How to hide form_dropdown in codeigniter - php

I want to hide form drop down after second selection, because that second combo box it already selected in earlier. Currently i make it to be like this.
$data['year'] = NULL;
but what i need is that variable is disappear after is selected the dropdown 1.
Below is my code.
Controller
function carbyyear() {
$arrCaryear = $this->modelRegister->loadcaryear();
$arrcaryear[''] = 'Please Select';
foreach ($arrCaryear as $caryears) {
$arrcaryear[$caryears->year] = $caryears->year;
}
$data['year'] = $arrcaryear;
$this->load->view('abc',$data);
}
function ajax_car_make() {
if (isset($_POST) && isset($_POST['year'])) {
$year = $_POST['year'];
$arrMakes = $this->modelRegister->loadcarmake($year);
//print_r($arrModels);
$arrmakes[''] = 'Please Select';
foreach ($arrMakes as $makes) {
$arrmakes[$makes->make] = $makes->make;
}
print form_dropdown('make',$arrmakes);
$data['year'] = NULL;
$this->load->view('abc',$data);
} else {
redirect('site');
}
}
function ajax_car_model() {
if (isset($_POST) && isset($_POST['make'])) {
$make = $_POST['make'];
$arrModels = $this->modelRegister->loadmodelfrombrand($make);
//print_r($arrModels);
$arrmodels[''] = 'Please Select';
foreach ($arrModels as $models) {
$arrmodels[$models->model] = $models->model;
}
print form_dropdown('model',$arrmodels);
} else {
redirect('site');
}
}
View
<body>
<div id="container">
<div id="body">
<article>
<table style="margin:0 auto;width:50%" >
<tr>
<td align="center" height="50">
<div id="yearcombox">
<?php
$js = 'id="year" onChange="showMake(this);;"';
echo form_dropdown('year',$year);
?>
</div>
</td>
</tr>
<tr>
<td align="center" height="50"><div id="makecombox"></div> </td>
</tr>
<tr>
<td align="center" height="50"><div id="modelcombox"></div> </td>
</tr>
</table>
</article>
</div>
</div>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>
$(document).ready(function () {
$('#yearcombox select').change(function () {
var selYear = $(this).val();
console.log(selYear);
$.ajax({
url: "ajax_car_make",
async: false,
type: "POST",
data: "year="+selYear,
dataType: "html",
beforeSend: function(data) {
$('#makecombox').html('<img src="<?php echo base_url(); ?>/template/images/loader.gif" alt="" width="24" height="24">');
},
success: function(data) {
$('#makecombox').html(data);
},
})
});
});
$(document).ready(function () {
$('#makecombox select').change(function () {
var selMake = $(this).val();
console.log(selMake);
$.ajax({
url: "ajax_car_model",
async: false,
type: "POST",
data: "make="+selMake,
dataType: "html",
beforeSend: function(data) {
$('#modelcombox').html('<img src="<?php echo base_url(); ?>/template/images/loader.gif" alt="" width="24" height="24">');
},
success: function(data) {
$('#modelcombox').html(data);
},
})
});
});
</script>
</body>

No need to load view in ajax response
function ajax_car_make()
{
if (isset($_POST) && isset($_POST['year'])) {
$year = $_POST['year'];
$arrMakes = $this->modelRegister->loadcarmake($year);
//print_r($arrModels);
$arrmakes[''] = 'Please Select';
foreach ($arrMakes as $makes) {
$arrmakes[$makes->make] = $makes->make;
}
echo form_dropdown('make',$arrmakes);
} else {
echo false;
}
}
Change $('#makecombox select').change(function () {
to
$('body').on('change','#makecombox select',function () {

Related

No Data Message Show

this code,i have done searching through enroll number. All code are correct and running properly but when match data are not found. No message shown .so, i want to show a message when match data are not found like that "No Such Data Found".
