I am trying with server side script datatable where I need to add images inside the table. The image path is stored inside the database. I need to display the images in my page. How can I add images in the page. Here is the code.I want the images to be displayed using mysqli and ajax.
<?php
//include connection file
include_once("connection.php");
// initilize all variable
$params = $columns = $totalRecords = $data = array();
$params = $_REQUEST;
//define index of column
$columns = array(
0 =>'id',
1 =>'name',
2=>'images',
3 => 'year',
4 => 'rank'
);
$where = $sqlTot = $sqlRec = "";
// check search value exist
if( !empty($params['search']['value']) ) {
$where .=" WHERE ";
$where .=" (name LIKE '".$params['search']['value']."%' ";
$where .=" OR year LIKE '".$params['search']['value']."%' ";
$where .=" OR id LIKE '".$params['search']['value']."%' ";
$where .=" OR rank LIKE '".$params['search']['value']."%' )";
}
// getting total number records without any search
$sql = "SELECT * FROM `search` ";
$sqlTot .= $sql;
$sqlRec .= $sql;
//concatenate search sql if value exist
if(isset($where) && $where != '') {
$sqlTot .= $where;
$sqlRec .= $where;
}
$sqlRec .= " ORDER BY ". $columns[$params['order'][0]['column']]." ".$params['order'][0]['dir']." LIMIT ".$params['start']." ,".$params['length']." ";
$queryTot = mysqli_query($conn, $sqlTot) or die("database error:". mysqli_error($conn));
$totalRecords = mysqli_num_rows($queryTot);
$queryRecords = mysqli_query($conn, $sqlRec) or die("error to fetch rank holders");
//iterate on results row and create new index array of data
while( $row = mysqli_fetch_row($queryRecords) ) {
$data[] = $row;
$data[] = "<img src =images/".$data[2].">";
$json_data = array(
"draw" => intval( $params['draw'] ),
"recordsTotal" => intval( $totalRecords ),
"recordsFiltered" => intval($totalRecords),
"data" => $data // total data array
);
echo json_encode($json_data); // send data as json format
?>
Because you store the pic in the DB, you can send in ajax the base64 encoding of the pic you want to display.
Related
I have a problem getting the data in JSON format via the data.php file.
When I try see JSON I got this:
"{"draw":0,"recordsTotal":null,"recordsFiltered":120,"data":[]}"
but needs the php script to retrieve data from the table all entries for the column date, name, id like datatables AJAX instructions . When doing this using the local XAMPP server, the script retrieves the entries from the mysql table and the data is displayed as a table using datatables.
Here is my PHP code
$connect = new PDO("mysql:host=localhost;dbname=abc", "root", "PASSWORD");
$query = "SELECT * FROM abc_result ";
if(isset($_POST["search"]["value"]))
{
$query .= '
WHERE DATE LIKE "%'.$_POST["search"]["value"].'%"
OR NAME LIKE "%'.$_POST["search"]["value"].'%"
OR ID LIKE "%'.$_POST["search"]["value"].'%"
';
}
if(isset($_POST['DATE']))
{
$query .= 'ORDER BY '.$column[$_POST['DATE']['0']['column']].' '.$_POST['DATE']['0']['dir'].' ';
}
else
{
$query .= 'ORDER BY ID DESC ';
}
$query1 = '';
if($_POST['length'] != -1)
{
$query1 = 'LIMIT ' . $_POST['start'] . ', ' . $_POST['length'];
}
$statement = $connect->prepare($query);
$statement->execute();
$number_filter_row = $statement->rowCount();
$result = $connect->query($query . $query1);
$data = array();
foreach($result as $row)
{
$sub_array = array();
$sub_array[] = $row['DATE'];
$sub_array[] = $row['NAME'];
$sub_array[] = $row['ID'];
$data[] = $sub_array;
}
function count_all_data($connect)
{
$query = "SELECT COUNT(*) FROM abc_result";
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchColumn();
return $result;
}
$output = array(
"draw" => intval($_POST["draw"]),
"recordsTotal" => count_all_data($connect),
"recordsFiltered" => $number_filter_row,
"data" => $data
);
echo json_encode($output);
I'm trying to retrieve data from my mysql database and display it using datatables. locally I've been able to do it but I'd like to do it on a NAS (QNAP) so that when I go to a website the table would be visible by anyone who visits it. To do this, I installed MariaDB 5 and PHPmyAdmin. I was able to connect to the database but the php code does not display the data as I would like it to
I've got below snippet where $filter_xx values are extracted from a dropdown basis user choice.
