href = "css/style.css">
<style>
.data-table{
width: 1024px;
margin-left: 150px;
text-align:center;
border: 1px solid firebrick;
background-color: white;
}
td,th{
border: 1px solid firebrick; padding: 3px 2px 1px 1px;
}
</style>
</head>
<body>
<div class="container">
<article>
<table class="data-table">
<thead>
<tr>
<th>Restuarant Name</th>
<th>Location</th>
<th>Menu</th>
</tr>
<tr>
</tr>
</thead>
<tbody>
<?php
while ($row = mysqli_fetch_array($query)){
$_SESSION['resphone'] = $row['resphone'];
$_SESSION['restaur'] = $row['restaur'];
echo '<tr>
<td>'.$row['restaur'].'</td>
<td>'.$row['loc'].'</td>
<td style="background-color:firebrick;"><form method="post" action="openmenu.php?id=$row[restaur]"><input value="<?php echo $restaur;?>" type="hidden">
<input type="submit" value="View"></form></td>
</tr>';
}
?>
</tbody>
</table>
</form>
</article>
</div>
</body>
</html>
openmenu.php
<?php
include('nav.php');
?>
<html>
<head>
<link rel="stylesheet" href="css/style.css">
<style>
table, td {
border: none;
text-align: center;
text-align-last: center;
}
</style>
</head>
<body>
<div class="container">
<article>
<form method="get" align="center" action="" class="formwrap" enctype='multipart/form-data'>
<h1><?php $restaur = $_SESSION['restaur'];
echo $restaur ;?></h1>
<h1>Call to Order:</h1>
<?php $resphone = $_SESSION['resphone'];
echo $resphone;
?>
<br>
<br>
<?php
$sql = "select img from owners where restaur ='$restaur'";
$result = mysqli_query($con,$sql);
$row = mysqli_fetch_array($result);
$image_src2 = "upload/".$row['img'];
?>
<img src='<?php echo $image_src2; ?>' >
</form>
</article>
</div>
</body>
</html>
Issue 1
In this snippet you are setting the session variables resphone and restaur to the values of the store you are currently iterating over. Over and over again. That's why you're only ever getting the last store's information - it's the last things you set those variables to.
while ($row = mysqli_fetch_array($query)){
$_SESSION['resphone'] = $row['resphone'];
$_SESSION['restaur'] = $row['restaur'];
Issue 2
You should probably change the form method to get and discard the unused hidden input like so:
<form method="post" action="openmenu.php?id=<?=$row['restaur']?>">
<input type="submit" value="View">
</form>
Or more likely just change it a plain old a link:
View
Issue 3
You're completely ignoring store id requested in openmenu.php. You are using $_SESSION where you should be using $_REQUEST or $_GET. I'm not going to give an example of how you should do that. Instead, please refer to this answer before moving any further.
first you getting data from database & then use view button for openmenu.php but why u use this way
<form method="post" action="openmenu.php?id=$row[restaur]"><input value="<?php echo $restaur;?>" type="hidden"><input type="submit" value="View"></form>
my problem is that i cant seem to call any kind of information that is stored in my database. I want to call everything in the order that it is in the database(name of the product, image and price. Here is the code for my index.php
Here you can view how my webpage looks so far:
Here you can view the data that is in my database:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Add to Cart</title>
<?php
$mysqli = new mysqli("localhost", "id3764036_alan", "agro12345", "id3764036_agrotienda");
?>
<link rel="stylesheet" href="style.css" type="text/css">
<link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/font-awesome/4.6.3/css/font-awesome.min.css">
<link href="https://fonts.googleapis.com/css?family=Roboto+Condensed|Rubik" rel="stylesheet">
<style>
a{text-decoration:none; color:inherit}
#undr{width:100%; height:580px; position:absolute; top:75px; left:0px;}
.bdimg{width:100%; height:100%}
#lowrbdy{ position:absolute; top:90px; left:0px;width:100%; height:100px}
.outer{width:270px; height:270px; background:rgba(255,255,255,0.8); float:left; margin-left:55px; margin-bottom:10px}
.imgdv{width:100px;height:140px;margin:10px auto;}
.imgdv img{width:100%; height:100%}
.pname{ text-align:center; width:100%; height:20px; font-size:15px; margin-top:-14px; margin-bottom:10px}
.prs{ text-align:center; font-size:24px; margin:0px}
.butndv{width:140px; height:40px; margin:auto; margin-top:-10px}
.butn{width:100%; height:100%; background:rgba(78,172,240,1.00); border:none; color:#fff; font-size:18px; border-radius:6px}
.outer:hover{ background:#fff}
.outer:hover .butn{ background:#4A7FDC; transition:all 0.2s ease-in-out; cursor:pointer}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
</head>
<body>
<header>
<?php
include('head.php');
?>
</header>
<div id="undr">
<img class="bdimg" src="bg.jpg">
</div>
<div id="lowrbdy">
<?php
$select_query="";
$sql = mysqli_query($mysqli,'SELECT * FROM `product`');
while ($row = $sql->fetch_row())
{
?>
<a href="view.php?product=<?=$row["id"]?>">
<div class="outer">
<div class="imgdv"><img src="carrillo/imeg/<?=$row["pro_image"]?>"/></div>
</div>
</a>
<?php
}
?>
</div>
</body>
</html>
Change fetch_row() to fetch_assoc(). If you use fetch_row(), the $row variable will contain array with numerical indexes. With fetch_assoc(), the $row variable will store an associative array with column names as the indexes.
