I want to delete row in database without reloading the page. I have written following codes. It does delete row in page but not in database. which means connection not going to ajax. pls help.
<?php
$advances_result= mysqli_query($conn, "SELECT * FROM advances") or die("error");
?>
<table border>
<caption>ADVANCES</caption>
<tr>
<th>Date</th>
<th>EmpName</th>
<th>EmpCode</th>
<th>Amount</th>
<th>Comment</th>
<th>Action</th>
</tr>
<?php
while($row = mysqli_fetch_array($advances_result)){
?>
<tr>
<td><?php echo $row['date'];?></td>
<td><?php echo $row['empname'];?></td>
<td><?php echo $row['empcode'];?></td>
<td style='text-align:right'><?php echo $row['amount'];?></td>
<td><?php echo $row['comment'];?></td>
<td><button class="delete" id="<?php echo $row['id']; ?>" > Delete</button></td>
</tr>
<?php
}
?>
</table>
'jquery part'
<script>
$(document).ready(function(){
$(".delete").click(function() {
if (confirm("Do you want to delete this row?"))
{
var row = $(this).parents('tr');
var id = row.attr("id");
var data = 'id=' + id ;
$.post({
type: "post",
url: "deleteadvances.php",
data: data,
cache: false,
success: function(){
row.slideUp('slow', function() {$(row).remove();});
}
});
}
return false;
});
});
</script>
'deleteadvances.php' page:
<?php
include("connection.php");
$id = $_POST['id'];
mysqli_query($conn,"INSERT INTO advancehistory SELECT * FROM advances WHERE ID='".$id."'");
mysqli_query($conn,"DELETE FROM advances WHERE ID='".$id."'");
?>
You need to test the output of mysqli_query in deleteadvances.php, if all good, it shows JSON Ok message that is easy parsable with $.post on the jQuery side.
e.g: {"deleted":"id"} on success or {"error":404} on error not found.
I think the id that you're passing from javascript to ajax is incorrect.
var data = 'id=' + id;
is appending the id with string 'id=' and now it finally becomes a string. When it is being passed to ajax, there is just a value and not a [key, value] pair. So, when you are accessing it in php you will get wrong id or Null value.
Try:
$.post({
type: "post",
url: "deleteadvances.php",
datatype : 'json',
data: {
id : id
},
cache: false,
contentType : 'application/x-www-form-urlencoded; charset=utf-8'
});
Change 'deleteadvances.php' page:
<?php
include ('connection.php');
$id=$_POST['id'];
$delete = "DELETE FROM table_name WHERE id=$id";
$result = mysqli_query($db,$delete) or die("Bad SQL: $delete");
?>
Related
I'm trying fill the table with fetched data from database by the id of selected option. Table content must change when user selects other option. Chosen plugin is working fine and select options is filled with correct values, how to give var selektas from test.php to loader.php in query where kliento_id = $idofclient?
Somehow make selektas == $idofclient so that i could use this variable in query in loader.php
My test.php:
<script type="text/javascript">
$(document).ready(function () {
$('.chosen-select').chosen();
});
</script>
<script type="text/javascript">
$(document).ready(function(){
$("#.pavadinimai").on("change",function(){
var selektas = $(this).val().split('|');
$.ajax({
type: "POST",
url: "loader.php",
data: {selektas[o]},
success: function(result){
$("#show").html(result);
$('#show').dataTable().fnDestroy();
$('#show').dataTable();
}
});
});
});
</script>
<select class="chosen-select" name="pavname" id="pavadinimai">
<option selected="selected" value = "">---Pasirinkti---</option>
<?php
echo "Pasirinkite klienta";
$sql = "SELECT id, kliento_pav FROM klientai";
$stmt = mysqli_query($link, $sql);
while ($row = mysqli_fetch_assoc($stmt)) {
echo "<option value='" . $row['id'] .'|'. $row['kliento_pav'] . "'>" . $row['kliento_pav'] . "</option>";
}
list($idofclient,$pavofclient) = explode ('|',$_POST['pavname']);
?>
</select>
<div id="show">
</div>
And this is my code in loader.php
<?php
require_once "config.php";
if(isset($_POST["pavadinimas"])){
$sql_query="SELECT uzsakymai.id, kliento_id, uzsakymai.kiekis,prekes.pavadinimas,uzsakymai.aprasymas FROM uzsakymai INNER JOIN prekes ON uzsakymai.prekes_id = prekes.id INNER JOIN klientai on uzsakymai.kliento_id = klientai.id WHERE kliento_id = $idofclient"
$resultset = mysqli_query($link, $sql_query) or die("database error:". mysqli_error($link));
while( $result = mysqli_fetch_assoc($resultset) ) {
?>
<br>
<table id="data_table" class="table table-striped">
<thead>
<tr>
<th>Prekės pavadinimas</th>
<th>Kiekis</th>
<th>Aprašymas</th>
</tr>
</thead>
<tbody>
<tr id="<?php echo $result ['id']; ?>">
<td><?php echo $result ['pavadinimas']; ?></td>
<td><?php echo $result ['kiekis']; ?></td>
<td><?php echo $result ['aprasymas']; ?></td>
</tr>
</tbody>
</table>
<?php } ?>
<?php
echo $result
}
?>
I'm using ...jquery/3.1.1/jquery.min.js
Try this
Initially you initialized the table so first clear that table
$('#myTable').dataTable().fnDestroy();
Then initialize again after ajax success
$('#myTable').dataTable();
Like this.....
