Old connection method mysql_connect maybe deprecated from PHP7 so what is the best way to connect and query in mysql using XAMPP or how I implement PDO in my bellow script.
<?php
$key = $_GET['key'];
$array = array();
$con = mysql_connect("localhost", "root", "");
$db = mysql_select_db("search", $con);
$query = mysql_query("select * from ajax_example where name LIKE '%{$key}%'");
while ($row = mysql_fetch_assoc($query)) {
$array[] = $row['name'];
}
echo json_encode($array);
?>
Database connection using mysqli_* :
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$database = "database";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $database);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
?>
For further mysqli_* statement syntax refer: Mysqli_* Manual
Database connection using PDO_* :
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$database = "database";
try {
$conn = new PDO("mysql:host=$servername;dbname=$database", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "Connected successfully";
}
catch(PDOException $e)
{
echo "Connection failed: " . $e->getMessage();
}
?>
For further PDO_* statement syntax refer PDO_* Manual
$conn = new Connection();
$query = "select * from ajax_example where name LIKE '%{$key}%'";
$res = $conn->execute_query($query)->fetchall(PDO::FETCH_ASSOC);
if (!empty($res))
{
$result['data'] = $res;
echo json_encode($result);
}
Related
I just noticed that i can not perform SQL updates when i am using PHP varibles from the link
My code (I don't noticed any errors, and no error output)
<?php
if ($_POST && isset($_POST['hdduid'], $_POST['status'])) {
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = 'L24wmc1nJBVP90q9yY';
$dbname = 'watt';
try {
// Try to connect
$dbh = new PDO(
'mysql:host='.$dbhost.';dbname='.$dbname,
$dbuser,
$dbpass
);
// Data
$hdduid = $_POST['hdduid'];
$status = $_POST['status'];
// query
$sql = "UPDATE users SET paid=':status' WHERE hdduid=':hdduid'";
$q = $dbh->prepare($sql);
$q->execute(array(
':message' => $message,
':email' => $email
));
// Null connection
$dbh = null;
} catch (PDOException $e) { // if exception
print "Error!: " . $e->getMessage() . "<br/>";
die();
}
?>
I edited the code, it still wont working
You need to use
mysqli_real_escape_string
Not
mysql_real_escape_string
You can not mix mysql with MySQLi
Here is another solution using prepared statements.
$servername = "localhost";
$username = "root";
$password = "L24wmc1nJBVP90q9yY";
$dbname = "ft";
// Create connection
$connection = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($connection->connect_error) {
die("Connection failed: " . $connection->connect_error);
}
$paid = $_GET["status"];
$hdduid = $_GET["hdduid"];
//Prepared statements
$statement = $connection->prepare("UPDATE users SET paid = ? WHERE hdduid = ?");
$statement->bind_param("ss", $paid, $hdduid);
if(!$statement->execute()) {
echo "Error updating record: " . $statement->error;
} else {
echo "Record updated successfully";
}
$statement->close();
$connection->close();
Here is a solution. It uses mysqli_real_escape_string instead of mysql_real_escape_string. I also changed the name of $status to $paid for better readability. Good luck!
$servername = "localhost";
$username = "root";
$password = ""; //$password = "L24wmc1nJBVP90q9yY";
$dbname = "test"; //$dbname = "ft";
// Create connection
$connection = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($connection->connect_error) {
die("Connection failed: " . $connection->connect_error);
}
$hdduid = $_GET["hdduid"];
$paid = $_GET["status"];
$sql = "UPDATE users SET paid='$paid' WHERE hdduid='$hdduid'";
if ($connection->query($sql) === TRUE) {
echo "Record updated successfully";
} else {
echo "Error updating record: " . $connection->error;
}
$connection->close();
I am trying to retrieve data from my database using PDO Fetch object and it says
Fatal error: Uncaught Error: Call to undefined method mysqli_result::execute()
what I'm doing wrong
This is what I have tried
<?php
$servername = "localhost"; $username = "root"; $password = ""; $dbname = "messages_db";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$getquery = $conn->query('select col_name from db where id = 2');
$getquery->execute();
$result = $getquery->fetch(PDO::FETCH_OBJ);
?>
<div><?= $result->col_name; ?></div>
Firstly, don't mix PDO and mysqli. Stick to one. Here's a PDO example. You first need to create a new PDO object. and connect to DB at the start
$servername = "localhost";
$dbusername = "root";
$dbpassword = "root";
$dbname = "dbname";
try{
$pdo = new PDO("mysql:host=$servername;dbname=$dbname",$dbusername,
$dbpassword);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $e)
{
print "Error! Unable to connect: " . $e->getMessage() . "<br/>";
die();
}
$rtrv = "select col_name from db where id = 2"
$stmt = $pdo->prepare($rtrv);
//Execute.
