I have the following php code:
//Usual mysqli stuff before here --> works
while($post = $result->fetch_assoc()) {
$post_text = (string)$post['post_text'];
$regex = "/(" . (string)$some_var . " - )(.*?)( [A-Z]{4})/";
}
echo $post_text . "<br />";
echo $regex . "<br />";
preg_match($regex, $post_text, $matches);
echo count($matches);
Unfortunately I don't get any results back, even though my regex seems to work with this tool here: http://www.phpliveregex.com/
I also tried to put the result manually in a string like this:
$my_string = "blablablablabla - proper stuff where the regex will find smth"
Using this string, the code works, but just not with the string I get back from the db. What am I doing wrong here?
Thx in advance.
Made it work myself. Problem was that the string contained new lines so I am running now the following regex on the stuff received from the db:
preg_replace('/\s+/', ' ', $post_text)
Related
I want to replace the first and last words and sentences .
I use this code.
$text = ' this is the test for string. ';
echo $text = str_replace(" ", "", $text);
when i have use replace code .
all space is deleted and repalsed.
any body can help me?!
i want get this:
this is the test for string.
You probably want the trim function here:
$text = ' this is the test for string. ';
echo '***' . trim($text) . '***';
***this is the test for string.***
Just to round out this answer, if you wanted to accomplish the same thing using a replacement, you could do a regex replace as follows:
$out = preg_replace("/^\s*|\s*$/", "", $text);
echo '***' . $out . '***';
***this is the test for string.***
This approach might a good starting point if you wanted to do a regex replacement with perhaps slightly different logic.
I need help with my PHP, I'm using str_ireplace() and I want to filter something out and replace it with what I have.
I find it hard to explain what I am talking about so I will give an example below:
This is what I need
$string = "<error> " . md5(rand(0, 1000)) . time() . " </error> Test:)";
then I want to remove and replace the whole <error> .... </error> with nothing.
So the end outcome should just print 'Test:)'.
Your question is not perfectly clear, but I believe I may understand what you are asking. This code may do the trick:
$string = " " . md5(rand(0, 1000)) . time() . " Test:)";
$newstring = preg_replace("/.*?\ /i", "", $string);
This uses regular expressions to filter out everything that comes before the space (and also removes the space)
I have some code running which finds out hashtags in the string and turns them into links. I have done this using preg_match_all as shown below:
if(preg_match_all('/(#[A-z_]\w+)/', $postLong, $arrHashTags) > 0){
foreach ($arrHashTags[1] as $strHashTag) {
$long = str_replace($strHashTag, ''.$strHashTag.'', $postLong);
}
}
Also, for my search script, I need to bold the searched keywords in the result string. Something similar to the below code using preg_replace:
$string = "This is description for Search Demo";
$searchingFor = "/" . $searchQuery . "/i";
$replacePattern = "<b>$0<\/b>";
preg_replace($searchingFor, $replacePattern, $string);
The problem that I am having is that both have to work together and should be thrown as a combined result. One way I can think of is to run the resultant string from preg_match_all with the preg_replace code but what if the tags and the searched string are the same? The second block will bold my tag as well which is not desired.
update the code i'm running based on the answer given below but it still doesn't work
if(preg_match_all('/(#[A-z_]\w+)/', $postLong, $arrHashTags) > 0){
foreach ($arrHashTags[1] as $strHashTag) {
$postLong = str_replace($strHashTag, ''.$strHashTag.'', $postLong);
}
}
And immediately after this, i run this
$searchingFor = "/\b.?(?<!#)" . $keystring . "\b/i";
$replacePattern = "<b>$0<\/b>";
preg_replace($searchingFor, $replacePattern, $postLong);
Just so you know, this is all going inside a while loop, which is generating the list
You just need to modify you the search pattern to avoid ones that start with a '#'
$postLong = "This is description for Search Demo";
if(preg_match_all('/(#[A-z_]\w+)/', $postLong, $arrHashTags) > 0){
foreach ($arrHashTags[1] as $strHashTag) {
$postLong = str_replace($strHashTag, ''.$strHashTag.'', $postLong);
}
}
# This expression finds any text with 0 or 1 characters in front of it
# and then does a negative look-behind to make sure that the character isn't a #
searchingFor = "/\b.?(?<!#)" . $searchQuery . "\b/i";
$replacePattern = "<b>$0<\/b>";
preg_replace($searchingFor, $replacePattern, $postLong);
Or if you don't need an array of the available hashes for another reason, you could use preg_replace only.
$postLong = "This is description for #Search Demo";
$patterns = array('/(#[A-z_]\w+)/', "/\b.?(?<!#)" . $searchQuery . "\b/i");
$replacements = array(''.$0.'', ' "<b>$0<\/b>');
preg_replace($patterns, $replacements, $postLong);
Hey there,
I have this little php code:
<p class="category_text"><? echo $category_text; ?></p>
I waht to split the $category_text and get something like this:
This is sentence 1 of category_text
This is sentence 2 of category_text
and so on...
$category_text has about 300 words and lets say 6 sentences. How could I split the text in multiple paragraphs (delimited by the stop sings ".")
Thank you very much!
echo '<p class="category_text">'
. implode('</p><p class="category_text">', explode('.',$string))
.'</p>';
You can just replace the "." by the tag "":
<p class="category_text"><? echo str_replace('.', '.<br />', $category_text); ?></p>
It's not a perfect solution! But if you text is simple enough this little trick should work.
For example if you have a line with 3 dots:
$category_text = "Ok...";
It will show up like that:
OK.
.
.
Also if your sentences finish by "?" or "!" you can also use that:
<p class="category_text"><? echo str_replace(array('.', '!', '?'), array('.<br />', '!<br />', '?<br />'), $category_text); ?></p>
PS: My solution will create one paragraph "" but with multiple line break
Try creating an array, and then output the lines one by one. A sentence ending in ... would still be recognized as still ends in ". ".
$sentences = explode('. ', $category_text)
foreach($sentences as $val)
{
echo $val . ".<br /><br />";
}
You want to split a text into sentences, which is not trivial - using explode(".", $string) does often not give good results.
Search Stackoverflow for "php split sentence", or directly try the solution to PHP: Parse document / text into sentences :
http://www.zubrag.com/scripts/text-splitter.php
Once you have an array with sentences, use
echo '<p>' . implode('</p><p>', $sentences) . '</p>';
to echo them out.
I'm looking to replace all occurrences of space characters that follow a new line (or occur at the beginning of the input string). I know that I can achieve this using preg_replace_callback() with a callback that uses str_repeat and strlen, or similarly with the /e switch; but was wondering if it could be done more simply.
Currently I have the following:
$testData = " Hello\n to everybody\n in the world";
echo preg_replace('/^|\n( )+/', ' ', $pValue);
which gives:
" Hello to everybody in the world"
What I'm really after is:
" Hello\n to everybody\n in the world"
I should have searched harder before asking: found the answer (for a java solution) that seems to work perfectly. I'll leave the solution here for the sake of anybody else that has the same problem.
$testData = " Hello\n to everybody\n in the world";
echo preg_replace('/(?m)(?:^|\\G) /', ' ', $pValue);
Now just need to identify whether older versions of PHP support this.
You can use recursion
$pValue = " Hello\n to everybody\n in the world";
echo myReplace($pValue);
function myReplace($value)
{
$value = preg_replace('/(^|\\n)(( )*) /', '\1\2 ', $value);
if (preg_match('/(^|\\n)(( )*) /', $value))
{
$value = myReplace($value);
}
return $value;
}