$(document).ready(function(){
$("#.pavadinimai").on("change",function(){
$.ajax({
type: "POST",
url: "loader.php",
data: {$idofclient},
success: function(result){
$("#show").html(result);
$('#show').dataTable().fnDestroy();
$('#show').dataTable();
}
});
});
});
$(document).ready(function() {
$("#pavadinimai").on("change", function() {
var pavadinimai = $("#pavadinimai").val();
$.ajax({
type: "POST",
url: "loader.php",
data: {
pavadinimai: pavadinimai
},
success: function(result) {
$("#show").html(result);
$('#show').dataTable().fnDestroy();
$('#show').dataTable();
}
});
});
});
I want to add a delete button to this table, to delete the query from Database. I have the Ajax and PHP codes here :
<?php
require_once 'dbconfig.php';
$stmt = $pdo->prepare("SELECT * FROM test");
$stmt->execute();
while($row=$stmt->fetch(PDO::FETCH_ASSOC))
{
?>
<tr>
<td><?php echo $row['id']; ?></td>
<td><?php echo $row['server']; ?></td>
<td><?php echo $row['reference']; ?></td>
<td align="center"><a id="<?php echo $row['id']; ?>" class="delete-link" href="#" title="Delete">
<img src="images/delete.png" width="20px" />
</a></td>
</tr>
<?php
}
?>
the ajax :
$(document).ready(function(){
/* Data Delete Starts Here */
$(".delete-link").click(function()
{
var id = $(this).attr("id");
var del_id = id;
var parent = $(this).parent("td").parent("tr");
if(confirm('Sure to Delete ID no = ' +del_id))
{
$.post('delete.php', {'del_id':del_id}, function(data)
{
parent.fadeOut('slow');
});
}
return false;
});
/* Data Delete Ends Here */
});
delete.php :
<?php
include_once 'dbconfig.php';
if($_POST['del_id'])
{
$id = $_POST['del_id'];
$stmt=$db_con->prepare("DELETE FROM test WHERE id=:id");
$stmt->bindParam(':id', $id);
$stmt->execute();
}
?>
The row selected doesn't seem to get DELETED in the DB ... i have no error too.
You had pass data incorrectly . Please try this
$(document).ready(function()
{
$('table#delTable td a.delete').click(function()
{
if (confirm("Are you sure you want to delete this row?"))
{
var id = $(this).parent().parent().attr('id');
var data = 'id=' + id ;
var parent = $(this).parent().parent();
$.ajax(
{
type: "POST",
url: "view.php",
data: {id:id},
cache: false,
success: function()
{
parent.fadeOut('slow', function() {$(this).remove();});
}
});
}
});
});
I am have a page where i have the table row id defined by 'lesson_id' and i have a delete function for jquery that deletes that row without having to change page.
It is almost all working but when it posts the information to delete_row.php it is not deleting the record.
but delete_row.php is working because i've manually done delete_row.php?id=4 and it deleted that record succesfully.
