How to remove unused line breaks using nl2br function for this example:
Hello
Nice
Expect output display:
Hello
Nice
and another example:
remove this unused line
remove this unused line
remove this unused line
Hello
remove this unused line
remove this unused line
remove this unused line
remove this unused line
Expect output display:
Hello
So means if the line break more than 3 line, so only set 1 line breaks.
Here is my PHP code:
nl2br($string);
Old schooled but hope this works
$str = explode("\n", $str);
foreach($str as $val){
if(!empty($val)){
$result[] = $val;
}
}
$final = implode("\n", $result); //if you want line break use "<br>"
echo $final;
Related
I need to replace the line break \n or \r with the HTML tag <br>, but only outside of [code] UBB tags.
Example string, how it is stored in the DB:
$string = "Test 123
Line break
[code]5: Test
10: With line
15: breaks[/code]
Further writing
Another new line";
Using this code:
$bbextended = array(
"/\[code\](.*?)\[\/code\](*SKIP)(*FAIL)|\\r?\\n/i" => "<br>",
"/\[code\](.*?)\[\/code\]/i" => "<textarea>$1</textarea>",
);
foreach($bbextended as $match=>$replacement){
$string = preg_replace($match, $replacement, $string);
}
echo $string;
I end up with this HTML output:
Line break<br>Test123<br>[code]5: Test<br>10: With line<br>15: breaks[/code]<br>Further writing<br>Another new line
Which means that line breaks within the [code][/code] UBB tags were replaced with <br> (wrong, should not) and the code elements were not replaced by <textarea></textarea> (also wrong).
The expected HTML output is:
Line break<br>Test123<br><textarea>5: Test
10: With line
15: breaks
</textarea><br>Further writing<br>Another new line
I tried to solve it on my own with regex101, but it highlights stuff that shouldnt be highlighted..
I assume there is an issue caused by the actual line breaks and how regex searches.
"/[code[\w\W]*?code](*SKIP)(*FAIL)|\\r?\\n/i" => "<br>",
this seems to work - to detect start and end of my code tags across multiple lines and skip them from formatting with
Needed solution:
I am working with a simple PHP script that should:
Add "value4:::" at the end of the first line in a file
Add ":::" at the end of all the next lines
I am novise in programming, and have sit here for two days trying to figure this out. Might be a little detail, or it might be totally wrong way of doing this task.
It might be wrong way to do this, or may be a regex problem? I really don't know.
I kindly ask you to help me with the solution.
Information:
The file newstest.db looks like this:
ID:::value1:::value2:::value3:::
1:::My:::first:::line:::
2:::My:::second:::line:::
3:::Your:::third:::line:::
And using this php script I'd like to make it look like this:
ID:::value1:::value2:::value3:::value4:::
1:::My:::first:::line::::::
2:::My:::second:::line::::::
3:::Your:::third:::line::::::
Problem:
So far I have almost got it, but I am confused to why it adds the "value4:::" to the beginning of the second line, and then add ":::" at the beginning (not end) of all of the rest of the lines.
So I get a file that looks like this:
ID:::value1:::value2:::value3:::
value4:::1:::My:::first:::line:::
:::2:::My:::second:::line:::
:::3:::Your:::third:::line:::
I thought that:
$lineshere = 'Some text here:::';
$lines1 = $linehere.'value4:::';
would output "Some text here:::value4:::"
May be the problem is due to this way of adding line after line?
$lines = '';
$lines.= 'My test';
$lines.= ' is here';
echo $lines;
I am a novise in programming, so I might have used totally wrong functions tec to make this work.
But in this case it seams to add a space or line break/ line end in the wrong place.
My try on this solution:
<?php
// specify the file
$file_source="newstest.db";
// get the content of the file
$newscontent = file($file_source, true);
//set a start value (clear memory)
$lines ='';
// get each line and treat it line by line.