I'm trying to query the mySQL database with what the user chose to query the database with via dropdown selection.
You will see that there are 4 $filter_xx variables and how many of them are set in a given instance is completely random.
The issue is when I use && in the query it checks if all four parameters are true and then throws and output. (Well I know && is suppose to work that way!). I tried replacing all && operators with || and had no luck.
How do I search the database with only options selected by the user?
if(isset($filter_brand) || isset($filter_year) || isset($filter_month) || isset($filter_status))
{
$query = "SELECT * FROM targets WHERE brand='$filter_brand' && startyear='$filter_year' && startmonth='$filter_month' && status='$filter_status' ORDER BY createdon DESC";
} else {
$query = "SELECT * FROM targets ORDER BY createdon DESC";
}
When you have several values that must work in a similar manner, use an array together with loop. I am supposing, you are using mysqli, change quoting for PDO if needed.
$mysqli = new mysqli("localhost", "user", "pass", "test");
//...
//SQL attr name => name of POST parameter
$filter = array('brand' => 'brand', 'startyear' => 'year',
'startmonth' => 'month', 'status' => 'status');
//here we'll store SQL conditions
$sql_filter = array();
foreach($filter as $key => $value)
{
if (isset($_POST[$value]))
{
//use your library function to quote the variable before using it in SQL
$sql_filter[] = $key . '="'. $mysqli->escape_string($_POST[$value]) . '"';
}
}
$query = "SELECT * FROM targets ";
if(isset($sql_filter[0]))
{
$query .= 'WHERE ' . implode(' AND ', $sql_filter) . ' ';
}
$query .= 'ORDER BY createdon DESC';
Try By This
$join = "";
//TAKE ONE BLANK VARIBLE THAT JOIN IF VALUE IS SET
if(isset($filter_brand)){
//IF VALUE ISSET THAN IT ADDED TO QUERY
$join .= " AND brand='$filter_brand'";
}
if(isset($filter_year){
$join .= " AND startyear='$filter_year'";
}
$query = "SELECT * FROM targets WHERE id != '' $join ORDER BY createdon DESC";
You can do something like this:
$query = 'SELECT * FROM targets';
$flag = 0;
if(isset($filter_brand) )
{
$query = "SELECT * FROM targets WHERE brand='$filter_brand'";
$flag = 1;
}
if(isset($filter_year)) {
if($flag==1)
$query .= " &&";
$query .= " startyear='$filter_year'";
$flag = 1;
}
if(isset($filter_month)) {
if($flag==1)
$query .= " &&";
$query = " startmonth='$filter_month'";
$flag = 1;
}
if(isset($filter_status)){
if($flag==1)
$query .= " &&";
$query = " status='$filter_status'";
$flag = 1;
}
if($flag == 1){
$query .= " ORDER BY createdon DESC";
} else {
$query = "SELECT * FROM targets ORDER BY createdon DESC";
}
Try this:
$query = "SELECT * FROM targets WHERE 1 ";
$query = isset($filter_brand) ? $query . " AND brand = '".$filter_brand."'" : $query;
$query = isset($filter_year) ? $query . " AND startyear = '".$filter_year."'" : $query;
$query = isset($filter_month) ? $query . " AND startmonth = '".$filter_month."'" : $query;
$query = isset($filter_status) ? $query . " AND status = '".$filter_status."'" : $query;
$query .= " ORDER BY createdon DESC";
I'm doing a table with sort, page and search function.First of all, the code runs well, but after I added where in my sql, the search function doesn't work anymore.