Any pointers and explanations would be great as i'm still learning.
lessons.php
<table id="lessons" class="table-hover">
<thead>
<tr>
<th>Lesson ID</th>
<th>Lesson Name</th>
<th></th>
</tr>
</thead>
<tbody>
<?php
while($row=mysqli_fetch_array($result)){
echo '<tr id="'. $row['lesson_id'].'">';
echo '<td>'. $row['lesson_id'] .'</td>';
echo '<td>'. $row['name'] .'</td>';
echo '<td><a class="delete">Delete</a></td>';
echo '</tr>';
}
?>
</tbody>
<div id="error"></div>
<script>
$(document).ready(function()
{
$('table#lessons td a.delete').click(function()
{
if (confirm("Are you sure you want to delete this row?"))
{
var id = $(this).parent().parent().attr('id');
var data = 'id=' + id ;
var parent = $(this).parent().parent();
//$('#error').html(data);
$.ajax(
{
type: "POST",
url: "delete_row.php",
data: data,
cache: false,
success: function()
{
parent.fadeOut('slow', function() {$(this).remove();});
}
});
}
});
});
</script>
delete_row.php
<?php
include ('../../../config.php');
$con = mysqli_connect ($dbhost,$dbuser,$dbpass,$dbname);
if (!$con){
die('could not connect: '. mysqli_error($con));
}
$error = "";
$success = "";
if($_GET['id'])
{
$id = $_GET['id'];
mysqli_query($con,"DELETE FROM module_lessons WHERE lesson_id='$id'");
}
?>
as its obvious ... this has no sql injection protection on it.
Change $_GET['id']; to $_POST['id'];
Here, you're doing a POST request:
type: "POST",
url: "delete_row.php",
... but in your PHP script you're checking for GET.
Also, as marc b noted, you're currently vulnerable to SQL injection. Look into using mysqli_real_escape_string, or bind_param.
There is a div element :
...
<div id="liste_secteurs"></div>
...
<script type="text/javascript">
$(document).ready(function() {
rechercheSecteursEtProduits(0); // setting the div's content
$('#btnSupprimer').click(function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
});
});
function rechercheSecteursEtProduits(pn){
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_user="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html); // this is the div element
}
</script>
Code of ListerProduitsUserParSecteursAjax.php :
<?php
... // getting database data
?>
<p>Total : <?php echo $nr; ?></p>
<div><img src="<?php echo HTTP_ICON.'plus.png'; ?>" /></div>
<?php echo $paginationDisplay; ?>
<table id="table" class="data display " >
<thead style="background-color:#CCC">
<tr>
<th><?php echo _getText("service.produit.form.secteur_activite");?></th>
<th><?php echo _getText("service.produit.form.titre");?></th>
<th></th>
<th><?php if($data["secteur"]["cnt"] > 0){ ?><input type="checkbox" id="check_all"><?php }?></th>
</tr>
</thead>
<tbody style="background-color:#FFF">
<?php
if($data["secteur"]["cnt"] > 0){
for($i=0;$i<$data["secteur"]["cnt"];$i++){?>
<tr class="odd gradeX">
<td><?php echo $data["secteur"][$i]["secta_lib_fr"] ?></td>
<td><?php echo $data["secteur"][$i]["produit_lib"] ?></td>
<td align="center" style="vertical-align:middle"><img src="<?php echo HTTP_ICON.'edit.png'; ?>" alt="<?php echo _getText('main.btn.modifier'); ?>" style="height:10px;width:10px;" /></td>
<td align="center" style="vertical-align:middle"><input type="checkbox" id="prod_<?php echo $i; ?>" value="<?php echo $data['secteur'][$i]['id_user_produit']; ?>"><input type="hidden" id="secteur_<?php echo $i; ?>" value="<?php echo $data['secteur'][$i]['id_user_secteur']; ?>"></td>
</tr>
<?php } ?>
<?php
}
else{
?>
<tr class="odd gradeX">
<td colspan="4" align="center"><b><?php echo _getText('main.liste.no_data'); ?></b></td>
</tr>
<?php }?>
</tbody>
</table>
<?php if($data["secteur"]["cnt"] > 0){ ?>
<div align="right"><input name="btnSupprimer" id="btnSupprimer" type="button" value="<?php echo _getText("main.btn.delete"); ?>" class="btn btn-blue"/></div>
<?php } ?>
<?php echo $paginationDisplay; ?>
When the page loads for the first time then the delete button works fine : the selected rows are deleted , and the list reappears accordingly to new database data. But later when I want to delete other rows then the alert does not show when I check some checkboxes and clicking the delete button !