How can i do this? please help to solve that problem,
My code is below.
index.php
<!DOCTYPE html>
<html>
<head>
<title>How to return JSON Data from PHP Script using Ajax Jquery</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<style>
#result {
position: absolute;
width: 100%;
max-width:870px;
cursor: pointer;
overflow-y: auto;
max-height: 400px;
box-sizing: border-box;
z-index: 1001;
}
.link-class:hover{
background-color:#f1f1f1;
}
</style>
</head>
<body>
<br /><br />
<div class="container" style="width:900px;">
<h2 align="center">How to return JSON Data from PHP Script using Ajax Jquery</h2>
<h3 align="center">Search Employee Data</h3><br />
<div class="row">
<div class="col-md-4">
<input type="text" name="employee_list" id="employee_list" class="form-control">
</div>
<div class="col-md-4">
<button type="button" name="search" id="search" class="btn btn-info">Search</button>
</div>
</div>
<br />
<div class="table-responsive" id="employee_details" style="display:none">
<table class="table table-bordered">
<tr>
<td width="10%" align="right"><b>Name</b></td>
<td width="90%"><span id="name"></span></td>
</tr>
<tr>
<td width="10%" align="right"><b>Address</b></td>
<td width="90%"><span id="address"></span></td>
</tr>
<tr>
<td width="10%" align="right"><b>Gender</b></td>
<td width="90%"><span id="total_marks"></span></td>
</tr>
<tr>
<td width="10%" align="right"><b>Designation</b></td>
<td width="90%"><span id="email"></span></td>
</tr>
<tr>
<td width="10%" align="right"><b>Age</b></td>
<td width="90%"><span id="ph"></span></td>
</tr>
</table>
</div>
</div>
</body>
</html>
<script>
$(document).ready(function(){
$('#search').click(function(){
var enroll= $('#employee_list').val();
if(enroll != '')
{
$.ajax({
url:"fetch.php",
method:"POST",
data:{enroll:enroll},
dataType:"JSON",
success:function(data)
{
if(data.length != 0){
$('#employee_details').css("display", "block");
$('#name').text(data.name);
$('#address').text(data.address);
$('#total_marks').text(data.total_marks);
$('#ph').text(data.ph);
$('#email').text(data.email);
}
else { alert("Please Select Employee"); }
}
})
}
else
{
alert("Please Select Employee");
$('#employee_details').css("display", "none");
}
});
});
</script>
fetch.php
<?php
//fetch.php
if(isset($_POST["enroll"]))
{
$connect = mysqli_connect("localhost", "root", "", "aviation");
$query = "SELECT * FROM student WHERE enroll = '".$_POST["enroll"]."'";
$result = mysqli_query($connect, $query);
if(mysqli_num_rows($result)>0)
{
while($row = mysqli_fetch_array($result))
{
$data["name"] = $row["name"];
$data["address"] = $row["address"];
$data["total_marks"] = $row["total_marks"];
$data["email"] = $row["email"];
$data["ph"] = $row["ph"];
}
echo json_encode($data);
}
}
?>
In your PHP code, you seam to use a loop to fetch database rows. But your PHP Code acts like you only receive 1 row on data.
Ill consider for the moment that you only will get 1 row of data unless you specify otherwise.
You already check if mysql returns 1 or more results.
So, all we need is a variable that tells you if a results has been found.
Example:
<?php
$output = array(
'result' => 0
);
if (isset($_POST["enroll"])) {
$connect = mysqli_connect("localhost", "root", "", "aviation");
$query = "SELECT name,address,total_marks,email,ph FROM student WHERE enroll = '" . $_POST["enroll"] . "'";
$result = mysqli_query($connect, $query);
if (mysql_num_rows($result) == 1) {
$output['row'] = mysqli_fetch_array($result);
$output['result'] = 1;
}
}
echo json_encode($output);
Then, if your javascript code, you only have to test if the data.result is equal to 1 or 0 and act accordingly. Example:
<script>
$(document).ready(function () {
$('#search').click(function () {
var enroll = $('#employee_list').val();
if (enroll != '')
{
$.ajax({
url: "fetch.php",
method: "POST",
data: {enroll: enroll},
dataType: "JSON",
success: function (data)
{
if(data.result == 1){
$('#employee_details').css("display", "block");
$('#name').text(data.row.name);
$('#address').text(data.row.address);
$('#total_marks').text(data.row.total_marks);
$('#ph').text(data.row.ph);
$('#email').text(data.row.email);
}
else{
alert("No Such Data Found");
}
}
})
} else
{
alert("Please Select Employee");
$('#employee_details').css("display", "none");
}
});
});
</script>
Edit: be carefull, you should also sanitise the POST variable before using it in your mysql query
you could just add
error: function(){
alert('No Such Data Found!');
}
after the success:function(data)
so your ajax call would be like :
$.ajax({
url:"fetch.php",
method:"POST",
data:{enroll:enroll},
dataType:"JSON",
success:function(data)
{
if ($.trim(data)){
$('#employee_details').css("display", "block");
$('#name').text(data.name);
$('#address').text(data.address);
$('#total_marks').text(data.total_marks);
$('#ph').text(data.ph);
$('#email').text(data.email);}
else{alert('No Such Data Found!')}
},
error: function(){
alert('error !');
}
or add an else in your php code that return a false if result is empty :
if(mysql_num_rows($result)>0)
{
while($row = mysqli_fetch_array($result))
{
//code ......
