I would like to randomize the order of my json objects. Here is the output:
And here is my code so far:
// check for empty result
if (mysql_num_rows($result1) > 0) {
// looping through all results
// products node
while ($row = mysql_fetch_array($result1)) {
// temp user array
$feedMain["user_id"] = $row["user_id"];
// push single product into final response array
array_push($response["feedMain"], $feedMain);
}
// success
$response["success"] = 1;
}
// check for empty result
if (mysql_num_rows($result2) > 0) {
// looping through all results
// products node
while ($row = mysql_fetch_array($result2)) {
// temp user array
$feedMain["user_id"] = $row["user_id"];
// push single product into final response array
array_push($response["feedMain"], $feedMain);
}
// success
$response["success"] = 1;
}
// check for empty result
if (mysql_num_rows($result3) > 0) {
// looping through all results
// products node
while ($row = mysql_fetch_array($result3)) {
// temp user array
$feedMain["user_id"] = $row["user_id"];
// push single product into final response array
array_push($response["feedMain"], $feedMain);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response, JSON_UNESCAPED_UNICODE);
}
I tried something like :
echo json_encode(shuffle($response), JSON_UNESCAPED_UNICODE);
and other code snippets but nothing won't work for me..
I just want to randomize the order of the json objects. Thanks.
result1,2 and 3 are mysql statements :)
shuffle will not walk the array deeply. What you should shuffle is $response["feedMain"]:
shuffle($response["feedMain"]);
echo json_encode($response, JSON_UNESCAPED_UNICODE);
Related
I am fetching data from the database, and while I'm fetching, I check for each result if it matches certain criteria, if it does, I want it to add the row with all the details as a new object inside the same JSON, so that I end up with a single JSON that holds all the matching rows
while ($result = $stmt->fetch(PDO::FETCH_ASSOC)) {
if (matching criteria){
//add row to the JSON
}
}
Right now I can add each row and echo it, but it overwrites the previous row:
while ($result = $stmt->fetch(PDO::FETCH_ASSOC)) {
if (matching criteria){
$firstColumn = $result['firstColumn'];
$secondColumn= $result['secondColumn'];
//more columns if necessary. . .
$myObj->firstColumn = $firstColumn ;
$myObj->secondColumn= $secondColumn;
$myJSON = json_encode($myObj);
echo $myJSON;
}
}
you can use PDO::fetch_object for ever row and add them to assoc array/another object and then use the json_encode on it.
something like (pseudocode not tested) it will create json array with object for every row:
$out = [];
while($result = $stmt->fetch(PDO::FETCH_OBJ)
{
if(matching){
$out[] = $result;
}
}
echo json_encode($out);
Try this way create a array assign value to that array with myObj Data and after get collection of array convert into Json object
$data = array(array());
$i = 0;
$j = 0;
while ($result = $stmt->fetch(PDO::FETCH_ASSOC)) {
if (matching criteria){
$firstColumn = $result['firstColumn'];
$secondColumn= $result['secondColumn'];
//more columns if necessary. . .
$myObj->firstColumn = $firstColumn ;
$myObj->secondColumn= $secondColumn;
$data[i][j]=$firstColumn;
$j++;
$data[i][j]=$secondCoulmn;
$i++;
$j--;
}
}
$myJSON = json_encode($data);
echo $myJSON;
I need json response in different array, but below code not give all the result.
while ($row=mysqli_fetch_assoc($result))
{
//$data[]=$row;
$data['id']=$row['id'];
$data['name']=$row['name'];
$data['Latitude']=$row['Latitude'];
$data['Longitude']=$row['Latitude'];
$lat_user=$row['Latitude'];
$long_user=$row['Longitude'];
$res=file_get_contents("https://maps.googleapis.com/maps/api/distancematrix/json".
"?units=imperial&origins=$lat,$long&destinations=$latuser,$longuser");
$json_res=json_decode($res);
$data['time']=$json_res->{'rows'}{0}->{'elements'}{0}->{'duration'}->{'text'};
}
echo json_encode($data,true);
You need to save your items into some array, e.g $dataArray at the end of each iteration and after cycle use this array to create json
$dataArray = array();
while ($row=mysqli_fetch_assoc($result))
{
//$data[]=$row;
$data['id']=$row['id'];
$data['name']=$row['name'];
$data['Latitude']=$row['Latitude'];
$data['Longitude']=$row['Latitude'];
$lat_user=$row['Latitude'];
$long_user=$row['Longitude'];
$res=file_get_contents("https://maps.googleapis.com/maps/api/distancematrix/json".