$stmt->execute();
//Fetch.
$user = $stmt->fetch(PDO::FETCH_ASSOC);
// Do whatever you want after this
I have written following code to connect mysql in php but I am not getting output.
<?php
$servername = "localhost";
$username = "root";
$password = "pravin";
$mysql_conn = new mysqli($servername, $username, $password);
if ($mysql_conn->connect_error) {
die("Connection failed: ". $mysql_conn->connect_error);
}
echo "Connected successfully";
$name = $_POST["microorganism"];
echo $name;
$db_selected = mysql_select_db('yieldofvanillin', $mysql_conn);
if (!$db_selected){
die ('Can\'t use : ' . mysql_error());
}
$query = "SELECT * FROM vanillin WHERE Microorganism = '$name' ";
$result = $mysql_query($query);
while ($line = myql_fetch_array($result, MYSQL_ASSOC)) {
echo $line["Substrate"];
echo $line["products"];
echo $line["Microorganism"];
echo $line["yield"];
echo $line["Reference"];
}
mysql_close($mysql_conn);
?>
The database name is "yieldofvanillin" and it has five column. I an getting output Connected successfully. After that no output. Please let me know the bug in code.
i have remove errors. which i mention in comments. Code Reference PHP Manual. you should read this manual (strongly recommended)
<?php
$mysqli = new mysqli("localhost", "root", "pravin", "yieldofvanillin");
/* check connection */
if ($mysqli->connect_errno) {
printf("Connect failed: %s\n", $mysqli->connect_error);
exit();
}
$query = "SELECT * FROM vanillin WHERE Microorganism = '$name' ";
if ($result = $mysqli->query($query)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
echo $row["Substrate"];
echo $row["products"];
echo $row["Microorganism"];
echo $row["yield"];
echo $row["Reference"];
}
/* free result set */
$result->free();
}
you're mixing mysqli and mysql libraries.
the code should be:
<?php
$servername = "localhost";
$username = "root";
$password = "pravin";
$mysql_conn = new mysqli($servername, $username, $password);
if (mysqli_connect_errno()) {
die("Connection failed: ". mysqli_connect_error());
}
echo "Connected successfully";
$name = $_POST["microorganism"];
echo $name;
$db_selected = mysqli_select_db($mysql_conn,'yieldofvanillin');
if (!$db_selected){
die ('Can\'t use : ' . mysqli_error($mysql_conn));
}
$query = "SELECT * FROM vanillin WHERE Microorganism = '$name' ";
$result = mysqli_query( $mysql_conn,$query);
while ($line = mysqli_fetch_assoc($result)) {
echo $line["Substrate"];
echo $line["products"];
echo $line["Microorganism"];
echo $line["yield"];
echo $line["Reference"];
}
mysqli_close($mysql_conn);
?>
Remove error in your code.Read carefully php manual.
<?php
$servername = "localhost";
$username = "root";
$password = "pravin";
$db = "yieldofvanillin";
// Create connection
$mysqli = new mysqli($servername, $username, $password, $db);
/* connection string*/
if ($mysqli->connect_errno) {
die("Connection failed: " . $mysqli->connect_error);
exit();
}
$query = "SELECT * FROM vanillin WHERE Microorganism = '$name' ";
if ($result = $mysqli->query($query)) {
while ($row = $result->fetch_assoc()) {
echo $row["Substrate"];
}
$result->free();
}
$mysqli->close();
?>
Your output not showing because mysql_fetch_array is not correct.Because you are mixing mysql_ and mysqli_ functions and you called myql_fetch_array that doesn't exist in mysqli. MySQL and MySQLi are two different PHP extensions and they cannot be mixed. Because the former is deprecated in mysqli
I've set up a database using MAMP.