foreach ($newscontent as $line_num => $linehere) {
// add "value4:::" at the end of FIRST line only, and put it in memory $lines
if($line_num==0) {
$lines.= $linehere.'value4:::';
// Just to see what the line looks like
//echo 'First line: '.$lines.'<br /><br />';
}
// then add ":::" to the other lines and add them to memory $lines
if($line_num>0) {
$lines1 = $linehere.':::';
$lines.= $lines1;
//just look at the line
//echo 'Line #'.$line_num.': '.$lines1.'<br /><br />';
}
}
//Write new content to $file_source
$f = fopen($file_source, 'w');
fwrite($f,$lines);
fclose($f);
echo "// to show the results ar array<br /><br />";
$newscontentlook = file($file_source, true);
print_r(array_values($newscontentlook));
?>
This is actually very easy to achieve with file_get_contents and preg_replace, i.e:
$content = file_get_contents("newstest.db");
$content = preg_replace('/(^ID:.*\S)/im', '$1value4:::', $content);
$content = preg_replace('/(^\d+.*\S)/im', '$1:::', $content);
file_put_contents("newstest.db", $content);
Output:
ID:::value1:::value2:::value3:::value4:::
1:::My:::first:::line::::::
2:::My:::second:::line::::::
3:::Your:::third:::line::::::
Ideone Demo
the function file() gives you the file in an array with each line being an element of the array. Each ending of the line (EOL) is included in the elements. So appending text to that line will be after the EOL, and thus effectively on the beginning of the next line.
You can either choose to not use file() and explode the text yourself on the EOL, so the EOL is no longer part of the array element. Then edit the elements, and implode the array again.
Or fopen() the file, and fread() through it yourself. The latter option is preferred, as it won't load the entire file into memory at once.
I think the problem is in your loop through the lines read by file() function:
foreach ($newscontent as $line_num => $linehere) {
...
$linehere contains a newline at the end, so you should simply chop it before using it:
foreach ($newscontent as $line_num => $linehere) {
$linehere = chop($linehere);
...
If you don't chop the line contents, when you concatenate a string to it, you'll get:
LINE_CONTENTS\nSTRING_ADDED
which, when printed, will be:
LINE_CONTENTS
STRING_ADDED
Hope this helps...
How can I wrap <i> </i> tags around This is line one!, This is line two!, This is line three! in $thisStr below, so the result is:
`<i>This is line one!</i>`
`<i>This is line two!</i>`
`<i>This is line three!</i>`
What I did only puts tags around the :: parts. I cant get it to go back and forward and wrap tags.
$thisStr = 'This is line one! :: This is line two! :: This is line three!';
echo preg_replace("/(::)/i", "<i>$1</i>", $thisStr);
This works great, but is not preg_replace:
$thisStr = 'This is line one! :: This is line two! :: This is line three!';
$result= "<i>".str_replace("::","</i><i>",$thisStr)."</i>";
echo $result;
Or, to match your exact example:
$thisStr = 'This is line one! :: This is line two! :: This is line three!';
$result= "'<i>".str_replace(" :: ","</i>'<br/>'<i>",$thisStr)."</i>'";
echo $result;
/*
'This is line one!'
'This is line two!'
'This is line three!'
*/
If you really really really need to use preg_replace this will work
$input_lines = "This is line one!
This is line two!
This is line three!";
$New_string = preg_replace("/This is line .*/", "<i>$0</i>", $input_lines);
The pattern looks for the string "this is line" and the .* means anything in any lenght.
Then the replace pattern is quite easy to understand I guess.
But i recommend the answer Verjas wrote.
There is no need for the extra complexty the preg_replace adds.
Try this:
$thisStr = 'This is line one! :: This is line two! :: This is line three!';
$lines = explode('::', $thisStr);
$result = '';
foreach($lines as $line) {
$result .= '<i>' . $line .'</i>';
}
echo htmlentities($result);
Hope this helps.
I know for sure that this was already been asked before but I just googled around and couldn't find anything (maybe wrong word choice?).
Just don't be too mad at me, I'm getting mad too...
I'd like
$string = '
This is a line
This is another line
';
to be shown to the HTML page as
This is a line
This is another line
when I do echo $string;.
How can I capture the return key or the new line and replace it with <br>?
Try the nl2br() function:
echo nl2br($string);
Would return:
<br>
This is a line<br>
This is another line<br>
To trim off the leading and trailing new lines, use trim():
echo nl2br(trim($string));
Would return:
This is a line<br>
This is another line
You can use the PHP function nl2br. It doesn't replace the newlines but, rather, inserts <br /> next to them (which is perfectly fine for your purposes).
