how Delete a value in Array php - php

Question

Please help
when i want yo remove an element from array buu after when i print array it shows error
4
6
2
NOTICE Undefined offset: 3 on line number 16
<?php
$value = 22;
$numbers = array(4, 6, 2, 22, 11);
$arrlength = count($numbers);
for($y = 0; $y < $arrlength ; $y++) {
if ( $numbers[$y] == $value) {
unset($numbers[$y]);
}
}
$arrlength = count($numbers);
for($x = 0; $x < $arrlength; $x++) {
echo $numbers[$x];
echo "<br>";
}
?>

Answer 1

You should use "array_values()" to re-index the array. You can find the explication here : http://php.net/manual/en/language.types.array.php#language.types.array.useful-funcs

Answer 2

Use array_values().
<?php
$value = 22;
$numbers = array(4, 6, 2, 22, 11);
$arrlength = count($numbers);
for($y = 0; $y < $arrlength ; $y++) {
if ( $numbers[$y] == $value) {
unset($numbers[$y]);
}
}
$numbers = array_values($numbers);
$arrlength = count($numbers);
for($x = 0; $x < $arrlength; $x++) {
echo $numbers[$x];
echo "<br>";
}
?>
Check Online Demo : Click Here
OR
<?php
$value = 22;
$numbers = array(4, 6, 2, 22, 11);
$arrlength = count($numbers);
for($y = 0; $y < $arrlength ; $y++) {
if ( $numbers[$y] == $value) {
unset($numbers[$y]);
}
}
//$numbers = array_values($numbers);
//$arrlength = count($numbers);
foreach($numbers as $key=>$num) {
echo $num;
echo "<br>";
}
?>

Answer 3

you are trying to print element of not existing key
try this:
<?php
$value = 22;
$numbers = array(4, 6, 2, 22, 11);
$arrlength = count($numbers);
for($y = 0; $y < $arrlength ; $y++) {
if ( $numbers[$y] == $value) {
unset($numbers[$y]);
}
}
foreach($numbers as $k => $number)
echo "key: ". $k . " value: ". $number . "<br />";