i have an array result. i want to print 2 rows(product data) in first page.
next 2 rows in second page and so on. if anybody knows this,please help me to solve it
my array
$data['product_list']
foreach($data['product_list'] as $dat)
{
echo $dat->prd_id;
echo $dat->prd_name;
}
You are doing a foreach loop on an associative array and then trying to access the the contents as objects by using ->. I can only given assumption of what you might be doing. If your array is already populated with a name and id like you have described in your foreach loop this is how you would access the contents in the loop:
foreach($data['product_list'] as $dat)
{
echo $dat['prd_id'];
echo $dat['prd_name'];
}
That is how you would print out the contents providing you had the data stored in your array like so:
$data['product_list'][0] = array('prd_id'=>'id0','prd_name'=>'name0');
$data['product_list'][1] = array('prd_id'=>'id1','prd_name'=>'name1');
$data['product_list'][2] = array('prd_id'=>'id2','prd_name'=>'name2');
Better you try with array_slice();
<?php
$a=array("red","green","blue","yellow","brown");
print_r(array_slice($a,2));
?>
Related
I just started learning PHP and I am having some difficulties with some of the coding.
Hopefully, someone could help me a little.
I'm using this:
if(!empty($_POST['yyy'])) {
foreach($_POST['yyy'] as $a1) {
echo " $a1";}}
The echo will write several results of $a1 depending on how many were selected in the form.
What I want is to save those results to some values so I can add them in MySQL.
Something like this:
if(!empty($_POST['yyy']))
{
foreach($_POST['yyy'] as $a1)
{
echo " $a1"; where $a1 will create a $result1,$result2,$result3(for each isset)
}
}
Then if I use:
echo "$result2";
it will give me the second result.
Not clear whether you are asking about this kind of result or not. But you can use an array to store each values inside the foreach loop.
var data=[];// define an array to access outside of if statement later..
if(!empty($_POST['yyy'])) {
foreach($_POST['yyy'] as $a1){
data[]=$a1;
//or can use array_push() method
array_push(data,$a1);
}
}
/*this will give the second result(because array indexing starts from 0. So to get third result
use data[2])*/
echo data[1];
Furthermore by echoing quoted variable will not give the value of that variable but gives a string literal.
echo "$result2" //output---> $result
foreach loop only repeating the last element of the arary?
java Script Code :
<?php foreach($_REQUEST["itemprice"] as $itemprice)
{
?>
+ "&itemname_price[]=<?php echo $itemname?>_price=" + <?=$itemname?>_price.value
<?php
}
?>
Code to request that data
$items_price = array();
foreach($_REQUEST['itemname_price'] as $itemname_pric) {
$items_price[]=$itemname_pric;
}
print_r($items_price);
foreach is used to get the values from an array, and what you are trying here is to get data from a specific array key. I guess that's why you are getting a single value. You can refer to
http://php.net/manual/en/control-structures.foreach.php to get the exact use of foreach.
Let me know if you have anything to know.
I am trying to get the specific value of file extension in this array. All I can do so far is .
I am wanting the fileextention ".jpg"
All I know how to do is echo the values like so using foreach;
file_nameBob7213.jpg file_typeimage/jpeg
file_pathC:/xampp/htdocs/midas/records/
full_pathC:/xampp/htdocs/midas/records/Bob7213.jpg raw_nameBob7213
orig_nameBob72.jpg client_nameafasfafs.jpg **file_ext.jpg** file_size44.96
is_image1 image_width716 image_height474 image_typejpeg
image_size_strwidth="716" height="474"
I am only interested in retrieving the file_ext from this array. How do I select that exact thing?
foreach ($file['upload_data'] as $item => $value)
{
echo $item; echo $value; echo "<br/>";
}
How do I do this? , thanks!
$file['upload_data']['file_ext']
It's just an array within an array, so specify 2 array keys
Incidentally, if you want to see the contents of an array, a quick way of doing it is to use var_export:
var_export($file); # echoes the entire array
You don't need to write a foreach loop every time
$file['upload_data']['file_ext'] contains '.jpg'.
I'm trying to check if a certain category is allready selected by looping through an array of categories also I want to add another element to the array whci is just a bit to indicate is the category selcated
my categories array looks like this
0=>array(category_id=>12,category_name=>"blogger")
1=>array(category_id=>13,category_name=>"dancer")
etc...
now the code i'm trying goes like that:
foreach ($userCategories as $key=>$category) {
if($category['category_id'] == $mediaDetails['currentCategory']) {
$category['current'] = 1;
} else {
$category['current'] = 0;
}
}
when executing
die(var_dump($userCategories));
I expect to get an array similar to
0=>array(category_id=>12,category_name=>"blogger",current=>0)
1=>array(category_id=>13,category_name=>"dancer",current=>1)
but instead I get the same array I had before the foreach loop
any ideas?
Thanks
It looks like $category is not getting passed by reference.
Try $userCategories[$key]['current']=1 instead, and see how that works.
When sending data from a form to a second page, the value of the session is always with the name "Array" insteed of the expected number.
The data should get displayed in a table, but insteed of example 1, 2, 3 , 4 i get : Array, Array, Array.
(A 2-Dimensional Table is used)
Is the following code below a proper way to "call" upon the stored values on the 2nd page from the array ?
$test1 = $_SESSION["table"][0];
$test2 = $_SESSION["table"][1];
$test3 = $_SESSION["table"][2];
$test4 = $_SESSION["table"][3];
$test5 = $_SESSION["table"][4];
What exactly is this, and how can i fix this?
Is it some sort of override that needs to happen?
Best Regards.
You don't need any sort of override. The script is printing "Array" rather than a value, because you're trying to print to the screen a whole array, rather than a value within an array for example:
$some_array = array('0','1','2','3');
echo $some_array; //this will print out "Array"
echo $some_array[0]; //this will print "0"
print_r($some_array); //this will list all values within the array. Try it out!
print_r() is not useful for production code, because its ugly; however, for testing purposes it can keep you from pulling your hair out over nested arrays.
It's perfectly fine to access elements in your array by index: $some_array[2]
if you want it in a table you might do something like this:
<table>
<tr>
for($i = 0 ; $i < count($some_array) ; $i++) {
echo '<td>'.$some_array[$i].'</td>';
}
</tr>
</table>
As noted, try
echo "<pre>";
print_r($_SESSION);
echo "</pre>";
That should show you what's in the session array.
A 2-dimensional table is just an array of arrays.
So, by pulling out $_SESSION["table"][0], you're pulling out an array that represents the first row of the table.
If you want a specific value from that table, you need to pass the second index, too. i.e. $_SESSION["table"][0][0]
Or you could just be lazy and do $table = $_SESSION["table"]; at which point $table would be your normal table again.
A nice way ...
<?php
foreach ($_SESSION as $key => $value) {
echo $key . " => " . $value . "<br>";
}
?>