PHP posting values but database not updating [duplicate] - php

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PHP's white screen of death [duplicate]
Closed 6 years ago.
I'm having a problem where my form is submitting the values but they aren't getting entered into the database?
I have tried echo'ing the $_POST to see what is getting posted and everything is posting as it should but its failing at the point of entering into the database.
Here is my code
if(isset ($_POST["update_detail"])) {
foreach($_POST["id"] AS $id) {
$name = mysqli_real_escape_string($_POST["name"][$id]);
$age = mysqli_real_escape_string($_POST["age"][$id]);
$update1 = "UPDATE `booked_peoples` SET `name` = '$name',`age` = '$age' WHERE `booked_peoples`.`id` = ".$id;
$update2 = mysqli_query($con,$update1);
if($update2){
echo '<script>window.location.href="add_passengers.php?book_id='.$book_id.'";</script>';
}
else {
echo 'OOPS';
} } }
and here is the php form code
if(isset($_GET['book_id']) and $_GET['action']=='edit')
{
$sq_edit_ps = "select * from booked_peoples where booking_id = ".$book_id;
$qr_edit_ps = mysqli_query($con,$sq_edit_ps);
while($rw_edit_ps = mysqli_fetch_array($qr_edit_ps))
{
$ps_id = $rw_edit_ps['id'];
echo '<form action="" method="POST" role="form">';
echo '<div class="row">
<div class="col-sm-9">
<label>Name</label>
<input class="form-control" type="text" name="name['.$ps_id.']" value="'.$rw_edit_ps['name'].'"/>
</div>
<div class="col-sm-3">
<label>Age</label>
<input class="form-control" type="text" name="age['.$ps_id.']" value="'.$rw_edit_ps['age'].'"/>
<input type="hidden" name="id[]" value="'.$ps_id.'"/>
</div>
</div>';
}
echo '
<button class="btn btn-info btn-flat" type="submit" name="update_detail" >Update</button>
</form>
</div>';
}
Im getting code blind.......:(

Answer 1

It was the mysql_real_escape_string that was stopping it form working.
It needed to be $name = mysqli_real_escape_string($con, $_POST["name"][$id]);
Thank you to the poster above for pointing it out :)
Wanted to post the solution in case anyone else comes across the same problem