}
echo json_encode($data);
}else {
return false;
}
then your ajax call would be like :
$.ajax({
url:"fetch.php",
method:"POST",
data:{enroll:enroll},
dataType:"JSON",
success:function(data)
{
if(data != false){
$('#employee_details').css("display", "block");
$('#name').text(data.name);
$('#address').text(data.address);
$('#total_marks').text(data.total_marks);
$('#ph').text(data.ph);
$('#email').text(data.email);}else{alert('No Such Data Found!');}
}

codeigniter ajax cart update quantity

I am new to codeigniter and ajax. I can add item to cart and remove it as well. but when i am trying to update the quantity of the first row it works fine. but if i change the quantity of other rows and when i leave the mouse it updates the price * quanity, but it wont take the quantity what we enterd instead it takes the value of the first row quantity. can anyone please help me out.
view file :
<html>
<head>
<title>Codeigniter Shopping Cart with Ajax JQuery</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
</head>
<body>
<div class="container">
<br /><br />
<div class="col-lg-6 col-md-6">
<div class="table-responsive">
<h3 align="center">Codeigniter Shopping Cart with Ajax JQuery</h3><br />
<?php
foreach($product as $row)
{
echo '
<div class="col-md-4" style="padding:16px; background-color:#f1f1f1; border:1px solid #ccc; margin-bottom:16px; height:400px" align="center">
<img src="'.base_url().'images/'.$row->product_image.'" class="img-thumbnail" /><br />
<h4>'.$row->product_name.'</h4>
<h3 class="text-danger">$'.$row->product_price.'</h3>
<input type="text" name="quantity" class="form-control quantity" id="'.$row->product_id.'" /><br />
<button type="button" name="add_cart" class="btn btn-success add_cart" data-productname="'.$row->product_name.'" data-price="'.$row->product_price.'" data-productid="'.$row->product_id.'" />Add to Cart</button>
</div>
';
}
?>
</div>
</div>
<div class="col-lg-6 col-md-6">
<div id="cart_details">
<h3 align="center">Cart is Empty</h3>
</div>
</div>
</div>
</body>
</html>
<script>
$(document).ready(function(){
$('.add_cart').click(function(){
var product_id = $(this).data("productid");
var product_name = $(this).data("productname");
var product_price = $(this).data("price");
var quantity = $('#' + product_id).val();
if(quantity != '' && quantity > 0)
{
$.ajax({
url:"<?php echo base_url(); ?>shopping_cart/add",
method:"POST",
data:{product_id:product_id, product_name:product_name, product_price:product_price, quantity:quantity},
success:function(data)
{
alert("Product Added into Cart");
$('#cart_details').html(data);
$('#' + product_id).val('');
}
});
}
else
{
alert("Please Enter quantity");
}
});
$('#cart_details').load("<?php echo base_url(); ?>shopping_cart/load");
// $(document).ready(function(){
// $("input").blur(function(e){
// e.preventDefault();
// }).blur(function() {
// alert("opo");
// });
// });
$(document).on('mouseleave', '#myqty', function(){
var rowid = $(this).attr("class");
var product_price = $(this).attr("title");
//var proqty = $('#myqty').val();
var fieldId = $(this).attr("class");
var proqty = $('#myqty').val();
alert(proqty);
$.ajax({
url:"<?php echo base_url();?>shopping_cart/update",
method:"POST",
data : {rowid:rowid,proqty:proqty,product_price:product_price},
//data: "rowid="+rowid+"&proqty="+proqty+"&product_price="+product_price,
success:function(data)
{
$('#cart_details').html(data);
}
});
});
$(document).on('click', '.remove_inventory', function(){
var row_id = $(this).attr("id");
if(confirm("Are you sure you want to remove this?"))
