Get both insert_id and updated row id in insert_update query - php

I have a query like this:
SET #uids = '';
INSERT INTO tbl1 (name,used,is_active)
VALUES (1,0,0),(2,0,0),(24,0,0)
ON DUPLICATE KEY UPDATE
id = LAST_INSERT_ID(id)
, used = (SELECT #uids := concat_ws(',', LAST_INSERT_ID(), #uids))
, used = used+1
, is_active = CASE WHEN used > 3 THEN 1 ELSE 0 END;
SELECT #uids;
See here to figure out the way of getting updated row id.
I get updated row ids' in #uids if it updates any rows but if a row is inserted, I can't get the id of that. So how to get both inserted row id and updated row id?
Or how to execute (SELECT #uids := concat_ws(',', LAST_INSERT_ID(), #uids)) in insert before ON DUPLICATE KEY... ?

Time's short and we are long
You can't do it, because there is no way to fill #uids while inserting which needs a select clause and you are not allowed to use a select clause within an insert statement unless your query can be transformed into an INSERT ... SELECT.
Long answer
As long as you don't try to insert mixed values that may result in both updating and inserting (which probably you do) there is a nasty but safe way you can go with:
SET #uids := '';
INSERT INTO `tbl1` (name, used, is_active)
VALUES (1,0,0),(2,0,0),(24,0,0)
ON DUPLICATE KEY UPDATE
is_active = CASE WHEN used > 3 THEN 1 ELSE 0 END,
id = LAST_INSERT_ID(id),
used = used + 1,
id = (SELECT #uids := concat_ws(',', LAST_INSERT_ID(), #uids));
SELECT #uids, LAST_INSERT_ID() as f, MAX(id) as l from `tbl1`;
Being not so tricky, you have two values at the end:
LAST_INSERT_ID() as f is the first inserted row ID
MAX(id) as l which is last inserted row ID
So with that two boundaries you surly have all inserted rows IDs. Saying that it has drawbacks and that is you always have a LAST_INSERT_ID() value even if rows only were affected by update statement. However as you tagged your question with php there was a chance to get benefit from mysqli_affected_rows while doing a multi_query but I couldn't produce expected return values from mysqli_affected_rows as is documented by MySQL:
For INSERT ... ON DUPLICATE KEY UPDATE statements, the affected-rows
value per row is 1 if the row is inserted as a new row, 2 if an
existing row is updated, and 0 if an existing row is set to its
current values.
You can try it yourself and see if it works. If you get an expected return value then you can understand if your query has done some updates or inserts and read results based on that
As my short answer, there is no correct way to do it within the same query context but may be doing it programatically is neater? (though I don't bet on its performance)
$values = [[1, 0, 0], [2, 0, 0], [24, 0, 0]];
$insertIDs = [];
$updateIDs = [];
foreach ($values as $v) {
$insert = $mysqli->prepare("INSERT INTO `tbl1` (name, used, is_active) VALUES (?, ?, ?)");
$insert->bind_param('ddd', $v[0], $v[1], $v[2]);
$insert->execute();
if ($insert->affected_rows == -1) {
$update = $mysqli->prepare("UPDATE `tbl1` SET id = LAST_INSERT_ID(id), used = used + 1, is_active = CASE WHEN used > 3 THEN 1 ELSE 0 END WHERE name = ?"); // considering `name` as a unique column
$update->bind_param('d', $v[0]);
$update->execute();
if ($update->affected_rows == 1) {
$updateIDs[] = $update->insert_id;
}
} else {
$insertIDs[] = $insert->insert_id;
}
}
var_dump($updateIDs);
var_dump($insertIDs);
Example output:
array(1) {
[0]=>
int(140)
}
array(1) {
[0]=>
int(337)
}
One another workaround could be using MySQL triggers. By creating an AFTER INSERT trigger on table tbl1, you are able to store IDs for later use:
CREATE TRIGGER trigger_tbl1
AFTER INSERT
ON `tbl1` FOR EACH ROW
BEGIN
UPDATE `some_table` SET last_insert_ids = concat_ws(',', LAST_INSERT_ID(), last_insert_ids) WHERE id = 1;
END;

Related

pdo get the last inserted id or the last updated row

I have a PDO statement that insert or update a row depending on a UNIQUE column (if the column exist then update) . I wonder if there is a solution for both to get the id of the INSERTED or UPDATED that I could use in the same query. So ...
considering this answer ... how could it be together?
SET #update_id := 0;
UPDATE some_table SET column_name = 'value', id = (SELECT #update_id := id)
WHERE some_other_column = 'blah' LIMIT 1;
SELECT #update_id;
plus
lastInsertId();
meaning something like (I'm not sure if there would be a sintax for this so I just set what i have in mind:
IF "INSERT" then SELECT lastInsertId()
else if "UPDATE" then select ID of the last row updated;