When I try the following test, I only receive a blank page. Fairly new to this, and I've tried different suggestions found on the web with no luck.
Tried using both port and socket.
<?php
$user = 'root';
$password = 'root';
$db = 'test';
$host = 'localhost';
$port = 3306;
$socket = "/Applications/MAMP/tmp/mysql/mysql.sock";
$link = mysql_connect(
"$host:$socket",
$user,
$password
);
$db_selected = mysql_select_db(
$db,
$link
);
if (!$link){
echo "ERROR";
}
else {
echo "Success";
}
mysql_close($link);
?>
<?php
$servername = "localhost";
$username = "root";
$password = "root";
try {
$conn = new PDO("mysql:host=$servername;test", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo "Connected successfully";
}
catch(PDOException $e)
{
echo "Connection failed: " . $e->getMessage();
}
?>
Would you like to try PDO ?!
<?php
$dsn = "mysql:host=localhost;dbname=databasenamehere";
$user = 'root';
$pass = '';
$option = array(
PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8',
);
try {
$connect = new PDO($dsn, $user, $pass,$option);
$connect->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION);
}
catch (PDOException $r) {
echo 'Failed' . $r->getMessage();
}
this is my first php code , i am trying to connect to a database with user name = "root" and password = "root"
i have a connection file called dbConnection.php
as following :
<?php
echo "in connection file";
$hostname = "localhost";
$username = "root";
$password = "root";
$db = "ledDB";
echo "<br> db-connection : vars definde ";
//connection to the database
$conn = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
echo "Connected to MySQL<br>";
echo "db-connection : initilize connection ";
mysql_select_db($db);
echo "db-connection : connection done";
// Check connection
echo "Connected successfully";
?>
and i call it in a file called what.php :
<?php
echo "Hello";
include "dbConnection.php";
echo "ohhhh";
?>
this returns status code 500 which is internal server error
but i want to know what is the error to fix it how can i get the error message ?
i tried
$conn = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
but it is not returning any thing.
can any one help me please ?
if you are having password on localhost then use password otherwise leave it blank
$con = mysqli_connect("localhost","root","yourpassword","yourdb");
You mysqli_connect() method.
<?php
echo "in connection file";
$hostname = "localhost";
$username = "root";
$password = "root";
$db = "ledDB";
echo "<br> db-connection : vars definde ";
//connection to the database
$conn = mysqli_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
echo "Connected to MySQL<br>";
echo "db-connection : initilize connection ";
mysqli_select_db($conn,$db);
echo "db-connection : connection done";
// Check connection
echo "Connected successfully";
?>
First Thing is to Change your connection method to mysqli or my personal favorite PDO.
PDO Example:
class db extends pdo{
//Website Variables
public $sitedb = '';
public $siteconfig;
public $sitesettings = array(
'host' => 'localhost',
'database' => 'yourdb',
'username' => 'youruser',
'password' => 'yourpass',
);
public function __construct(){
$this->sitedb = new PDO(
"mysql:host={$this->sitesettings['host']};" .
"dbname={$this->sitesettings['database']};" .
"charset=utf8",
"{$this->sitesettings['username']}",
"{$this->sitesettings['password']}"
);
$this->sitedb->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC);
}
}
$db = new db();
Then you can extend your PDO class to new classes after including the db.php page.
Example Select:
class yourclass extends db {
public function SelectUsers() {
global $db;
$query = <<<SQL
SELECT email
FROM users
WHERE active = :active
SQL;
$resource = $db->sitedb->prepare( $query );
$resource->execute( array (
':active' => 1,
));
$count = $resource->rowCount();
foreach($resource as $user){
$this->email = $user['email'];
}
}
}
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "mydb";
// Create connection
$conn = mysqli_connect($servername, $username, $password);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
// make the current db
$db_selected = mysqli_select_db ( $conn , $dbname );
if (!$db_selected) {
die ('Can\'t connect to Database : ' . mysql_error());
}
?>