I have that error
for this php code
$query = "insert into question values(" . $_SESSION['testqn'] . ",$newstd,'" . htmlspecialchars($_REQUEST['question'], ENT_QUOTES) . "','" . htmlspecialchars($_REQUEST['optiona'], ENT_QUOTES) . "','" . htmlspecialchars($_REQUEST['optionb'], ENT_QUOTES) . "','" . htmlspecialchars($_REQUEST['optionc'], ENT_QUOTES) . "','" . htmlspecialchars($_REQUEST['optiond'], ENT_QUOTES) . "','" . htmlspecialchars($_REQUEST['correctanswer'], ENT_QUOTES) . "'," . htmlspecialchars($_REQUEST['marks'], ENT_QUOTES) . ")";
"Column count doesn't match value count at row 1", this error would be shown if you have mismatch in the number of table columns and number of columns you are entering in the insert query.
Say, If you have 8 columns in table and if you are trying to insert with 7 or less columns you will get this error. I can see a mismatch in your table columns versus the insert query
Check the query and also the columns in the table, you will be able to fix this error.
Related
I have 2 tables (artist, cd) and I'm trying to use the result of the first query which returns an artID and make it equal to the artID in the 2nd table(cd) where artID is a foreign key but I'm not sure how to do it. Any help would be appreciated.
$strqueryID="SELECT artID FROM artist WHERE artName= '" . $_POST["category"] . "' ";
$resultsID=mysql_query ($strqueryID) or die(mysql_error());
$strqueryCD="INSERT INTO cd SET cdTitle='" . $_POST['title'] . "', artID='" . ??? . "' cdPrice='" . $_POST['price'] . "', cdGenre='" . $_POST['genre'] . "', cdNumTracks='" . $_POST['tracks'] . "'";
$resultsCD=mysql_query ($strqueryCD) or die(mysql_error());
You can use one single query, like this:
$strqueryCD="
INSERT INTO cd (cdTitle, artID, cdPrice, cdGenre, cdNumTracks)
VALUES(
'" . $_POST['title'] . "',
(SELECT artID FROM artist WHERE artName= '" . $_POST["category"] . "'),
'" . $_POST['price'] . "',
'" . $_POST['genre'] . "',
'" . $_POST['tracks'] . "')
";
also, google 'sqlinjection' before you continue
So, first thing's first - you shouldn't be using mysql_* functions now in 2017. I mean, really - they're actually even removed in later versions of PHP (7.0+). Refer to this StackOverflow post for more information.
Now, for your question at hand. Given the fact that you've searched for (and found) a given artID, you'll first have to get the actual "rows" from the $resultsID variable. In this example, we'll do it in a typical while loop:
while ($row = mysql_fetch_assoc($resultsID)) {
$strqueryCD="INSERT INTO cd SET cdTitle='" . $_POST['title'] . "', artID='" . $row['artID'] . "' cdPrice='" . $_POST['price'] . "', cdGenre='" . $_POST['genre'] . "', cdNumTracks='" . $_POST['tracks'] . "'";
$resultsCD=mysql_query ($strqueryCD) or die(mysql_error());
}
That should now loop over the artIDs that you've found in your first query and use them in the subsequent insert(s).
--
Disclaimer: I've disregarded the fact that user input is being passed straight into the query itself, as it's just too much "out of scope" for this post.
I am looking to update one of the table. After I update, all the duplicate data is getting inserted again. Especially, the cloneSQL part of the code. I tried using DISTINCT, NOT EXISTS but no luck.
if(DB_num_rows($checkResult) > 0){
$cloneSQL = "UPDATE DISTINCT pricematrixdiscount SET
discount='" . $vals[3] . "'
WHERE debtorno='" . $_POST['cloneTo'] . "',
product_line='" . $vals[1] . "',
salestype='" . $vals[2] . "' ";
}
else {
$cloneSQL = "INSERT into pricematrixdiscount
(debtorno,
product_line,
salestype,
discount) VALUES
('" . $_POST['cloneTo'] . "',
'" . $vals[1] . "',
'" . $vals[2] . "',
'" . $vals[3] . "')";
How can I insert only distinct values on the pricematricdiscount table without the duplicates being inserted?
