html php echo on div - php

Question

here i have a simple function but this show me data fom sql only in 1 div i want to show [ on div 1 show 1 data, in other div show 2 data, etc etc]...
function load_post($added_by)
{
global $Connection;
$SQL_3 = mysqli_query($Connection, "SELECT * FROM posts WHERE added_by='$added_by'");
$NumPosts = mysqli_num_rows($SQL_3);
$out['num_posts'] = $NumPosts;
while($Fetch_3 = mysqli_fetch_array($SQL_3))
{
$out['id'] = $Fetch_3['id'];
$out['text'] = $Fetch_3['text'];
$out['added_by'] = $Fetch_3['added_by'];
$out['mp4'] = $Fetch_3['mp4'];
$out['likes'] = $Fetch_3['likes'];
$out['youtube'] = $Fetch_3['youtube'];
$out['image'] = $Fetch_3['image'];
$out['date_added'] = $Fetch_3['date_added'];
return $out;
}
}
index.php.
$posts = load_post('gentritabazi');
<div class="settings_forms_content">
<?php echo $posts['text']; ?>
</div>

Answer 1

return finish immediately your function so only one iteration is done. You need to save your results in array and then after loop return that array, sth like this:
$out = array();
while($Fetch_3 = mysqli_fetch_array($SQL_3))
{
$out[] = $Fetch_3;
}
return $out;
and display:
$posts = load_post('gentritabazi');
foreach ($posts as $post) {
echo '<div class="settings_forms_content">';
echo $post['text'];
echo '</div>';
}

Answer 2

Lots to amend, so I commented the code rather than write an essay
function load_post($con, $added_by)
{
// dont use globals, use parameters
//global $Connection;
// select only what you want to see not `*`
$SQL_3 = mysqli_query($con, "SELECT id, text, added_by, mp4,
likes, youtube, image, data_added
FROM posts
WHERE added_by='$added_by'");
// not needed
//$NumPosts = mysqli_num_rows($SQL_3);
//$out['num_posts'] = $NumPosts;
while($Fetch_3 = mysqli_fetch_array($SQL_3))
{
/*
* THsi code would overwrite the last iteration of the while loop
$out['id'] = $Fetch_3['id'];
$out['text'] = $Fetch_3['text'];
$out['added_by'] = $Fetch_3['added_by'];
$out['mp4'] = $Fetch_3['mp4'];
$out['likes'] = $Fetch_3['likes'];
$out['youtube'] = $Fetch_3['youtube'];
$out['image'] = $Fetch_3['image'];
$out['date_added'] = $Fetch_3['date_added'];
*/
// now as you SELECT only what you want yo can simply do
$out[] = $Fetch_3;
//return $out; instantly terminates the function
}
return $out; // return the array
}
Now call your function
// pass the connection as a parameter
$posts = load_post($Connection, 'gentritabazi');
// if you want to know how many results were returned
$result_count = count($posts);
// process the returned array
foreach ( $posts as $post ) {
echo '<div class="settings_forms_content">';
echo $post['text'];
echo '</div>';
}
Your script is at risk of SQL Injection Attack
Have a look at what happened to Little Bobby Tables Even
if you are escaping inputs, its not safe!
Use prepared statement and parameterized statements

Answer 3

$posts = load_post('gentritabazi');
foreach ($posts ['text'] as $postText){
echo "<div class='settings_forms_content'>$postText</div>";
}
first line calls your function which returns the array $posts
this array looks like:
$posts = array(
"id" => array of ids
"text" => array of texts
...
);
if you want to access the third text it would be like this:
$posts ['text'][3]
the foreach iterates to your $post array with index "text" -> which is also an array
every value in this array, $post['text'] will be referenced with $postText -> that means:
$post['text'][1] = $postText (first time looping through foreach-loop)
$post['text'][2] = $postText (secondtime looping through foreach-loop)
..
if you are familiar with loops, a foreach is just the short version for
for(var $i=0;$i<length($posts['text'];$i++){
echo "<div class='settings_forms_content'>$posts['text'][i]</div>";
}