PHP and Swift : Fatal error on password_hash() - php

Question

I have set up my sign up and sign in php files they're on the server and it works with my swift app. I can sign in and sign up easily. But when i added the password_hash() method to had security to the user password it gives an error on Xcode when I try to sign up. Is there any other way to have a store the password securely if this doesn't work anymore. Yes I have php 5.5.34 installed:
error via Xcode:
DATA: <br />
<b>Fatal error</b>: Call to undefined function password_hash() in <b>/*/*/public_html/*/signup.php</b> on line <b>92</b><br />
signup.php
// Hash password and insert new user to table
$hashPassword = password_hash($password, PASSWORD_DEFAULT);
$command = " INSERT INTO USER
(firstname, lastname, username, email, password)
VALUES
('$firstname', '$lastname', '$username', '$email', '$hashPassword')";
if ( mysqli_query($DB, $command) ) {
// Search for newUser
$command = "SELECT * FROM USER WHERE username = '$username'";
$sql = mysqli_query($DB, $command);
if ( mysqli_num_rows($sql) != 0 ) {
$newUser = mysqli_fetch_array($sql);
$returnData["status"] = "200";
$returnData["message"] = "Success!";
$returnData["ID"] = $newUser["ID"];
$returnData["firstname"] = $newUser["firstname"];
$returnData["lastname"] = $newUser["lastname"];
$returnData["username"] = $newUser["username"];
$returnData["email"] = $newUser["email"];
}
echo json_encode($returnData);
return;
} else {
$returnData["status"] = "400";
$returnData["message"] = "Sorry, something must've went wrong. Please try again...";
echo json_encode($returnData);
return;
}
signin.php
// Find user from table and sign in
$command = "SELECT * FROM USER WHERE email = '$email'";
$sql = mysqli_fetch_array( mysqli_query($DB, $command) );
if ( isset($sql) ) {
$hashPassword = $sql["password"];
if ( password_verify($password, $hashPassword) ) {
$returnData["status"] = "200";
$returnData["message"] = "Success!";
$returnData["ID"] = $sql["ID"];
$returnData["username"] = $sql["username"];
}
echo json_encode($returnData);
return;
} else {
$returnData["status"] = "400";
$returnData["message"] = "Sorry, something must've went wrong. Please try again...";
echo json_encode($returnData);
return;
}

Answer 1

You can use this library to get the password_*() functions. Also provides < PHP 5.5 support.