I already saw other post related to this question, but they did not solve my problem. I want to automatically go to next rows and want to insert that row in the table. I am transfering sample of data from another database. I want to insert large set of rows... Right now I am getting first row repeatedly in all rows. I need to go to to next rows automoatically
Below is my sample code...
while ($row = mysql_fetch_array($query)) {
$sql = "INSERT INTO table_name (info1, info2, info3,...) "
."VALUES (" . $row['info1'] . "," . $row['info2'] . "," . $row['info3'] . "),
(" . $row['info1'] . "," . $row['info2'] . "," . $row['info3'] . "),
(" . $row['info1'] . "," . $row['info2'] . "," . $row['info3'] . "),
(" . $row['info1'] . "," . $row['info2'] . "," . $row['info3'] . ")";
}
This sql Query could help you. You can insert the select datas in one Query. See MySQL documentation: http://dev.mysql.com/doc/refman/5.7/en/insert-select.html
INSERT INTO table_name
(info1, info2, info3)
SELECT
source_table.info1,
source_table.info2,
source_table.info3,
FROM
source_table
WHERE
(WHERE CLAUSE)
do a separate insert for each selected rows:
while ($row = mysql_fetch_array($query)) {
$sql = "INSERT INTO table_name (incremented_field, info1, info2, info3) "
."VALUES (NULL, " . $row['info1'] . "," . $row['info2'] . "," . $row['info3'] . ")";
mysql_query($sql);
}
I have the following query:
REPLACE INTO `oxarticles`
SET
OXID = '10-1010',
oxartnum = '10-1010',
oxtitle = 'Dummy',
oxprice = '10.000000',
oxstock = '100',
importstatus = 1"
This works so far as expected, but the fields I do not specifiy, are just overwritten with ' ' / empty string. From what I read, should this syntax work identically like the UPDATE-command.
Am I missing something? How can I prevent that fields are replaced with '' ?
Edit 1
Just to clarify, I can't just use UPDATE. I am setting a flag (importstatus) to 0 before every run and during the import to 1. After the import finishes, I delete all articles, which are still on status 0.
// Just for the compeletion, here is the PHP-snippet:
while (!feof($this->handle))
{
$row = fgetcsv($this->handle, 0, ";");
$sSql = "REPLACE INTO oxarticles SET "
. " OXID = '" . $row[0] . "', "
. " oxartnum = '" . $row[0] . "', "
. " oxtitle = '" . $row[1] . "', "
. " oxprice = '" . str_replace(",", ".", $row[4]) . "', "
. " oxstock = '" . str_replace(",", ".", $row[5]) . "', "
. " importstatus = 1";
// $sSql = "UPDATE oxarticles SET oxtitle ='" . $row[1] . "', oxprice='" . $row[4] . "', oxstock='" . $row[5] . "' WHERE oxartnum ='".$row[0]."'";
$this->db->execute($sSql);
}
From the mysql documentation:
REPLACE works exactly like INSERT, except that if an old row in the
table has the same value as a new row for a PRIMARY KEY or a UNIQUE
index, the old row is deleted before the new row is inserted. See
Section 13.2.5, “INSERT Syntax”.
In other words, the row is being deleted and then inserted, hence your old values aren't staying intact. Perhaps you could select the original row first, and feed those values back in where appropriate.
You query will replace old data into new data if you do not provide data for a field it will set to null . If you do not want to loose your data just want to update field use on duplicate key update.
If did't found any match it will insert new row
If found it will replace data if provide
INSERT INTO table (id,a,b,c,d,e,f,g) VALUES (1,2,3,4,5,6,7,8) ON
DUPLICATE KEY
UPDATE a=a, b=b, c=c, d=d, e=e, f=f, g=g;
I don't really know what wrong a while ago; it's still working, but then it's just causing an error:
$query = "insert into subject values($newstd,'" . htmlspecialchars($_REQUEST['subname'], ENT_QUOTES) . "','" . htmlspecialchars($_REQUEST['subdesc'], ENT_QUOTES) . "','" . htmlspecialchars($_REQUEST['recommendation1'], ENT_QUOTES) . "','" . htmlspecialchars($_REQUEST['recommendation2'], ENT_QUOTES) . "',NULL)";
The structure of my Database is
subid
subname
sudesc
recommendation1
recommendation2
When I run the Query I always got that kind of error.
you are having 5 columns in table, and inserting six columns value. Why inserting 'Null' value at last.. there is no column for it