I have an online MySQL where a table has a column containing an https URL which is stored as varchar(255). For example, here's a screenshot from phpMyAdmin:
The strange thing which is actually happens, is that when I get the data from MySQL through PHP and I encode them into JSON (so that to be delivered to an iOS app) then the caption is always null. Here's my code:
public function fieldInfoByFishID($fish_id){
$sql = mysqli_query($this->config->dbConn,"SELECT * FROM ".$this->config->table_fields." WHERE id_fish='".$fish_id."'");
$v = mysqli_fetch_array($sql,MYSQLI_ASSOC);
$tmp = array(
'id'=>$v['id'],
'id_fish'=>$v['id_fish'],
'description_info'=>utf8_encode($v['description_info']),
'recognition_info'=>utf8_encode($v['recognition_info']),
'place_info'=>utf8_encode($v['place_info']),
'fishing_method'=>$v['fishing_method'],
'buy_period'=>$v['buy_period'],
'caption'=>$v['caption'],
'life_method'=>utf8_encode($v['life_method']),
'exploitation_status'=>$v['exploitation_status']
);
return $tmp;
}
The code looks correct to me but I don't know why that column is not fetched. Is there a particular attention I have to pay in order to get the url correctly? I thought it was just a simple string.
Here's an example:
Obviously, if I tr to exec the sql query in phpMyAdmin console, it all works fine.
Thank you all.
Related
I have successfully extracted the correct data from my database during testing (its just a prototype - so yes I know its not secure SQL). The test SQL is
$sql=
SELECT *
FROM jobcards
WHERE jobnumber='$jobnumber'
";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0)
{loop}
The issue is the source of the data to which $jobnumber is set.
If during testing I set $jobnumber to the string Agen912-491 (implicitly) I get out of the database exactly what I should get out. However here is the problem.
I am clicking from a link on another page. The link creates the URL:-
domain.php/jobcard.php?jobnumber=%20Agen912-491
which take me to the page on which the SQL query (and the output) resides. So on the page I set
$jobnumber = $_GET["jobnumber"];
echo $jobnumber;//testing
to request (and test) the jobnumber (passed from the link) that I need to insert into the WHERE condition. As expected the echo correctly returns Agen912-491. So exactly the same string (it seems) as the implicit value used succesfully in testing. All good so far.
However when I then set $jobnumber= $_GET["jobnumber"]; the database query fails to find any records. [In desperation I fudged the process so that the variable $jobnumber = $_SESSION ["jobnumber"]; (and ensured via an echo that $_session[] gave me Agent912-491). Now the database correctly returns the record again!
So for some reason the $GET["jobnumber"]; statement when set to $jobnumber is failing [even though when it is echoed it returns the correct value that works implicity (and when set it via $s[session]. So there is clearly an issue with a) requesting $_GET["jobnumber"]; b) setting it to the $jobnumber and then c) using that in the WHERE statement. Everything else works as does setting $jobnumber implicitly or via $_session.
I have an incline it might be something to do with santitising the $_GET result before using it. But that really is a guess and even if correct I dont know what exactly to try out.
Help would be really appreciated. Many thanks.
I'm developping a website where there are ajax request to get data from a mySQL database.
To simplify the problem, let's say I have the following database structure :
Table OBJECT
ID_OBJECT (int)
NAME_OBJECT (varchar)
Table IMAGE
ID_OBJECT (int) -> foreign key from OBJECT
URL (varchar)
So every object can have between 0 and n images attached to it.
I'm stuck at writing the php script that request the data.
To simplify again, let's say I want to get all objects with all the images they have (but in the future I'll want to get any specific object with all its picture too)
I have written this PHP script :
$sql = "select
ID_OBJECT,
NAME_OBJECT,
URL
from
OBJECT,
IMAGE
where
OBJECT.ID_OBJECT = IMAGE.ID_OBJECT";
$statement=$db->prepare($sql);
$statement->execute();
$result=$statement->fetchAll(PDO::FETCH_ASSOC);
header('Content-Type: application/json; charset=utf-8');
echo json_encode($result);
The problem I have is as soon as I add "URL", "IMAGE" and the where statement in the sql query, it doen"t echo anything.(I have several objects and images in my databases with the propers ids). I don't understand where I'm making a mistake here.
ID_OBJECT is in both tables, so MySQl doesn't know which one to show. Try specifying like this:
select
OBJECT.ID_OBJECT,
OBJECT.NAME_OBJECT,
IMAGE.URL
from
OBJECT,
IMAGE
where
OBJECT.ID_OBJECT = IMAGE.ID_OBJECT
Obviously you have an error in your query. You should set what ID_OBJECT field you want - from first or second table.
