Selecting only even numbers in php output [duplicate] - php

Question

This question already has answers here:
How to filter an array by a condition
(9 answers)
Closed 6 years ago.
I am trying to select and display only the even number in a separate output from this below
function toms($c,$first = 0,$second = 1)
{
$toms = [$first,$second];
for($i=1;$i<$c;$i++)
{
$toms[] = $toms[$i]+$toms[$i-1];
}
return $toms;
}
echo "<pre>";
print_r(toms(33));
?>
currently this outputs
array
(
[0] => 0
[1] => 1
[2] => 1
[3] => 2
[4] => 3
[5] => 5
[6] => 8
[7] => 13
[8] => 21
[9] => 34
[10] => 55
[11] => 89
[12] => 144
[13] => 233
[14] => 377
[15] => 610
[16] => 987
[17] => 1597
[18] => 2584
[19] => 4181
[20] => 6765
[21] => 10946
[22] => 17711
[23] => 28657
[24] => 46368
[25] => 75025
[26] => 121393
[27] => 196418
[28] => 317811
[29] => 514229
[30] => 832040
[31] => 1346269
[32] => 2178309
[33] => 3524578
)
Anyone know how I can display only the even numbers returned, so I would want to have 2, 8, 34 and so on
thank you

Answer 1

You can use array_filter
print_r(array_filter(toms(33), function($number){
return $number % 2 == 0;
}));
Or if you want to filter out 0:
print_r(array_filter(toms(33), function($number){
return $number != 0 && $number % 2 == 0;
}));
A bit more readable:
$isEvenNumber = function($number) {
return $number % 2 == 0;
}
$numbers = toms(33);
$filtered_numbers = array_filter($numbers, $isEvenNumber);
var_dump($filtered_numbers);