I want to get multiple return value for checkbox. But problem is with following code check box only can echo a single value. Even I select multiple checkbox I am getting only single value form it. How to solve it
$q2 = mysqli_query($conn,"SELECT product_img_url FROM temp_img");
while ($row = mysqli_fetch_array($q2)) {
$product_img_url = $row['product_img_url'];
$target_dir = "../assets/img/temp_img/";
$img_link = $target_dir.$product_img_url;
echo '<br>Add it<br><input type="checkbox" name="pic_tobe_add" value="'.$img_link.'"><br><img src="'.$img_link.'" class="img-rounded" alt="Uploaded image" width="152" height="118"><br><br>';
}
if(isset($_POST['submit_p'])) {
if (empty($_POST['pic_tobe_add'])) {
echo "Error: select a pic";
}else{echo $pic_tobe_add = $_POST['pic_tobe_add'];}
}
echo '<br><input type="submit" name="submit_p" value="Add this product"><form>';
Actually name of each check-box is same that's why you get only single value which is last-one.
change name="pic_tobe_add" to name="pic_tobe_add[]" (Make it array type so that you will get all the value)
On the next page confirm it by printing out POST value using echo "<pre/>";print_r($_POST);
use <input type="checkbox" name="pic_tobe_add[]" value="'.$img_link.'">
$q2 = mysqli_query($conn,"SELECT product_img_url FROM temp_img");
while ($row = mysqli_fetch_array($q2)) {
$product_img_url = $row['product_img_url'];
$target_dir = "../assets/img/temp_img/";
$img_link = $target_dir.$product_img_url;
echo '<br>Add it<br><input type="checkbox" name="pic_tobe_add[]" value="'.$img_link.'"><br><img src="'.$img_link.'" class="img-rounded" alt="Uploaded image" width="152" height="118"><br><br>';
}
//
if(isset($_POST['submit_p'])) {
if (empty($_POST['pic_tobe_add'])) {
echo "Error: select a pic";
}else{echo $pic_tobe_add = $_POST['pic_tobe_add'];}
}
echo '<br><input type="submit" name="submit_p" value="Add this product"><form>';
Related
i want to echo selected parent value. but i am getting error- Notice: Undefined index:
How can i echo selected parent value then? Whats wrong i am doing?
$q = mysql_query("SELECT * FROM menu");
echo '<form action="" method="post">
Menu name:<input type="text" name="mname"><br>
<select>';
while ($row = mysql_fetch_array($q)) {
$menu_name = $row['menu_name'];
echo '<option value="'.$menu_name.'">'.$menu_name.'</option>';
}
echo '</select><br>
<input type="submit" name="submit" value="Add Menu">
</form>';
if (isset($_POST['submit'])) {
echo $mname = $_POST['mname'];
echo $parent = $_POST[$menu_name];
}
add name to the select box and get the value of select box by name.
Updated code:-
$q = mysql_query("SELECT * FROM menu");
echo '<form action="" method="post">
Menu name:<input type="text" name="mname"><br>
<select name="menu_name">';
while ($row = mysql_fetch_array($q)) {
$menu_name = $row['menu_name'];
echo '<option value="'.$menu_name.'">'.$menu_name.'</option>';
}
echo '</select><br>
<input type="submit" name="submit" value="Add Menu">
</form>';
if (isset($_POST['submit'])) {
echo $mname = $_POST['mname'];
echo $parent = $_POST['menu_name'];
}
$_POST[$menu_name] probably doesn't exist, because only two elements in your form have name attributes. The text input and the submit input.
option elements aren't posted as part of the form, but rather the selected option's value for the select element. But your select element has no name, therefore no key to use in the key/value pair, so it isn't posted.