Rewrite your query like:
select
o.ID_OBJECT,
o,NAME_OBJECT,
i.URL
from
OBJECT o,
IMAGE i
where
o.ID_OBJECT = i.ID_OBJECT
I have a mySQL database table setup called site.
Rather than qet the column headings to produce a PHP object of values I want to produce data from the rows.
TABLE: site
:::field:::::value:::::
url www.example.com
name example site
etc Example Etcetera
So I want to be able to get this information from the server by calling the column name I want and the row I am after. I want to do this for all fields in site as I don't want to do multiple calls for the various different rows in site; I'd rather store all the information from the beginning in the object:
eg. <? echo $site['url']; ?>
I created this put it appears to be causing an error:.
$sql = "SELECT * FROM `site`";
$site[];
foreach($sodh->query($sql) as $sitefield){
$site[$sitefield['field']] = $sitefield['value'];
}
Obviously I've missed something. ¿Any idea as to what?
$site[];
should be
$site = array();
I need some help figuring out why the following scenario does not work. I'm trying to retrieve a value from the last updated ID in mysql, then pass that value via javascript over to an ajax call which calls a .php page, which also calls another function "ZEND_emaiL" in a different php page.
In the very first php page that retrieves the id from mysql LAST_INSERT_ID(), if I hard code the value "100" it works, but if I use the value returned from LAST_INSERT_ID() it causes a failure.
Here's the php code for the LAST_INSERT_ID():
$sql='SELECT LAST_INSERT_ID();';
$last_updated_id = $db->get_var( $sql );
$last_updated_id = $last_updated_id+0;//make int
echo $last_updated_id; //send output back to the ajax call
var_dump($last_updated_id); ------------->RETURNS **int 149**
if I send back a hard coded "100" like this: echo 100; then it works.
Any ideas? Thanks for your help in advance.
The following are values retrieved from the php page that contains the ZEND_email() function. I grabbed these for debugging purposes hoping it would help.
RETURN VALUES for Hard Coded:
var_dump($n_id);---------->Returns **int 100**
var_dump($sqlresult);----->Returns **resource 24**
var_dump($row);----------->Returns **array of data to parse through**
RETURN VALUES FOR Passed in Variable (Fails):
function ZEND_email($to, $from="", $subject="", $msg="", $notif_id='', $root_dir="")
{
var_dump($notif_id);---------------------->RETURNS **string '100'**
$notif_id = $notif_id+0;//convert to int
var_dump($notif_id);---------------------->RETURNS **int 100**
$n_id = $notif_id;
$xsql = $sql_str->SQL_SELECT_all_notif_attachments($account_id, $n_id);
$sqlresult=mysql_query($xsql);
$row=mysql_fetch_row($sqlresult);
var_dump($n_id);---------------->RETURNS **int 100**
var_dump($sqlresult);----------->RETURNS **resource 24**
var_dump($row);----------------->RETURNS **boolean false**
}
you are aware that you could use mysql_insert_id() ?
see http://uk.php.net/manual/en/function.mysql-insert-id.php which would give you an INT value directly,
btw, to convert a variable to integer you can use:
$foo = (int) $bar
or
$foo = intval($bar);
or
$foo = settype($bar,'int');
Hard to tell from those code snippets. Better check what's going on on the client-side.
E.g. with firebug you can both check the actual response data and step into the javascript code.
Had to scrap this code...couldn't get it all to work with the feature for the app so we dropped it. Thanks for your help.
I have a tabled view in a while loop, where a user can view information on books.
For example, book ISBN, book name, read status...
Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this:
if ($readstatus == 'complete') {
echo '<tr class="completed">';
}
else if ($readstatus != 'complete') {
echo '<tr class="reading">';
}
I'm obviously doing something wrong here, table content to change if the value of 'readstatus' = 'complete', if not, then output is the default
Why are you using $_GET? Does this information come from an HTML form or a URL etc... ?
I suspect you meant to change $readstatus = $_GET['readstatus']; to $readstatus = $row['readstatus'];.
$_GET is an aray of GET parameters which come from the query string.
$row is a row in your database, so if the information is in the database - which I suspect it is - you want to use $row instead of $_GET.
Try changing $readstatus = $_GET['readstatus']; to $readstatus = $row['readstatus'];
The $_GET function relies on the value being contained in the query string of the URL, and it has nothing to do with the database. I have a hunch you're trying to get the value from the database here and you're using the wrong function to do it.
$_GET['readstatus'] says the value is coming from the browser.
$row['readstatus'] says the value is coming from the database.
You need to decide which should take precedence-- probably the $_GET['readstatus']` because it's what the user wants to change. If that's the case, you need to update your database with the new readstatus before you requery the db for the dataset.