Try Using prepared statement
<?php
$select_query="";
// $sql = mysqli_query($mysqli,'SELECT * FROM `product`');
$sql="SELECT id, pro_image,name,price FROM product";
if ($stmt = $conn->prepare($sql)) {
$stmt->execute();
$stmt->bind_result($id, $pro_image, $name);
while ($stmt->fetch()) {
?>
<a href="view.php?product=<?php echo $id;?>">
<div class="outer">
<div class="imgdv"><img src="carrillo/imeg/<?php echo $p_image;?>"/></div>
</div>
</a>
<?php
}
}?>
You can also try with MySQLi Procedural
You have to use mysqli_fetch_assoc instated of fetch_row
$sql = "SELECT * FROM `products`";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
?>
<a href="view.php?product=<?php echo $row["id"];?>">
<div class="outer">
<div class="imgdv"><img src="carrillo/imeg/<?php echo $row["pro_image"];?>"/></div>
</div>
</a>
<?php
}
}
else {
echo "0 results";
}
mysqli_close($conn);
?>
Here's what I'm basically trying to do:
Retrieve the values of a column
Store those values into an array in PHP
Echo each value with a line break in between each value
Here's my attempted code:
<?php
$connection = mysqli_connect("localhost", "root", "bruhfrogzombie098", "growtapi_social");
if (!$connection) {
die("Failed to connect to MYSQL: " . mysqli_connect_errno());
};
$members = mysqli_query($connection, "SELECT Username FROM s_users");
$members_status = mysqli_query($connection, "SELECT Status_Content FROM s_users");
$members_array = array();
while ($member = mysqli_fetch_assoc($members)) {
$members_array[] = $member;
};
$members_status_array = array();
while ($status = mysqli_fetch_assoc($members_status)) {
$members_status_array[] = $status;
};
?>
And this is where I want to echo out the values:
<center>
<h1>Members Directory</h1>
<div style="width: 20%; height; 75%; border: 3px solid black; margin: auto; overflow: hidden; overflow-y: scroll;">
<?php echo $members_array['$member'];
echo "<br />";
?>
</div>
</center>
I don't receive any errors, but the problem is that nothing shows up in the div, meaning that I either didn't retrieve the data properly or didn't use it right.
Note: I've finally moved on to writing up-to-date code, so I hope no one here comments that somewhere in this code I have outdated code ( ͡° ͜ʖ ͡°)
$members_array = array();
while ($member = mysqli_fetch_assoc($members)) {
$members_array[] = $member;
//$members_array is array and $member is array so $members_array like $members_array[][];
};
<center>
<h1>Members Directory</h1>
<div style="width: 20%; height; 75%; border: 3px solid black; margin: auto; overflow: hidden; overflow-y: scroll;">
<?
$member_count = count($members_array);
for( $i = 0 ; $i < $member_count ; $i++ ){
echo $member_array[$i]['Username'];
echo "<br />";
}
?>
</div>
</center>
I have this structure on my page:
*{
margin: 0px;
}
.div1{
width: 1000px;
background-color: grey;
overflow: hidden;
}
.div2{
width: 300px;
background-color: orange;
height: 500px
}
.div3{
width: 300px;
background-color: orange;
height: 500px;
}
.float_left{
float: left;
}
.float_right{
float: right;
}
<div class="div1">
<div class="div2 float_left">
</div>
<div class="div3 float_right">
</div>
</div>
And inside the two orange container's I want to put some smaller divs, but I read the data from a database. The first row should be in div1, the second in div2, the third in div1 and so on.
$sql = "SELECT * FROM question ORDER BY question_id DESC";
$result = mysqli_query($db,$sql);
while($row = mysqli_fetch_assoc($result)){
}
But how can I do something like that? Can I open a div container closed container to place a div container inside the container?
You should really read and try by yourself, this is pretty basic question.
There are many ways, here is one of them.
Declare 2 variables to store the results for Div1 and Div2.
Declare a count variable and use the odd and even property to decide who turn is it to store the results.
Output the results.
PHP:
$sql = "SELECT * FROM question ORDER BY question_id DESC";
$result = mysqli_query($db,$sql);
$resultsForDiv1 = "";
$resultsForDiv2 = "";
$count = 0;
while($row = mysqli_fetch_assoc($result)){
if ($count%2 == 0) {
$resultsForDiv1 .= $row[0]; // You should change it to whatever data you need from $row.
}
else {
$resultsForDiv2 .= $row[0]; // You should change it to whatever data you need from $row.
}
$count++;
}
Html:
<div class="div1">
<div class="div2 float_left">
<?php echo $resultsForDiv1; ?>
</div>
<div class="div3 float_right">
<?php echo $resultsForDiv2; ?>
</div>
</div>
What you should do is store the data from the $row variable into new variables which you can then output in the two columns. Like this:
<?php
$sql = "SELECT * FROM question ORDER BY question_id DESC";
$result = mysqli_query($db, $sql);
// Use this to toggle column on the sql results
$left_right = true;
while ($row = mysqli_fetch_assoc($result)) {
if ($left_right) {
// Add to left column variable
// [some code to add the data from $row to $left_column_content]
} else {
// Add to right column variable
// [some code to add the data from $row to $right_column_content]
}
// Switch columns by inverting the boolean from true to false, false to true
$left_right = !$left_right;
}
?>
<div class="div1">
<div class="div2 float_left">
<?php echo $left_column_content; ?>
</div>
<div class="div3 float_right">
<?php echo right_column_content; ?>
</div>
</div>