Give the element a name:
<select name="someName">
Then in the POST, you would be able to fetch the selected value just as you do for any other form element:
$_POST['someName']
You need to add name attribute to select tag.
echo '<form action="" method="post">
Menu name:<input type="text" name="mname"><br>
<select name="any_name">';
$q = mysql_query("SELECT * FROM menu");
while ($row = mysql_fetch_array($q)) {
$menu_name = $row['menu_name'];
echo '<option value="'.$menu_name.'">'.$menu_name.'</option>';
}
echo '</select><br>
<input type="submit" name="submit" value="Add Menu">
</form>';
if (isset($_POST['submit'])) {
echo $mname = $_POST['mname'];
echo $select_option_name = $_POST['any_name'];
}
Note: mysql_* functions are depricated, use mysqli_* functions
I have written code to retrieve all the images from database for a specific city, and I want to be able to delete a specific image or to change the caption.
The problem is:
the code always work on the last image only!
I hope you guys will be able to help me with this problem.
Retrieve code:
<?php
$City_name=$_REQUEST['id'];
$Image_query = "SELECT * FROM image where City_name ='".$City_name."' ";
$Image_result = mysqli_query($dbcon,$Image_query);
echo "<table>";
while ($row = mysqli_fetch_array($Image_result))
{
$image_id = $row['Image_id'];
$image = $row['Image_url'];
$Caption = $row['Caption'];
echo "<tr style='float:right;'>";
echo "<td>"; ?> <img src="<?php echo $image ; ?>"/> <br>
<input type="text" name="caption" value="<?php echo $Caption ;?>" />
<br> <input name="delete" type="submit" value="Delete picture" />
<br> <input name="Update_caption" type="submit" value="change caption" />
<?php echo "</td>";
echo "<td>"; ?> <input class="input-image" type="hidden" name="id" value="<?php echo $image_id ;?>" />
<?php echo "</td>";
} /* End of while loop */
echo "</tr>";
echo"</table>";
?>
Update code :
if (isset($_POST['Update_caption'])) {
$ImageID = $_POST['id'];
$ImageCaption = $_POST['caption'];
$sql = mysqli_query ($dbcon,"UPDATE `image` SET `Caption`='".$ImageCaption."' WHERE `Image_id`='".$ImageID."' ");
if ($sql) {
echo "done";
} else { echo "error"; }
}
Delete code :
if (isset($_POST['delete'])) {
$ImageID = $_POST['id'];
$sql = mysqli_query ($dbcon,"DELETE FROM `image` where `Image_id` = '".$ImageID."' ");
if ($sql) {
echo "done";
} else { echo "error"; }
}
$_POST['id'] (sql injection alert!) contains the contents of the input element that has a name attribute id.
You are echoing out your input elements in a loop, all with the same name so the last one will overwrite all the previous ones.
You should use an array like for example:
<input class="input-image" type="hidden" name="id[<?php echo $image_id ;?>]" value="<?php echo $image_id ;?>" />
So that your $_POST['id'] is an array containing all elements.
The same applies to other input elements like the caption.
An alternative, especially for your delete option, would be to wrap every image in its own form. But keep in mind that you will need valid html for that to work, you can't have a form that opens in a row element and spans different columns.
And note that you should really use a prepared statement to close the sql injection hole you have now.
I am a little stuck with this. I am trying to insert groups of items only if that groups checkbox is clicked. I have tested the SQL insert without the checkboxes, and the SQL works perfectly and inserts the data. But when I added the checkboxes and if/else statement, it started to give me troubles.
For example:
-If I select group 1 and not group 2 - the SQL works correctly only inserting group 1 data
-If I select group 2 and not group 1 - The insert still inserts group 1 data
-If I select group 1 and group 2 - The SQL inserts two rows of group 1 data
-If I do not select any groups, then I get "Warning: Invalid argument supplied for foreach() in /home..." - which I will sort out later.
I have marked "Group 1" and "Group 2". I need the code to insert only the groups if checkbox is clicked, and ignore the non clicked checkbox groups. Any help would be great. Thanks.