{
$.ajax({
url:"<?php echo base_url(); ?>shopping_cart/remove",
method:"POST",
data:{row_id:row_id},
success:function(data)
{
alert("Product removed from Cart");
$('#cart_details').html(data);
}
});
}
else
{
return false;
}
});
$(document).on('click', '#clear_cart', function(){
if(confirm("Are you sure you want to clear cart?"))
{
$.ajax({
url:"<?php echo base_url(); ?>shopping_cart/clear",
success:function(data)
{
alert("Your cart has been clear...");
$('#cart_details').html(data);
}
});
}
else
{
return false;
}
});
});
</script>
controller file :
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Shopping_cart extends CI_Controller {
function index()
{
$this->load->model("shopping_cart_model");
$data["product"] = $this->shopping_cart_model->fetch_all();
$this->load->view("shopping_cart", $data);
}
function add()
{
$this->load->library("cart");
$data = array(
"id" => $_POST["product_id"],
"name" => $_POST["product_name"],
"qty" => $_POST["quantity"],
"price" => $_POST["product_price"]
);
$this->cart->insert($data); //return rowid
echo $this->view();
}
function load()
{
echo $this->view();
}
function remove()
{
$this->load->library("cart");
$row_id = $_POST["row_id"];
$data = array(
'rowid' => $row_id,
'qty' => 0
);
$this->cart->update($data);
echo $this->view();
}
function clear()
{
$this->load->library("cart");
$this->cart->destroy();
echo $this->view();
}
function view()
{
$this->load->library("cart");
$output = '';
$output .= '
<h3>Shopping Cart</h3><br />
';
echo count($this->cart->contents());
$output .= '
<div class="table-responsive">
<div align="right">
<button type="button" id="clear_cart" class="btn btn-warning">Clear Cart</button>
</div>
<br />
<table class="table table-bordered">
<tr>
<th width="40%">Name</th>
<th width="15%">Quantity</th>
<th width="15%">Price</th>
<th width="15%">Total</th>
<th width="15%">Action</th>
</tr>
';
$count = 0;
foreach($this->cart->contents() as $items)
{
$count++;
$output .= '
<tr>
<td>'.$items["name"].'</td>
<td><input id="myqty" title="'.$items["price"].'" class="'.$items['rowid'].'" type="number" min="1" value="'.$items['qty'].'">
</td>
<td><span id='.$items["price"].'>'.$items["price"].'</span></td>
<td>'.$items["subtotal"].'</td>
<td><button type="button" name="remove" class="btn btn-danger btn-xs remove_inventory" id="'.$items["rowid"].'">Remove</button></td>
</tr>
';
}
$output .= '
<tr>
<td colspan="4" align="right">Total</td>
<td><span>'.$this->cart->total().'</span></td>
</tr>
</table>
</div>
';
if($count == 0)
{
$output = '<h3 align="center">Cart is Empty</h3>';
}
return $output;
}
function update(){
$this->load->library("cart");
// Recieve post values,calcute them and update
$rowid = $_POST['rowid'];
$price = $_POST['product_price'];
$qty = $_POST['proqty'];
$data = array(
'rowid' => $rowid,
'price' => $price,
'qty' => $qty
);
$this->cart->update($data);
echo $this->view();
}
}
<input class="qty_set" name="quantity" data-rowid="your rowid" type="number" value="5">
this will not work "quantity = document.getElementById ("qty_set"). value;"
// use this var quantity = $(this).val();
$(document).on('change', '.qty_set', function(){
var quantity = $(this).val();
var row_id = $(this).data("rowid");
$.ajax({
url:"<?php echo base_url(); ?>Sepet/setliste",
method:"POST",
data:{row_id:row_id, quantity:quantity},
success:function(data)
{
//alert("Güncellendi");
$('#sepetload').html(data);
}
});

Php ajax update button not working in jquery [duplicate]

list.php: A simple ajax code that I want to display only records of the Mysql table:
<html>
<head>
<script src="jquery-1.9.1.min.js">
</script>
<script>
$(document).ready(function() {
var response = '';
$.ajax({
type: "GET",
url: "Records.php",
async: false,
success: function(text) {
response = text;
}
});
alert(response);
});
</script>
</head>
<body>
<div id="div1">
<h2>Let jQuery AJAX Change This Text</h2>
</div>
<button>Get Records</button>
</body>
</html>
Records.php is the file to fetch records from Mysql.
