Setting and retrieving values from an array with Checkboxes in PHP - php

Question

I'm trying to place a value and retrieve it later on
$fruits = array("Watermelon", "Lime", "Lemon");
$result = count($fruits);
$i = 0;
while ($i < $result) {
echo "<br>" . "<input type='checkbox' name='fruit[]' value='$fruits[$i]'>";
echo "$fruits[$i]";
$i++;
}
The first set I assigned the fruit to the value per the array, the code below is supposed to set the values in the if statement and compare them to the checkbox. If I put in the fruit by name it works e.g. "Watermelon" works but "$fruits[0]" does not.
if ($_SERVER["REQUEST_METHOD"] == "POST") {
if(isset($_POST["fruit"])){
$i = 0;
while($i < $result) {
if(in_array('$fruits[$i]', $_POST['fruit'])){
echo "It works!";
$i++;
} else {
$i++;
}
}
} else {
echo "choose a box";
$i = $result;
}

Answer 1

You can do this easily with foreach()(if you want to).
if(isset($_POST['fruit'])) {
foreach($_POST['fruit'] as $fruit) {
$fruits[] = $fruit;
}
if(!empty($fruits)) {
echo 'It Works.!';
} else {
echo "choose a box";
}
}

Answer 2

You use $i++ in work condition so if will increase $i to 1 until last index of $fruits ,if $fruits last index is not exist in $_POST it will nothing display.. use exit can be display.
if(isset($_POST["fruit"])){
$i = 0;
while($i < $result) {
if(in_array($fruits[$i],$_POST['fruit'])){
echo "It works!";
exit;
} else {
$i++;
}
}
}
Also no need to quote in your array...
if(in_array('$fruits[$i]', $_POST['fruit'])) //remove ''