I really Dont know What should I do the problem is that $_Files is always empty when I try to upload a file.
<form method="get" action="pic.php" enctype="multipart/form-data">
<input type="file" name="file">
<input type="submit" name="submit">
</form>
<?php
$name=$_FILES["file"]["name"];
$tmp_name=$_FILES["file"]["tmp_name"];
echo "php is talking";
echo $name;
if(isset($name)&&!empty($name))
{
echo "OK";
$location="uploads/";
if(move_uploaded_file($name,$location.$name))
{
echo "the file has been Uploaded";
}
}
?>
You have to change the HTTP method in the form from GET to POST
<form method="POST" action="pic.php" enctype="multipart/form-data">
Related
I'm trying to take posted input file name, I'm not uploading anywhere.
I just need the name of posted filename so I'm trying this code;
<form method="post" enctype="multipart/form-data" role="form">
<input type="file" id="file" name="file">
<input type="submit" name="submit" value="Submit Form">
</form>
<?php
if(isset($_POST['submit'])){
echo $_FILES['file'];
}
?>
If I change enctype="multipart/form-data" into form tag, it's ok, but I need this tag.
You still need the enctype attribute, as the files will not be available without it.
if (isset($_POST['submit'])) {
echo $_FILES['file']['name'];
}
use
echo $_FILES['file']['name'];
instead of
echo $_FILES['file'];
$_FILES['file'] contains array of properties of uploaded file. use print_r instead. It will work fine.
you can get file name like that
$name = $_FILES['file']['name'];
this code is working fine
<form method="post" enctype="multipart/form-data" role="form">
<input type="file" id="file" name="file">
<input type="submit" name="submit" value="Submit Form">
</form>
<?php
if(isset($_POST['submit'])){
echo "<pre>";
print_r($_FILES['file']) ;
}
?>
All of my other form data is visible, but the name of the file is not showing up in the browser.
Here is a little portion of my code:
<form method="POST" action=<?php echo $_SERVER["PHP_SELF"];?> entype="multipart/form-data">
<input type="file" name="file">
<input type="submit" name="file" value="yoyo">
</form>
<?php
echo $name = $_FILES["file"]["name"];
echo "problem";
?>
and this is the output:
Notice: Undefined index: file in D:\xamp\htdocs\colgWeb\index.php on line 228
problem
Use a validator: You misspelled enctype (it has a c in it).
Consequently, the form is being submitted with the default (url based) encoding which doesn't support file uploads.
You need to think that as a two step page. First, you send your form, then you use the input.
<form method="POST" action="<?php echo $_SERVER["PHP_SELF"];?>" enctype="multipart/form-data">
<input type="file" name="file">
<input type="submit" name="file" value="yoyo">
</form>
<?php
if (isset($_FILES["file"]))
{
$name = $_FILES["file"]["name"];
echo "File: $name";
}
?>
Please try below code. You are using same name (ie "file") for both file and submit button."
<form method="POST" action=<?php echo $_SERVER["PHP_SELF"];?> entype="multipart/form-data">
<input type="file" name="file">
<input type="submit" name="submit" value="yoyo">
</form>
<?php
echo $name = $_FILES["file"]["name"];
echo "problem";
?>
I have a form where multiple images can be selected...
HTML
<form action="" method="post" enctype="multipart/form-data">
<input type="text" name="name" class="form-field" placeholder="First Name">
<input type="file" name="files[]" multiple accept="image/*" class="form-field">
<input type="submit" value="UPLOAD" class="button" name="submit4">
</form>
Then, in my PHP I want to detect if at least 1 file has been uploaded.... I tried this, but the code still triggers as if a file was uploaded...
if(isset($_POST['submit4']) and $_SERVER['REQUEST_METHOD'] == "POST")
{
echo "post sucessful<br>";
if(is_uploaded_file($_FILES['files']['temp_name']))
{ echo "file exist";}
else{ echo "no file";}
}
THIS always triggers the "no file" even if there is a file..
and if I try:
if(!empty($_FILES['files']['temp_name']))
it always triggers the "no file" ... I'm really confused...
You can use following code
if(!file_exists($_FILES['files']['tmp_name']) || !is_uploaded_file($_FILES['files']['tmp_name'])) {
echo "No File";
}
else{
echo "Successfully uploaded";
}
Found my answer...
if(!empty($_FILES['files']['name'][0]))
works quit well... thanks everyone.
Hi Hi trying to upload a file via a form move it to another folder and then print its name. But doesnt work don't know why.
<form method="post" action='exercice.php' id="form1">
<input type="file" name="files" id="files" onChange="submitForm();">
</form>
<?php
if (isset($_FILES['files']))
{
move_uploaded_file($_FILES['files']['tmp_name'], "uploaded/");
echo $_FILES['files']['name'];
}
?>
form missing:
enctype="multipart/form-data"
ref:
spec
<form method="post" action='exercice.php' id="form1">
<input type="file" name="files" id="files" onChange="submitForm();">
</form>
<?php
if (isset($_FILES['files']))
{
move_uploaded_file($_FILES['files']['tmp_name'], "uploaded/".$_FILES['files']['name']);
echo $_FILES['files']['name'];
}
?>
You need to include the file name in the upload path, like shown above.
Also, where is your upload (ajax) code?
Did isset($_FILES['files']) return true?
I am trying to get image file name by tag, But when I check it through isset($_FILES['imgFile']), it returns always false.
Here is my HTML tag for getting image file:
<input type="file" name="imgFile" accept="image/*" id="imgFile" src=""/>
Here is my php code to retrieve it:
if(isset($_FILES['imgFile']))
{
$img = $_FILES['imgFile']['name'];
echo $img";
}
else
{
echo "Image not set";
}
It always generate "Image not set" as an output though I have selected an image.
Are you using the correct enctype on the form?
<form enctype="multipart/form-data">
This is required when using a file upload element.
just use:
enctype="multipart/form-data"
Say this is your form:
<form action="same_page.php" method="post" enctype="multipart/form-data">
<input type="file" name="imgFile" accept="image/*" id="imgFile" src=""/>
<input type="submit" name="upload" value="Upload" />
</form>
and your php code to retrive name of the image is in the same page where the form is, then your code should be like this:
<?php
if (isset($_POST["upload"])) {
if (isset($_FILES['imgFile'])) {
$img = $_FILES['imgFile']['name'];
echo $img;
} else {
echo "Image not set";
}
}
?>
But if your php code is in another page, then you only need to use enctype="multipart/form-data" in the form as mentioned in the other answers.