In the Database are only two fields: 'Name', 'Address'.
<?php
//database name = "simple_ajax"
//table name = "users"
$con = mysql_connect("localhost","root","");
$dbs = mysql_select_db("simple_ajax",$con);
$result= mysql_query("select * from users");
$array = mysql_fetch_row($result);
?>
<tr>
<td>Name: </td>
<td>Address: </td>
</tr>
<?php
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>$row[1]</td>";
echo "<td>$row[2]</td>";
echo "</tr>";
}
?>
This code is not working.
For retrieving data using Ajax + jQuery, you should write the following code:
<html>
<script type="text/javascript" src="jquery-1.3.2.js"> </script>
<script type="text/javascript">
$(document).ready(function() {
$("#display").click(function() {
$.ajax({ //create an ajax request to display.php
type: "GET",
url: "display.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
<body>
<h3 align="center">Manage Student Details</h3>
<table border="1" align="center">
<tr>
<td> <input type="button" id="display" value="Display All Data" /> </td>
</tr>
</table>
<div id="responsecontainer" align="center">
</div>
</body>
</html>
For mysqli connection, write this:
<?php
$con=mysqli_connect("localhost","root","");
For displaying the data from database, you should write this :
<?php
include("connection.php");
mysqli_select_db("samples",$con);
$result=mysqli_query("select * from student",$con);
echo "<table border='1' >
<tr>
<td align=center> <b>Roll No</b></td>
<td align=center><b>Name</b></td>
<td align=center><b>Address</b></td>
<td align=center><b>Stream</b></td></td>
<td align=center><b>Status</b></td>";
while($data = mysqli_fetch_row($result))
{
echo "<tr>";
echo "<td align=center>$data[0]</td>";
echo "<td align=center>$data[1]</td>";
echo "<td align=center>$data[2]</td>";
echo "<td align=center>$data[3]</td>";
echo "<td align=center>$data[4]</td>";
echo "</tr>";
}
echo "</table>";
?>
You can't return ajax return value. You stored global variable store your return values after return.
Or Change ur code like this one.
AjaxGet = function (url) {
var result = $.ajax({
type: "POST",
url: url,
param: '{}',
contentType: "application/json; charset=utf-8",
dataType: "json",
async: false,
success: function (data) {
// nothing needed here
}
}) .responseText ;
return result;
}
Please make sure your $row[1] , $row[2] contains correct value, we do assume here that 1 = Name , and 2 here is your Address field ?
Assuming you have correctly fetched your records from your Records.php, You can do something like this:
$(document).ready(function()
{
$('#getRecords').click(function()
{
var response = '';
$.ajax({ type: 'POST',
url: "Records.php",
async: false,
success : function(text){
$('#table1').html(text);
}
});
});
}
In your HTML
<table id="table1">
//Let jQuery AJAX Change This Text
</table>
<button id='getRecords'>Get Records</button>
A little note:
Try learing PDO http://php.net/manual/en/class.pdo.php since mysql_* functions are no longer encouraged..