I have been testing with the following code:
Form:
<form id="Form" method="post" action="/random.php" name="Form">
<input id="itemCurrency" type="hidden" value="2" name="itemCurrency"></input>
<div class="row">
<div class="col-lg-4">
<div class="itemHolder">
<img class="itemImg thumbnail" src="http://images.com/i/images.jpg"></img>
<div class="itemName">swim Shorts Wi...</div><
<div class="itemPrice">$33.33</div>
<div class="itemHref"><a target="_blank" href="http://random.com/product.aspx?id=40"> Visit Item Page </a></div>
</div>
</div>
//GROUP 1
<input id="itemCheckBox[]" type="checkbox" value="checked" name="itemCheckBox[]"></input>
<input id="itemName[]" type="hidden" value="some random text" name="itemName[]"></input>
<input id="itemHref[]" type="hidden" value="http://random.com/product.aspx?id=2140" name="itemHref[]"></input>
<input id="itemImg[]" type="hidden" value="http://images.com/i/image1s.jpg" name="itemImg[]"></input>
<input id="itemPrice[]" type="hidden" value="$37.33" name="itemPrice[]"></input>
//END GROUP 1
<div class="col-lg-4">
<div class="itemHolder">
<img class="itemImg thumbnail" src="http://images.com/i/image_xl.jpg"></img>
<div class="itemName">Bomber Jacket With Fur</div>
<div class="itemPrice"> $88.88</div>
<div class="itemHref"><a target="_blank" href="http://random.com/Bomber-Jacket-With-fur/..">Visit Item Page</a></div>
</div>
</div>
//GROUP 2
<input id="itemCheckBox[]" type="checkbox" value="checked" name="itemCheckBox[]"></input>
<input id="itemName[]" type="hidden" value="Bomber Jacket With Fur" name="itemName[]"></input>
<input id="itemHref[]" type="hidden" value="http://random.com/Bomber-Jacket-With-fur/.." name="itemHref[]"></input>
<input id="itemImg[]" type="hidden" value="http://images.com/i/image_xl.jpg" name="itemImg[]"></input>
<input id="itemPrice[]" type="hidden" value="$88.88" name="itemPrice[]"></input>
//END GROUP 2
<input id="site" type="hidden" value="1" name="site"></input>
<input id="submit_form" type="submit" value="yes" name="submit_form"></input>
</form>
PHP
if($submitForm == "yes" && $site == "1") {
foreach($_POST['itemCheckBox'] as $key => $val)
{
$fields[] = array(
'itemCheckBox'=>$_POST['itemCheckBox'] [$key],
'itemName' =>$_POST['itemName'] [$key],
'itemHref' =>$_POST['itemHref'] [$key],
'itemImg' =>$_POST['itemImg'] [$key],
'itemPrice' =>$_POST['itemPrice'][$key] );
//Remove non numaric characters from price(leave commas).
$itemPrice = preg_replace('/[^0-9,.]/s', '', $itemPrice);
//Data fields not in form
$userId = "username";
$userIp = $_SERVER['REMOTE_ADDR'];
$itemType = "ADD LATER";
$itemOutFit = "ADD LATER";
$site = "1";
$itemSale = "1";
//Only insert if checkbox is clicked --NOT WORKING, ????
if (isset($_POST['itemCheckBox'])){
echo "CHECKED";
echo "<br>";
/*** INSERT data ***/
$sql = "INSERT INTO items (userId,itemHref,itemImg,itemPrice,itemName,userIp,itemSite,itemType,itemCurrency,itemOutFit,itemSale) VALUES (:userId,:itemHref,:itemImg,:itemPrice,:itemName,:userIp,:itemSite,:itemType,:itemCurrency,:itemOutFit,:itemSale)";
$q = $conn->prepare($sql);
$q->execute(array(':userId'=>$userId,
':itemHref'=>$itemHref[$key],
':itemImg'=>$itemImg[$key],
':itemPrice'=>$itemPrice[$key],
':itemName'=>$itemName[$key],
':userIp'=>$userIp,
':itemSite'=>$itemSite,
':itemType'=>$itemType,
':itemCurrency'=>$itemCurrency,
':itemOutFit'=>$itemOutFit,
':itemSale'=>$itemSale));
} else {
echo "NOT CHECKED";
echo "<br>";
}
/*
echo $conn->errorCode();
echo "<br>"; ('SET CHARACTER SET utf8')
echo $conn->errorInfo();
echo "<br>";
//die(print_r($q->errorInfo(), true));
*/
}
UPDATE Tried to strip php down to basic code, still no luck. Does the same thing....anyone have an idea how I can fix this.