<?php
include_once("connection.php");
session_start();
$db = new dbObj();
$connString = $db->getConnstring();
$params = $_REQUEST;
$action = isset($params['action']) != '' ? $params['action'] : '';
$empCls = new cusinfo($connString);
switch($action)
{
default:
$empCls->getEmployees($params);
return;
}
class cusinfo
{
protected $conn;
protected $data = array();
function __construct($connString)
{
$this->conn = $connString;
}
public function getEmployees($params)
{
$this->data = $this->getRecords($params);
echo json_encode($this->data);
}
function getRecords($params) {
$rp = isset($params['rowCount']) ? $params['rowCount'] : 10;
if (isset($params['current'])) { $page = $params['current']; } else { $page=1; };
$start_from = ($page-1) * $rp;
$sql = $sqlRec = $sqlTot = $where = '';
if( !empty($params['searchPhrase']) )
{
$where .=" WHERE ";
$where .=" ( NO_ID LIKE '".$params['searchPhrase']."%' ";
$where .=" OR TICKET_ID LIKE '".$params['searchPhrase']."%' ";
$where .=" OR CAT_C_B LIKE '".$params['searchPhrase']."%' ";
$where .=" OR ORDER_TYPE LIKE '".$params['searchPhrase']."%' ";
$where .=" OR AGENT_STAFF_NAME LIKE '".$params['searchPhrase']."%' ";
$where .=" OR EFORM_ID LIKE '".$params['searchPhrase']."%' ";
$where .=" OR LATEST_ORDER_STATUS LIKE '".$params['searchPhrase']."%' )";
}
if( !empty($params['sort']) )
{
$where .=" ORDER By ".key($params['sort']) .' '.current($params['sort'])." ";
}
// getting total number records without any search
$role = $_SESSION['sess_userrole'];
$uid = $_SESSION['sess_user_id'];
$tid = $_SESSION['tmid'];
$mid = $_SESSION['mid'];
$sid = $_SESSION['sid'];
if($role=="admin")
{
$sql = "SELECT * FROM `cusinfo` where AGENT_CODE_STAFF_ID IN (SELECT id FROM `users` where tm_groupid = '$tid') ";
$sqlTot .= $sql;
$sqlRec .= $sql;
}
else
{
.
.
.
}
//concatenate search sql if value exist
if(isset($where) && $where != '')
{
$sqlTot .= $where;
$sqlRec .= $where;
}
if ($rp!=-1)
$sqlRec .= " LIMIT ". $start_from .",".$rp;
$qtot = mysqli_query($this->conn, $sqlTot) or die("error to fetch tot customer data");
$queryRecords = mysqli_query($this->conn, $sqlRec) or die("error to fetch customer data");
while( $row = mysqli_fetch_assoc($queryRecords) )
{
$data[] = $row;
}
$json_data = array(
"current" => $page,
"rowCount" => 10,
"total" => intval($qtot->num_rows),
"rows" => $data // total data array
);
return $json_data;
}
}
?>
Thankyou for all of the reply,this question have been solve by myself.It can be solve by just change the where to AND on the code bellow:
if( !empty($params['searchPhrase']) )
{
$where .=" WHERE";//change this line to $where .=" AND";
.
.
.
}
THIS IS MY PHP CODE how can i changed the font color of specific row based on the value
$sql = "SELECT * FROM employee "; $sqlTot .= $sql; $sqlRec .= $sql;
if(isset($where) && $where != '') {
$sqlTot .= $where;
$sqlRec .= $where;
}
if ($rp!=-1)
$sqlRec .= " LIMIT ". $start_from .",".$rp;
$qtot = mysqli_query($this->conn, $sqlTot) or die("error to fetch tot seaman's data");
$queryRecords = mysqli_query($this->conn, $sqlRec) or die("error to fetch seaman's data");
while( $row = mysqli_fetch_assoc($queryRecords) ) {
$data[] = $row;
}
$json_data = array(
"current" => intval($params['current']),
"rowCount" => 10,
"total" => intval($qtot->num_rows),
"rows" => $data // total data array
);
return $json_data;
}
Add more details about your client-side code. according to comments, you can change your code to this one:
...
while( $row = mysqli_fetch_assoc($queryRecords) ) {
if ($you_want)
$row['remarks'] = 'ACTIVE';
$data[] = $row;
}
...