$(document).ready(function(){
var response = '';
$.ajax({ type: "GET",
url: "Records.php",
async: false,
success : function(text)
{
response = text;
}
});
alert(response);
});
needs to be:
$(document).ready(function(){
$.ajax({ type: "GET",
url: "Records.php",
async: false,
success : function(text)
{
alert(text);
}
});
});
This answer was for #
Neha Gandhi but I modified it for people who use pdo and mysqli sing mysql functions are not supported. Here is the new answer
<html>
<!--Save this as index.php-->
<script src="//code.jquery.com/jquery-1.9.1.js"></script>
<script src="//ajax.aspnetcdn.com/ajax/jquery.validate/1.9/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#display").click(function() {
$.ajax({ //create an ajax request to display.php
type: "GET",
url: "display.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
<body>
<h3 align="center">Manage Student Details</h3>
<table border="1" align="center">
<tr>
<td> <input type="button" id="display" value="Display All Data" /> </td>
</tr>
</table>
<div id="responsecontainer" align="center">
</div>
</body>
</html>
<?php
// save this as display.php
// show errors
error_reporting(E_ALL);
ini_set('display_errors', 1);
//errors ends here
// call the page for connecting to the db
require_once('dbconnector.php');
?>
<?php
$get_member =" SELECT
empid, lastName, firstName, email, usercode, companyid, userid, jobTitle, cell, employeetype, address ,initials FROM employees";
$user_coder1 = $con->prepare($get_member);
$user_coder1 ->execute();
echo "<table border='1' >
<tr>
<td align=center> <b>Roll No</b></td>
<td align=center><b>Name</b></td>
<td align=center><b>Address</b></td>
<td align=center><b>Stream</b></td></td>
<td align=center><b>Status</b></td>";
while($row =$user_coder1->fetch(PDO::FETCH_ASSOC)){
$firstName = $row['firstName'];
$empid = $row['empid'];
$lastName = $row['lastName'];
$cell = $row['cell'];
echo "<tr>";
echo "<td align=center>$firstName</td>";
echo "<td align=center>$empid</td>";
echo "<td align=center>$lastName </td>";
echo "<td align=center>$cell</td>";
echo "<td align=center>$cell</td>";
echo "</tr>";
}
echo "</table>";
?>
<?php
// save this as dbconnector.php
function connected_Db(){
$dsn = 'mysql:host=localhost;dbname=mydb;charset=utf8';
$opt = array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC
);
#echo "Yes we are connected";
return new PDO($dsn,'username','password', $opt);
}
$con = connected_Db();
if($con){
//echo "me is connected ";
}
else {
//echo "Connection faid ";
exit();
}
?>

jQuery code does not work after resetting a div's content twice

There is a div element :
...
<div id="liste_secteurs"></div>
...
<script type="text/javascript">
$(document).ready(function() {
rechercheSecteursEtProduits(0); // setting the div's content
$('#btnSupprimer').click(function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
});
});
function rechercheSecteursEtProduits(pn){
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_user="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html); // this is the div element
}
</script>
Code of ListerProduitsUserParSecteursAjax.php :
<?php
... // getting database data
?>
<p>Total : <?php echo $nr; ?></p>
<div><img src="<?php echo HTTP_ICON.'plus.png'; ?>" /></div>
<?php echo $paginationDisplay; ?>
<table id="table" class="data display " >
<thead style="background-color:#CCC">
<tr>
<th><?php echo _getText("service.produit.form.secteur_activite");?></th>
<th><?php echo _getText("service.produit.form.titre");?></th>
<th></th>
<th><?php if($data["secteur"]["cnt"] > 0){ ?><input type="checkbox" id="check_all"><?php }?></th>
</tr>
</thead>
<tbody style="background-color:#FFF">
<?php
if($data["secteur"]["cnt"] > 0){
for($i=0;$i<$data["secteur"]["cnt"];$i++){?>
<tr class="odd gradeX">
<td><?php echo $data["secteur"][$i]["secta_lib_fr"] ?></td>
<td><?php echo $data["secteur"][$i]["produit_lib"] ?></td>
<td align="center" style="vertical-align:middle"><img src="<?php echo HTTP_ICON.'edit.png'; ?>" alt="<?php echo _getText('main.btn.modifier'); ?>" style="height:10px;width:10px;" /></td>
<td align="center" style="vertical-align:middle"><input type="checkbox" id="prod_<?php echo $i; ?>" value="<?php echo $data['secteur'][$i]['id_user_produit']; ?>"><input type="hidden" id="secteur_<?php echo $i; ?>" value="<?php echo $data['secteur'][$i]['id_user_secteur']; ?>"></td>
</tr>
<?php } ?>
<?php
}
else{
?>
<tr class="odd gradeX">
<td colspan="4" align="center"><b><?php echo _getText('main.liste.no_data'); ?></b></td>
</tr>
<?php }?>
</tbody>
</table>
<?php if($data["secteur"]["cnt"] > 0){ ?>
<div align="right"><input name="btnSupprimer" id="btnSupprimer" type="button" value="<?php echo _getText("main.btn.delete"); ?>" class="btn btn-blue"/></div>
<?php } ?>
<?php echo $paginationDisplay; ?>
When the page loads for the first time then the delete button works fine : the selected rows are deleted , and the list reappears accordingly to new database data. But later when I want to delete other rows then the alert does not show when I check some checkboxes and clicking the delete button !
