How to show all data from multiple table using sql JOIN query? - php

Question

I have following Mysql table :
1) products
2) product_images
3) product_date_time
4) product_menu
5) chef_profile
I need to show all data from those 5 table to a page called menu-details.php
All table have foreign key as p_id of products table id and Some table have multiple data of same p_id.
To get this done I am using following mysql join query :
$query = mysqli_query($conn, "SELECT p.p_id, p.p_title, p.p_description,
p.p_price, p.p_availability, p.delivery_option, p.event_location,
pimg.p_large_image, pimg.p_small_image, pdt.date, pm.p_menu_title,
pm.p_menu_description, pm.p_menu_price, pm.p_menu_availability, chef.fname,
chef.lname, chef.chef_details FROM products as p LEFT JOIN product_images as
pimg ON p.p_id = pimg.p_id LEFT JOIN product_date_time as pdt ON pdt.p_id =
p.p_id LEFT JOIN product_menu as pm ON pm.p_id = p.p_id LEFT JOIN
chef_profile AS chef ON chef.u_id = p.u_id WHERE p.p_id = '$mid' ") or
die('wrong query');
To show data I am using following php code :
$result = mysqli_fetch_array($query);
$menu_title = htmlspecialchars($result['p_title']);
My Questions
Should I use 5 unique sql query to show data to that menu_details.php page ?
Now this query is showing single record from those table which have multiple data of same p_id. I need to show all data which have same p_id with multiple data. How can I do this ?
For example : I have following data in product_images table :
pimg_id p_large_image p_id u_id
1 name 203 25
1 name 204 26
1 name 204 25
1 name 205 27
1 name 205 28
So If I use php while loop it's showing all data from that table but it's should be show all data based on p_id for e.g p_id = 204
while($result = mysqli_fetch_array($query)) {
echo $menu_l_image = htmlspecialchars($result['p_large_image']);
echo '<br/>';
}

Answer 1

If the p.id is an integer remove the single quote form $mid
"SELECT
p.p_id,
p.p_title,
p.p_description,
p.p_price,
p.p_availability,
p.delivery_option,
p.event_location,
pimg.p_large_image,
pimg.p_small_image,
pdt.date,
pm.p_menu_title,
pm.p_menu_description,
pm.p_menu_price,
pm.p_menu_availability,
chef.fname,
chef.lname,
chef.chef_details
FROM products as p
LEFT JOIN product_images as pimg ON p.p_id = pimg.p_id
LEFT JOIN product_date_time as pdt ON pdt.p_id = p.p_id
LEFT JOIN product_menu as pm ON pm.p_id = p.p_id
LEFT JOIN chef_profile AS chef ON chef.u_id = p.u_id
WHERE p.p_id = $mid "
of previus a proper sanitize of the $mid vars you can use
"SELECT
p.p_id,
p.p_title,
p.p_description,
p.p_price,
p.p_availability,
p.delivery_option,
p.event_location,
pimg.p_large_image,
pimg.p_small_image,
pdt.date,
pm.p_menu_title,
pm.p_menu_description,
pm.p_menu_price,
pm.p_menu_availability,
chef.fname,
chef.lname,
chef.chef_details
FROM products as p
LEFT JOIN product_images as pimg ON p.p_id = pimg.p_id
LEFT JOIN product_date_time as pdt ON pdt.p_id = p.p_id
LEFT JOIN product_menu as pm ON pm.p_id = p.p_id
LEFT JOIN chef_profile AS chef ON chef.u_id = p.u_id
WHERE p.p_id = ". $mid . ";"