foreach($_POST['itemCheckBox'] as $key => $val)
{
$i = 0;
$itemCheckBox = $_POST['itemCheckBox'];
$itemName = $_POST['itemName'];
$itemHref = $_POST['itemHref'];
$itemImg = $_POST['itemImg'];
$itemPrice = $_POST['itemPrice'];
echo $i;
echo "<br>";
$i = $i +1;
if (isset($_POST['itemCheckBox'])){
echo "<br>";
echo "CHECKED";
echo "<br>";
echo "<br>";
echo $itemCheckBox[$i];
echo "<br>";
echo $itemName[$i];
echo "<br>";
echo $itemHref[$i];
echo "<br>";
echo $itemImg[$i];
echo "<br>";
echo $itemPrice[$i];
} else {
echo "NOT CHECKED";
echo "<br>";
$i = $i +1;
}
}
A couple things I spots that may be contributing to the issue:
In your PHP you have a line that has this:
//Remove non numaric characters from price(leave commas).
$itemPrice = preg_replace('/[^0-9,.]/s', '', $itemPrice);
I don't see where $itemPrice is defined though, should it be:
$itemPrice = preg_replace('/[^0-9,.]/s', '', $fields['itemPrice']);
Your issue of getting the "Warning: Invalid argument supplied for foreach() in /home..." can be solved by checking to make sure it exists and is an array beforelooping. You can use !empty() and is_array() to check.
if(!empty($_POST['itemCheckBox']) and is_array($_POST['itemCheckBox'])){}
Side Issue:
Your IDs for the inputs are all the same, "itemCheckBox[]", "itemName[]", etc.. are the same ID used for all of them. This may cause problems in the future if you want to use javascript or css properly.
Edit:
In your revised example the issue is that each time it cycles into the loop it is setting $i=0 because you declare it at the top of the foreach. If you go back to using the $key as the index it should work. See below:
//GROUP 1 checkbox
<input id="itemCheckBox[]" type="checkbox" value="0" name="itemCheckBox[]"></input>
//GROUP 2 checkbox
<input id="itemCheckBox[]" type="checkbox" value="1" name="itemCheckBox[]"></input>
I may also advise that you adjust your HTML items to match the Key you are passing:
<input id="itemName[1]" type="hidden" value="Bomber Jacket With Fur" name="itemName[]"></input>
<input id="itemHref[1]" type="hidden" value="http://random.com/Bomber-Jacket-With-fur/.." name="itemHref[]"></input>
<input id="itemImg[1]" type="hidden" value="http://images.com/i/image_xl.jpg" name="itemImg[]"></input>
<input id="itemPrice[1]" type="hidden" value="$88.88" name="itemPrice[]"></input>
foreach($_POST['itemCheckBox'] as $key => $val) {
$itemCheckBox = $_POST['itemCheckBox'];
$itemName = $_POST['itemName'];
$itemHref = $_POST['itemHref'];
$itemImg = $_POST['itemImg'];
$itemPrice = $_POST['itemPrice'];
if (isset($_POST['itemCheckBox'])){
echo "<br>";
echo "CHECKED";
echo $itemCheckBox[$key];
echo "<br>";
echo "<br>";
echo $itemCheckBox[$itemCheckBox[$key]];
echo "<br>";
echo $itemName[$itemCheckBox[$key]];
echo "<br>";
echo $itemHref[$itemCheckBox[$key]];
echo "<br>";
echo $itemImg[$itemCheckBox[$key]];
echo "<br>";
echo $itemPrice[$itemCheckBox[$key]];
} else {
echo "NOT CHECKED";
echo "<br>";
}
}
<!DOCTYPE html>
<html>
<head>
<title>Talenquiz2</title>
</head>
<body>
<?php
if (isset($_GET["controleer"]))
{
$vraag = $_GET["vraag"];
$juistantwoord = $_GET["juistantwoord"];
$foutantwoord1 = $_GET["foutantwoord1"];
$foutantwoord2 = $_GET["foutantwoord2"];
$con = mysql_connect("localhost","root","");
mysql_select_db("dbproject", $con);
$result = mysql_query("SELECT * FROM tblquizvragen");
while($row = mysql_fetch_array($result))
{
if ($row['vraag'] == $vraag)
{
if ($row['juistantwoord'] == $juistantwoord)
{
echo "Juist!<br />";
}
else
{
echo "Fout!<br />";
}
}
}
mysql_close($con);
echo "\n<hr />\n";
}
$aantalvragen=1;
$con = mysql_connect("localhost","root","");
mysql_select_db("dbproject", $con);
$result = mysql_query("SELECT * FROM tblquizvragen WHERE id='". $aantalvragen . "';");
$row = mysql_fetch_array($result);
The program is a quiz, it asks 5 questions with 3 chckbox 1 is corect and 2 are incorrect.