"?units=imperial&origins=$lat,$long&destinations=$latuser,$longuser");
$json_res=json_decode($res);
$data['time']=$json_res->{'rows'}{0}->{'elements'}{0}->{'duration'}->{'text'};
$dataArray[] = $data;
}
echo json_encode($dataArray,true);
I am developing in PHP/MS SQL for getting JSON Response.
Code which I wrote is:
while( $result = sqlsrv_fetch_object($sql_Gpo_Carr)) {
$array_res[] = $result; // add result to array
array_push($array_res, array('unidad' => $uni)); // add extra element
$jsonObj = json_encode($array_res); // encode JSON
}
echo $jsonObj;
exit();
This is what I want in result:
[{"idperiodo":"37","idgrupo":"1963","idhorario":"12832","unidades":null,"unidad":1}]
but the result shows me this:
[{"idperiodo":"37","idgrupo":"1963","idhorario":"12832","unidades":null},{"unidad":1}]
You're fetching an object. Add $uni to $result first and then add to $array_res:
while( $result = sqlsrv_fetch_object($sql_Gpo_Carr)) {
$result->unidad = $uni;
$array_res[] = $result;
}
Also, you probably want the json_encode() after the loop not in the loop:
echo json_encode($array_res);
I'm creating an app that parses json feeds into a listactivity. I've read that new items are added at the bottom of a listview and this is the case in my app. I'm trying to remedy this by sorting the output of my json by id in descending order. Don't know if this will fix my problem or I need to remedy it in my java code. Part one of my question is, will changing the order of output from the database change the order in which the feeds are displayed in the app? If so, I've tried to modify my php script by following the examples on http://php.net/manual/en/function.usort.php but the order doesn't change. Part two, What am I doing wrong in the following php script?
<?php
require("config.inc.php");
$query_params=null;
//initial query
$query = "Select * FROM feeds";
//execute query
try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error!";
die(json_encode($response));
}
// Finally, retrieve all of the found rows into an array using fetchAll
$rows = $stmt->fetchAll();
if ($rows) {
$response["feed"] = array();
foreach ($rows as $row) {
$post = array();
$post["id"] = $row["id"];
$post["name"] = $row["name"];
$post["status"] = $row["status"];
//update our repsonse JSON data
array_push($response["feed"], $post);
}
function cmp($a, $b)
{
if ($a->id == $b->id) {
return 0;
}
return ($a->id > $b->id) ? -1 : 1;
}
$a = array();
usort($a, "cmp");
// echoing JSON response
echo json_encode($response, JSON_NUMERIC_CHECK);
} else {
$response["success"] = 0;
$response["message"] = "No Post Available!";
die(json_encode($response));
}
?>
Looks like you are calling usort on an empty array, instead of the data that you actually want to sort.
Instead of
$a = array();
usort($a, "cmp");
Try
$a = $response['feed'];
usort($a, "cmp");
$response['feed'] = $a;
Blackbelt is right that you can't technically sort a JSON array, at least one with sequential indexes (which results in no indexes at all). In practice, though, when you iterate through the resulting object on the client side, it will be in the order it was defined, so sorting it server-side should not raise any issues.
This question already has answers here:
JSON encode MySQL results
(16 answers)
Closed 1 year ago.
I've spent a couple of hours looking through several the similar answers before posting my problem.
I'm retrieving data from a table in my database, and I want to encode it into a JSON. However, the output of json_encode() is only valid when the table has one single row. If there is more than one row, the test at http://jsonlint.com/ returns an error.
This is my query:
$result = mysql_query($query);
$rows = array();
//retrieve and print every record
while($r = mysql_fetch_assoc($result)){
$rows['data'] = $r;
//echo result as json
echo json_encode($rows);
}
That gets me the following JSON:
{
"data":
{
"entry_id":"2",
"entry_type":"Information Relevant to the Subject",
"entry":"This is my second entry."
}
}
{
"data":{
"entry_id":"1",
"entry_type":"My Opinion About What Happened",
"entry":"This is my first entry."
