PHP pdo insert query not working - php

Question

<?php
// DATABASE-HOSTNAME-OR-IPADDRESS-GOES-HERE
// MYSQL-DBNAME-GOES-HERE
class LoginHandler {
public $dbHostname = 'localhost';
public $dbDatabaseName = 'employee101';
public $user = 'root';
public $password = 'root';
public function handleRequest($arg) {
$username = '123';
$password2 = '123';
$fname = 'John';
$lname = 'Doe';
$age = '18';
if ( ! $username ) {
$this->fail();
return;
}
try {
$dsn = "mysql:dbname={$this->dbDatabaseName};host={$this->dbHostname};port=8888";
$pdo = new PDO($dsn, $this->user, $this->password);
$sql="SELECT * FROM `employee_data` WHERE `username`='$username'";
$stmt = $pdo->query($sql);
if ( $stmt === false ) {
echo "DB Critical Error";
return;
}
elseif ( $stmt->rowCount() > 0 ) {
echo "user already exists";
return;
}
else {
echo "User created";
$sql = "INSERT INTO employee_data (name, sumame, age, username, password)
VALUES ($fname, $lname, $age, $username, $password2)";
$dsn = "mysql:dbname={$this->dbDatabaseName};host={$this->dbHostname};port=8888";
$pdo = new PDO($dsn, $this->user, $this->password);
$stmtz = $pdo->prepare($sql);
$stmtz->bindParam($fname, $_POST[$fname], PDO::PARAM_STR);
$stmtz->bindParam($lname, $_POST[$lname], PDO::PARAM_STR);
$stmtz->bindParam($age, $_POST[$age], PDO::PARAM_STR);
$stmtz->bindParam($username, $_POST[$username], PDO::PARAM_STR);
$stmtz->bindParam($password2, $_POST[$password2], PDO::PARAM_STR);
$resultzzx = $stmtz->execute();
return;
}
}
catch(PDOException $e) {
$this->log('Connection failed: ' . $e->getMessage());
echo "DB Critical Error";
}
}
function log($msg) {
file_put_contents("login.log", strftime('%Y-%m-%d %T ') . "$msg\n", FILE_APPEND);
}
}
$handler = new LoginHandler();
$handler->handleRequest($_POST);
?>
When attempting to use this script above, I get the echo that the user was created, but even when refreshing the table, the new entry doesn't show up.
Now, if i change the values line to be the following, it will work and show the new entry.
('John', 'Doe', '18', $username, $password2)";
What am i doing wrong? I need the first name, last name and age entries to not be concrete, as i will be obtaining them from a POST on my android device. The whole purpose of this script is to create the user and it's records if it doesn't already exist.

Answer 1

You have various mistakes.
1) You are not binding your parameters correctly. To bind them correctly, you place a :variablename in the position you want to include the variable. Usually the "variablename" should be the same as the one you are obtaining from the $_POST superglobal so that the code is cleaner and more readable.
2) You are not obtaining the values from the $_POST superglobal correctly. The key values you place inside are strings, and by placing an empty $fname variable, you are not going to obtain a correct result. It would only work if you had coding saying $fname = 'fname' somewhere up top hidden from us, however that code itself would be unadvised since it is unnecessary and only makes the source code larger.
$sql = "INSERT INTO employee_data (name, sumame, age, username, password)
VALUES (:fname, :lname, :age, :username, :password2)";
$dsn = "mysql:dbname={$this->dbDatabaseName};host=
{$this>dbHostname};port=8888";
$pdo = new PDO($dsn, $this->user, $this->password);
$stmtz = $pdo->prepare($sql);
$stmtz->bindParam(':fname', $_POST['fname']);
$stmtz->bindParam(':lname', $_POST['lname']);
$stmtz->bindParam(':age', $_POST['age']);
$stmtz->bindParam(':username', $_POST['username']);
$stmtz->bindParam(':password2', $_POST['password2']);
I hope that helps.

Answer 2

$sql = "INSERT INTO employee_data (name, sumame, age, username, password) VALUES (:name, :sumame, :age, :username, :password)";
$dsn = "mysql:dbname={$this->dbDatabaseName};host={$this->dbHostname};port=8888";
$pdo = new PDO($dsn, $this->user, $this->password);
$stmtz = $pdo->prepare($sql);
$stmtz->bindParam(':name', $fname);
$stmtz->bindParam(':sumame', $lname);
$stmtz->bindParam(':age', $age);
$stmtz->bindParam(':username', $username);
$stmtz->bindParam(':password', $password2);
$resultzzx = $stmtz->execute();
return;
After reviewing the link Fred posted in the comment above, i've modified it to work fine, thanks.