So what is wrong in my approach ?
From what I am reading you are having problems with the row that are added from the database.
What could be the problem is when you execute this peace of code:
$('#btnSupprimer').click(function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
When you call the $.click() function you add a event to all the existing DOM object that have a id of 'btnSupprimer', however this doesn't update if you add a new DOM object. So what you should do is call this function every time you add a new row. you would get something like this:
function rechercheSecteursEtProduits(pn){
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_user="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html);
$('#btnSupprimer').click(addClickHandler()); // this is the div element
}
function addClickHandler(){
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
}
I hope it helps
Try using on instead of click as below
$('#btnSupprimer').on("click","#liste_secteurs",function() { // btnSupprimer = button generated from an ajax called inside previous function "rechercheSecteursEtProduits"
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
var msg = "Do you want to remove these records ?";
if (confirm(msg)) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0); // this causes the bug : the "delete" button does not work anymore after this code is called !
}
}
});
Use the dynamic jquery selector instead of the regular 'click' event
$('#liste_secteurs').on('click', '#btnSupprimer', function() {});
// $("container").on("event", "button", function() {});
As from Caveman's answer I made some updates :
function rechercheSecteursEtProduits(pn) {
var user = "<?php echo $_SESSION[CODE_USER]; ?>";
var html = $.ajax({
data: "id_usermer="+user,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/ListerProduitsUserParSecteursAjax.php?pn=" + pn,
async: false
}).responseText;
$('#liste_secteurs').html(html);
$('#btnSupprimer').on('click',function(){
if ($(':checkbox[id^="prod_"]:checked').length > 0) {
if (confirm("Do you want to remove these records ?")) {
$(':checkbox[id^="prod_"]:checked').each(function(){
var type = "",id="";
if($(this).val() == "") { // delete secteur
type = "secteur";
var tabIdx = $(this).attr("id").substr(5);
id = $("#secteur_"+tabIdx).val();
} else { // delete produit
type = "produit";
id = $(this).val();
}
$.ajax({
data: "type="+type+"&id="+id,
type: "POST",
url: "<?php echo HTTP_AJAX ?>service/SupprimerSecteursProduitsUserAjax.php", // deleting database row
async: false
});
});
rechercheSecteursEtProduits(0);
}
}
});
}
And it works !
I have an HTML table generated by PHP querying from MySQL table.
<table>
<tr>
<th>Sl</th>
<th>ID</th>
<th>Article Name</th>
<th>Publish Status</th>
</tr>
<?php
$i = 1;
foreach ($obj->showAllFromTable('pattern') as $pattern) {
extract($pattern);
?>
<tr>
<td><?php echo $i++; ?></td>
<td><?php echo $id; ?></td>
<td><?php echo $pattern_name; ?></td>
<td id="publish_<?php echo $id; ?>" class="status_pattern">
<?php echo $publish; ?>
</td>
</tr>
<?php
}
?>
</table>
I want to change the status of any article by clicking on the 'publish' cell of the corresponding article row. I am trying to use ajax method of jquery for this purpose as shown in the following:
<script type="text/javascript">
$(document).ready(function(){
$('.status_pattern').click(function(){
var thisid = $(this).attr('id');
$.ajax({
url: "status_change_pattern.php",
data: {
id: thisid
},
success: function (response) {
alert(response);
}
});
});
});
</script>
In the "success" block, instead of "alert", I want to create a functionality to change the text of the specific cell which I clicked. The "status_change_pattern.php" has just a text "Hey Hey".
Can anyone help? Please.
Thanks.
You have to use closure to preserve the id.
<script type="text/javascript">
$(document).ready(function(){
$('.status_pattern').click(function(){
var thisid = $(this).attr('id');
$.ajax({
url: "status_change_pattern.php",
data: {
id: thisid
},
success: function (id) {
return function (response) {
$("#" + id).html(response);
}
}(thisid)
});
});
});
</script>
You need to write,
success: function (response) {
$(thisid).html(response);
}
Here in response, you need to get new status.
The solution provided by SajithNair works. Thanks to SajithNair. But it can also be done without using closure. As shown below:
$('.status_pattern').click(function() {
var thisid = $(this).attr('id');
$.ajax({
url : "status_change_pattern.php",
data : {
id : thisid
},
success : function(response) {
$('#' + thisid).html(response);
}
});
});
Thanks