So what is wrong in my approach ?
From what I am reading you are having problems with the row that are added from the database.
What could be the problem is when you execute this peace of code:
$('#btnSupprimer').click(function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
When you call the $.click() function you add a event to all the existing DOM object that have a id of 'btnSupprimer', however this doesn't update if you add a new DOM object. So what you should do is call this function every time you add a new row. you would get something like this:
function rechercheSecteursEtProduits(pn){
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_user="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html);
$('#btnSupprimer').click(addClickHandler()); // this is the div element
}
function addClickHandler(){
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
}
I hope it helps
Try using on instead of click as below
$('#btnSupprimer').on("click","#liste_secteurs",function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
});
Use the dynamic jquery selector instead of the regular 'click' event
$('#liste_secteurs').on('click', '#btnSupprimer', function() {});
// $("container").on("event", "button", function() {});
As from Caveman's answer I made some updates :
function rechercheSecteursEtProduits(pn) {
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_usermer="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html);
$('#btnSupprimer').on('click',function(){
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
if (confirm("Do you want to remove these records ?")) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0);
}
}
});
}
And it works !

Using Jquery Ajax to retrieve data from Mysql

list.php: A simple ajax code that I want to display only records of the Mysql table:
<html>
<head>
<script src="jquery-1.9.1.min.js">
</script>
<script>
$(document).ready(function() {
var response = '';
$.ajax({
type: "GET",
url: "Records.php",
async: false,
success: function(text) {
response = text;
}
});
alert(response);
});
</script>
</head>
<body>
<div id="div1">
<h2>Let jQuery AJAX Change This Text</h2>
</div>
<button>Get Records</button>
</body>
</html>
Records.php is the file to fetch records from Mysql.
In the Database are only two fields: 'Name', 'Address'.
<?php
//database name = "simple_ajax"
//table name = "users"
$con = mysql_connect("localhost","root","");
$dbs = mysql_select_db("simple_ajax",$con);
$result= mysql_query("select * from users");
$array = mysql_fetch_row($result);
?>
<tr>
<td>Name: </td>
<td>Address: </td>
</tr>
<?php
while ($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>$row[1]</td>";
echo "<td>$row[2]</td>";
echo "</tr>";
}
?>
This code is not working.
For retrieving data using Ajax + jQuery, you should write the following code:
<html>
<script type="text/javascript" src="jquery-1.3.2.js"> </script>
<script type="text/javascript">
$(document).ready(function() {
$("#display").click(function() {
$.ajax({ //create an ajax request to display.php
type: "GET",
url: "display.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
<body>
<h3 align="center">Manage Student Details</h3>
<table border="1" align="center">
<tr>
<td> <input type="button" id="display" value="Display All Data" /> </td>
</tr>
</table>
<div id="responsecontainer" align="center">
</div>
</body>
</html>
For mysqli connection, write this:
<?php
$con=mysqli_connect("localhost","root","");
For displaying the data from database, you should write this :
<?php
include("connection.php");
mysqli_select_db("samples",$con);
$result=mysqli_query("select * from student",$con);
echo "<table border='1' >
<tr>
<td align=center> <b>Roll No</b></td>
<td align=center><b>Name</b></td>
<td align=center><b>Address</b></td>
<td align=center><b>Stream</b></td></td>
<td align=center><b>Status</b></td>";
while($data = mysqli_fetch_row($result))
{
echo "<tr>";
echo "<td align=center>$data[0]</td>";
echo "<td align=center>$data[1]</td>";
echo "<td align=center>$data[2]</td>";
echo "<td align=center>$data[3]</td>";
echo "<td align=center>$data[4]</td>";
echo "</tr>";
}
echo "</table>";
?>
You can't return ajax return value. You stored global variable store your return values after return.