for ($aantalvragen=1; $aantalvragen<=5; $aantalvragen++)
{
$row = mysql_fetch_array($result);
}
her i lin
$vraag = $row['vraag'];
$juistantwoord = $row['juistantwoord'];
$foutantwoord1 = $row['foutantwoord1'];
$foutantwoord2 = $row['foutantwoord2'];
mysql_close($con);
?>
<form>
It doensn't show the values of the rows in my browser it shows only an open text and an open checkbox.
<input type="text" name="vraag" value="<?php echo $vraag; ?>" /><br />
<input type="checkbox" name="juistantwoord" value="<?php echo $juistantwoord; ?>" /><br />
<input type="checkbox" name="foutantwoord1" value="<?php echo $foutantwoord1; ?>" /><br />
<input type="checkbox" name="foutantwoord2" value="<?php echo $foutantwoord2; ?>" /><br />
<input type="submit" value="Controleer je antwoord" name="controleer" />
</form>
</body>
</html>
Your code is incorrect for fetching from the db
for(...) {
$row = mysql_fetch_array(...);
}
You simply loop over 5 lines of results, regardless of how many there may be, and assign the row array to $row... but do so for EVERY row without ever using them. So you end up trashing the first n-1 rows and come out of the loop with only row n saved.
If you're wrong with how many rows of data you're expecting, your 5-item loop may have only a 4-item result set to deal with, and the final row $row1 value will be the boolean FALSE that msyql_fetch returns when there's no more data.
Try something like this instead:
while($row = mysql_fetch_assoc($result)) {
echo ..... your stuff here ...
}
Far more reliable, doesn't depend on there being a known number of rows available, and will not output anything if there's no data at all.
I am trying to create a compare option between selected cars.
<?php
if(isset($_POST['compares'])) {
$id_nums = array($_POST['cBox']);
//$id_nums = array(1,6,12,18,24);
$id_nums1 = implode(", ", $id_nums);
$query = "SELECT * FROM wp_cars WHERE id in ($id_nums1)";
$cCars = mysql_query($query) or mysql_error();
while($car = mysql_fetch_array($cCars)) {
echo $car['cartitle']."<br/>";
echo $car['saleprice']."<br/>";
}
} else {
$query1 = "SELECT * FROM wp_cars";
$allcars = mysql_query($query1) or die(mysql_error()); `
while($car1 = mysql_fetch_array($allcars)) {
echo "<input type='checkbox' value=".$car1['id']." name='cBox[]' />";
echo $car1['cartitle']."<br/>";
echo $car1['saleprice']."<br/>";
}
}
?>
How to pass the checkbox name(cBox[]) array based on checkboxes selection.
<form action="compares.php" method="post">
<button name="compares">Select Cars to Compare</button>
</form>
$id_nums = array($_POST['cBox']);
$_POST['cBox'] is already an array, you are making a 2d array. Doing
$id_nums1 = implode(", ", $_POST['cBox']);
would do what you want. Although it is wide open to SQL injection.
From your HTML part, send inputs this way:
<form action="compares.php" method="post">
<?php foreach (mysql_fetch_array($allcars) as $car: ?>
<input type="checkbox" value="<?php echo $car['id']; ?>" name="cBox[]" />
<?php echo $car['cartitle']; ?><br />
<?php echo $car['saleprice']; ?><br />
<?php endforeach; ?>
</form>
And in your PHP part, receive inputs this way:
$id_nums = implode(",", $_POST['cBox']);