Using your example:
$string = '
This is a line
This is another line
';
echo nl2br($string);
/* output
<br />
This is a line<br />
This is another line<br />
*/
Use nl2br function like this:
echo nl2br($string);
If you're not getting it with nl2br, your new line character must not be \n.
print nl2br( str_replace( array( "\r\n", "\r" ), "\n", $string);
Why don't you use:
$string = "
This is a line\n
This is another line
";
?
or use
$string = <<<EOF
This is a line
This is another line
EOF;
<textarea> put returns between paragraphs
for linebreak add 2 spaces at end
indent code by 4 spaces
quote by placing > at start of line
</textarea>
$text = value from this textarea;
How to:
1) Get each line from this textarea ($text) and work with them using foreach()?
2) Add <br /> to the end of each line, except the last one?
3) Throw each line to an array.
Important - text inside textarea can be multilanguage.
Have tried to use:
$text = str_replace('\n', '<br />', $text);
But it doesn't work.
Thanks.
You will want to look into the nl2br() function along with the trim().
The nl2br() will insert <br /> before the newline character (\n) and the trim() will remove any ending \n or whitespace characters.
$text = trim($_POST['textareaname']); // remove the last \n or whitespace character
$text = nl2br($text); // insert <br /> before \n
That should do what you want.
UPDATE
The reason the following code will not work is because in order for \n to be recognized, it needs to be inside double quotes since double quotes parse data inside of them, where as single quotes takes it literally, IE "\n"
$text = str_replace('\n', '<br />', $text);
To fix it, it would be:
$text = str_replace("\n", '<br />', $text);
But it is still better to use the builtin nl2br() function, PHP provides.
EDIT
Sorry, I figured the first question was so you could add the linebreaks in, indeed this will change the answer quite a bit, as anytype of explode() will remove the line breaks, but here it is:
$text = trim($_POST['textareaname']);
$textAr = explode("\n", $text);
$textAr = array_filter($textAr, 'trim'); // remove any extra \r characters left behind
foreach ($textAr as $line) {
// processing here.
}
If you do it this way, you will need to append the <br /> onto the end of the line before the processing is done on your own, as the explode() function will remove the \n characters.
Added the array_filter() to trim() off any extra \r characters that may have been lingering.
You could use PHP constant:
$array = explode(PHP_EOL, $text);
additional notes:
1. For me this is the easiest and the safest way because it is cross platform compatible (Windows/Linux etc.)
2. It is better to use PHP CONSTANT whenever you can for faster execution
Old tread...? Well, someone may bump into this...
Please check out http://telamenta.com/techarticle/php-explode-newlines-and-you
Rather than using:
$values = explode("\n", $value_string);
Use a safer method like:
$values = preg_split('/[\n\r]+/', $value_string);
Use PHP DOM to parse and add <br/> in it. Like this:
$html = '<textarea> put returns between paragraphs
for linebreak add 2 spaces at end
indent code by 4 spaces
quote by placing > at start of line
</textarea>';
//parsing begins here:
$doc = new DOMDocument();
#$doc->loadHTML($html);
$nodes = $doc->getElementsByTagName('textarea');
//get text and add <br/> then remove last <br/>
$lines = $nodes->item(0)->nodeValue;
//split it by newlines
$lines = explode("\n", $lines);
//add <br/> at end of each line
foreach($lines as $line)
$output .= $line . "<br/>";
//remove last <br/>
$output = rtrim($output, "<br/>");
//display it
var_dump($output);
This outputs:
string ' put returns between paragraphs
<br/>for linebreak add 2 spaces at end
<br/>indent code by 4 spaces
<br/>quote by placing > at start of line
' (length=141)
It works for me:
if (isset($_POST['MyTextAreaName'])){
$array=explode( "\r\n", $_POST['MyTextAreaName'] );
now, my $array will have all the lines I need
for ($i = 0; $i <= count($array); $i++)
{
echo (trim($array[$i]) . "<br/>");
}
(make sure to close the if block with another curly brace)
}
$array = explode("\n", $text);
for($i=0; $i < count($array); $i++)
{
echo $line;
if($i < count($array)-1)
{
echo '<br />';
}
}
$content = $_POST['content_name'];
$lines = explode("\n", $content);
foreach( $lines as $index => $line )
{
$lines[$index] = $line . '<br/>';
}
// $lines contains your lines
For a <br> on each line, use
<textarea wrap="physical"></textarea>
You will get \ns in the value of the textarea. Then, use the nl2br() function to create <br>s, or you can explode() it for <br> or \n.
Hope this helps