I have made an search script to search inside various records, but when i add a WHERE session in the sql the script doesn't work anymore. can you please check the code and give me advice how i can change the script so i can get it work?
here are my scripts:
<?php
//include connection file
include_once("connection.php");
session_start();
if (!isset($_SESSION['GEBRUIKER_ID'])) {
header ("Location: ");
die;
}
// initilize all variable
$params = $columns = $totalRecords = $data = array();
$params = $_REQUEST;
//define index of column
$columns = array(
0 =>'id',
1 =>'user_id',
2 => 'klant_id',
3 => 'naam_klant',
4 => 'contactpersoon',
5 => 'adres'
);
$where = $sqlTot = $sqlRec = "";
// check search value exist
if( !empty($params['search']['value'])) {
$where .=" WHERE ";
$where .=" ( naam_klant LIKE '".$params['search']['value']."%' ";
$where .=" OR contactpersoon LIKE '".$params['search']['value']."%' ";
$where .=" OR adres LIKE '".$params['search']['value']."%')";
}
// getting total number records without any search
$sql = "SELECT id,naam_klant,contactpersoon,adres FROM klanten WHERE user_id='".$_SESSION['GEBRUIKER_ID']."' ";
$sqlTot .= $sql;
$sqlRec .= $sql;
//concatenate search sql if value exist
if(isset($where) && $where != '') {
$sqlTot .= $where;
$sqlRec .= $where;
}
$sqlRec .= " ORDER BY ". $columns[$params['order'][0]['column']]." ".$params['order'][0]['dir']." LIMIT ".$params['start']." ,".$params['length']." ";
$queryTot = mysqli_query($conn, $sqlTot) or die("database error:". mysqli_error($conn));
$totalRecords = mysqli_num_rows($queryTot);
$queryRecords = mysqli_query($conn, $sqlRec) or die("error to fetch employees data");
//iterate on results row and create new index array of data
while( $row = mysqli_fetch_row($queryRecords) ) {
$data[] = $row;
}
$json_data = array(
"draw" => intval( $params['draw'] ),
"recordsTotal" => intval( $totalRecords ),
"recordsFiltered" => intval($totalRecords),
"data" => $data // total data array
);
echo json_encode($json_data); // send data as json format
?>
<script type="text/javascript">
$( document ).ready(function() {
$('#employee_grid').DataTable({
"bProcessing": true,
"serverSide": true,
"ajax":{
url :"response.php", // json datasource
type: "post", // type of method ,GET/POST/DELETE
error: function(){
$("#employee_grid_processing").css("display","none");
}
}
});
});
</script>
<div class="container">
<div class="">
<h3>Klanten overzicht</h3>
<div class="">
<table id="employee_grid" class="display" width="100%" cellspacing="0">
<thead>
<tr>
<th>Klantnummer</th>
<th>Naam</th>
<th>Contactpersoon</th>
<th>Adres</th>
</tr>
</thead>
<tfoot>
<tr>
<th>Klantnummer</th>
<th>Naam</th>
<th>Contactpersoon</th>
<th>Adres</th>
</tr>
</tfoot>
</table>
</div>
</div>
</div>
When you're constructing your queries, you add a where user_id = ? clause for logged in users apparently. If the search value is not empty, you're adding a second where clause, making the query be essentially select .. from .. where user_id = ? where (naam_klant like ".." OR .. OR ..). You cannot have two wheres in one query, it has to be and, like this:
select .. from .. where user_id = ? AND (naam_klant like ".." OR .. OR ..)