Or Change ur code like this one.
AjaxGet = function (url) {
var result = $.ajax({
type: "POST",
url: url,
param: '{}',
contentType: "application/json; charset=utf-8",
dataType: "json",
async: false,
success: function (data) {
// nothing needed here
}
}) .responseText ;
return result;
}
Please make sure your $row[1] , $row[2] contains correct value, we do assume here that 1 = Name , and 2 here is your Address field ?
Assuming you have correctly fetched your records from your Records.php, You can do something like this:
$(document).ready(function()
{
$('#getRecords').click(function()
{
var response = '';
$.ajax({ type: 'POST',
url: "Records.php",
async: false,
success : function(text){
$('#table1').html(text);
}
});
});
}
In your HTML
<table id="table1">
//Let jQuery AJAX Change This Text
</table>
<button id='getRecords'>Get Records</button>
A little note:
Try learing PDO http://php.net/manual/en/class.pdo.php since mysql_* functions are no longer encouraged..
$(document).ready(function(){
var response = '';
$.ajax({ type: "GET",
url: "Records.php",
async: false,
success : function(text)
{
response = text;
}
});
alert(response);
});
needs to be:
$(document).ready(function(){
$.ajax({ type: "GET",
url: "Records.php",
async: false,
success : function(text)
{
alert(text);
}
});
});
This answer was for #
Neha Gandhi but I modified it for people who use pdo and mysqli sing mysql functions are not supported. Here is the new answer
<html>
<!--Save this as index.php-->
<script src="//code.jquery.com/jquery-1.9.1.js"></script>
<script src="//ajax.aspnetcdn.com/ajax/jquery.validate/1.9/jquery.validate.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#display").click(function() {
$.ajax({ //create an ajax request to display.php
type: "GET",
url: "display.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#responsecontainer").html(response);
//alert(response);
}
});
});
});
</script>
<body>
<h3 align="center">Manage Student Details</h3>
<table border="1" align="center">
<tr>
<td> <input type="button" id="display" value="Display All Data" /> </td>
</tr>
</table>
<div id="responsecontainer" align="center">
</div>
</body>
</html>
<?php
// save this as display.php
// show errors
error_reporting(E_ALL);
ini_set('display_errors', 1);
//errors ends here
// call the page for connecting to the db
require_once('dbconnector.php');
?>
<?php
$get_member =" SELECT
empid, lastName, firstName, email, usercode, companyid, userid, jobTitle, cell, employeetype, address ,initials FROM employees";
$user_coder1 = $con->prepare($get_member);
$user_coder1 ->execute();
echo "<table border='1' >
<tr>
<td align=center> <b>Roll No</b></td>
<td align=center><b>Name</b></td>
<td align=center><b>Address</b></td>
<td align=center><b>Stream</b></td></td>
<td align=center><b>Status</b></td>";
while($row =$user_coder1->fetch(PDO::FETCH_ASSOC)){
$firstName = $row['firstName'];
$empid = $row['empid'];
$lastName = $row['lastName'];
$cell = $row['cell'];
echo "<tr>";
echo "<td align=center>$firstName</td>";
echo "<td align=center>$empid</td>";
echo "<td align=center>$lastName </td>";
echo "<td align=center>$cell</td>";
echo "<td align=center>$cell</td>";
echo "</tr>";
}
echo "</table>";
?>
<?php
// save this as dbconnector.php
function connected_Db(){
$dsn = 'mysql:host=localhost;dbname=mydb;charset=utf8';
$opt = array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC
);
#echo "Yes we are connected";
return new PDO($dsn,'username','password', $opt);
}
$con = connected_Db();
if($con){
//echo "me is connected ";
}
else {
//echo "Connection faid ";
exit();
}
?>

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