}
}
When I run the test at http://jsonlint.com/, it returns this error:
Parse error on line 29:
..."No comment" }}{ "data": {
---------------------^
Expecting 'EOF', '}', ',', ']'
However, if I only use this first half of the JSON...
{
"data":
{
"entry_id":"2",
"entry_type":"Information Relevant to the Subject",
"entry":"This is my second entry."
}
}
... or if I only test the second half...
{
"data":{
"entry_id":"1",
"entry_type":"My Opinion About What Happened",
"entry":"This is my first entry."
}
}
... the same test will return "Valid JSON".
What I want is to be able to output in one single [valid] JSON every row in the table.
Any suggestion will be very much appreciated.
The problem is you're spitting out separate JSON for each row, as opposed to doing it all at once.
$result = mysql_query($query);
$rows = array();
//retrieve and print every record
while($r = mysql_fetch_assoc($result)){
// $rows[] = $r; has the same effect, without the superfluous data attribute
$rows[] = array('data' => $r);
}
// now all the rows have been fetched, it can be encoded
echo json_encode($rows);
The minor change I've made is to store each row of the database as a new value in the $rows array. This means that when it's done, your $rows array contains all of the rows from your query, and thus you can get the correct result once it's finished.
The problem with your solution is that you're echoing valid JSON for one row of the database, but json_encode() doesn't know about all the other rows, so you're getting a succession of individual JSON objects, as opposed to a single one containing an array.
You need to change your PHP code into something like this:
$result = mysql_query($query);
$rows = array();
//retrieve every record and put it into an array that we can later turn into JSON
while($r = mysql_fetch_assoc($result)){
$rows[]['data'] = $r;
}
//echo result as json
echo json_encode($rows);
I think you should do
$rows = array();
while($r = mysql_fetch_assoc($result)){
$rows[]['data'] = $r;
}
echo json_encode($rows);
echo should be placed outside of the loop.
I was trying the same in my PHP, so I came whit this...
$find = mysql_query("SELECT Id,nombre, appaterno, apmaterno, semestre, seccion, carrera FROM Alumno");
//check that records exist
if(mysql_num_rows($find)>0) {
$response= array();
$response["success"] = 1;
while($line = mysql_fetch_assoc($find)){}
$response[] = $line; //This worked for me
}
echo json_encode($response);
} else {
//Return error
$response["success"] = 0;
$response["error"] = 1;
$response["error_msg"] = "Alumno could not be found";
echo json_encode($response);
}
And, in my Android Class...
if (Integer.parseInt(json.getString("success")) == 1) {
Iterator<String> iter = json.keys();
while (iter.hasNext()) {
String key = iter.next();
try {
Object value = json.get(key);
if (!value.equals(1)) {
JSONObject jsonArray = (JSONObject) value;
int id = jsonArray.getInt("Id");
if (!db.ExisteAlumo(id)) {
Log.e("DB EXISTE:","INN");
Alumno a = new Alumno();
int carrera=0;
a.setId_alumno(id);
a.setNombre(jsonArray.getString("nombre"));
a.setAp_paterno(jsonArray.getString("appaterno"));
a.setAp_materno(jsonArray.getString("apmaterno"));
a.setSemestre(Integer.valueOf(jsonArray.getString("semestre")));
a.setSeccion(jsonArray.getString("seccion"));
if(jsonArray.getString("carrera").equals("C"))
carrera=1;
if(jsonArray.getString("carrera").equals("E"))
carrera=2;
if(jsonArray.getString("carrera").equals("M"))
carrera=3;
if(jsonArray.getString("carrera").equals("S"))
carrera=4;
a.setCarrera(carrera);
db.addAlumno(a);
}
}
} catch (JSONException e) {
// Something went wrong!
}
}
I must have spent 15 hours on this issue. Every variation discussed above was tried. Finally I was able to get the 'standard solution' working. The issue, very oddly, appears to be this:
When the interval is set beyond 14 hours, json appears to be unable to parse it. There must be a limit to JSON.
$sql= "SELECT cpu_name, used, timestamp FROM tbl_cpu_use WHERE timestamp>(NOW() - INTERVAL 14 HOUR) ORDER BY id";
$result=mysql_query($sql);
if ($result){
$i=0;
$return =[];
while($row = mysql_fetch_array($result, MYSQL_NUM)){
$rows[] = $row;
}
echo json_encode($rows);
}else{
echo "ERROR";
}