PHP check if MYSQL query was an insert or update

I have a simple MYSQL query:
INSERT INTO table (col1,col2) VALUES ('1','2')
ON DUPLICATE KEY UPDATE col1 = '1', col2 = '2'
I use PHP PDO statements to query the database. Is there a way to know if the query executed resulted into a new inserted row or an existing was updated?
One way to do so is to get the number of rows before executing the query, then get the number of rows after executing the query, if they're not equal, it means a new row was inserted and if they are equal, it means a row was updated.
$sql = "SHOW TABLE STATUS LIKE 'TABLE_NAME'";
$stmt = $pdo->prepare($sql);
$stmt->execute();
$row = $stmt->fetch();
$number_of_rows_before = $row['Rows'];
// Do your query here, afterwards
$stmt = $pdo->prepare($sql);
$stmt->execute();
$row = $stmt->fetch();
$number_of_rows_after = $row['Rows'];
// If condition
if($number_of_rows_before == $number_of_rows_after) // Update was executed
else // a new row was inserted.
Just use mysqli_affected_rows,it returns the number of rows affected by the last INSERT, UPDATE, REPLACE or DELETE query.
From PHP documentation:
In the case of "INSERT ... ON DUPLICATE KEY UPDATE" queries, the return value will be 1 if an insert was performed, or 2 for an update of an existing row.
see https://www.php.net/manual/en/function.mysql-affected-rows.php
From Mysql manual:
"With ON DUPLICATE KEY UPDATE, the affected-rows value per row is 1 if
the row is inserted as a new row and 2 if an existing row is updated."
See: http://dev.mysql.com/doc/refman/5.0/en/insert-on-duplicate.html
This is the most reliable way to do it.
maybe you put the answer right into the query like:
INSERT INTO table (col1,col2, col_type) VALUES ('1','2','inserted')
ON DUPLICATE KEY UPDATE col1 = '1', col2 = '2', col_type = 'updated'

Insert multiple rows with same unique ID

I am inserting multiple rows using one query and, obviously, the ID column auto increments each row. I want to create another ID column and have the ID remain the same for all rows inserted during the query. So if I insert 10 rows during one query, I want all 10 rows to have the id "1". How can this be done? Thanks for any help
If I understood your question correctly, you want to supply an ID for the specific group of INSERT statements.
Assumming you have this schema
CREATE TABLE TableName
(
RecordID INT AUTO_INCREMENT PRIMARY KEY,
OtherColumn VARCHAR(25) NOT NULL,
GroupID INT NOT NULL
)
You can have two statements for this:
1.) Getting the last GroupID and increment it by 1.
SELECT COALESCE(MAX(GroupID), 0) + 1 AS newGroupID FROM TableName
2.) once you have executed it, store the value in a variable. Use this variable for all the insert statement,
$groupID = row['newGroupID'];
$insert1 = "INSERT INTO TableName(OtherColumn, GroupID) VALUES ('a', $groupID)";
$insert2 = "INSERT INTO TableName(OtherColumn, GroupID) VALUES ('b', $groupID)";
$insert3 = "INSERT INTO TableName(OtherColumn, GroupID) VALUES ('c', $groupID)";
UPDATE 1
SQLFiddle Demo

Count rows in one table within a IF statement

Is it possible to check if num rows in a table is 0 then perform an insert, all in ONE sql statement?
Here's my query that I tried but it says I have a syntax error:
$query =
"IF (SELECT COUNT(ID) FROM votes WHERE userid = $userid AND itemid = $itemid AND itemtype=1) = 0
INSERT INTO votes (itemtype, itemid, userid) VALUES (1, $itemid, $userid)
SELECT 1 AS result
ELSE
SELECT 0 AS result
END IF";
I know the SELECT COUNT bit works successfully on its own.
NO IDEA if this is the best way of solving this, but it will work. Basically, it simply causes an error if the condition is false, and so it prevents insert:
-- make itemtype not nullable then simply insert
INSERT INTO votes SELECT
CASE
WHEN
(SELECT COUNT(ID)
FROM votes
WHERE userid = $userid AND itemid = $itemid AND itemtype=1) = 0 THEN 1
ELSE NULL
END CASE,
$itemid, $userid;
I don't have access to MySQL to test this right now, but would this work?
INSERT INTO votes (itemtype, itemid, userid)
(SELECT 1,$itemid, $userid
WHERE NOT EXISTS (
SELECT *
FROM votes
WHERE itemtype=1
AND itemid=$itemid
AND userid=$userid))

Show item of the day

I am looking to create a function that gets me a random item from a mySQL table, but let's me keep the returned as the "item of the day". In other words, the item that was "the item of the day" yesterday should not be shown again until all other items have been shown as item of the day.
Any suggestions on how to do this in an elegant way?
Thanks
Add a bool column "UsedAsItemOfTheDay" set to false (0). Update to true when item is picked. Exclude already used items from the picking process.
SELECT * FROM `table`
WHERE UsedAsItemOfTheDay = 0
ORDER BY RAND() LIMIT 1;
(Note: this is not the fastest way to return a random row in MySql; it will be slow on huge tables)
See also: quick selection of a random row from a large table in mysql
SELECT <fields> FROM <table> WHERE <some logic to exclude already used> ORDER BY RAND() LIMIT 1 will get you a random row from the table.
Add a column to store whether the item has been used:
ALTER TABLE your_table ADD COLUMN isused BOOL DEFAULT 0;
Get a random item of the day:
SELECT t.*
FROM your_table t
WHERE t.isused = 0
ORDER BY RAND()
LIMIT 1
Now update that record so it can't be used in the future:
UPDATE your_table
SET isused = 1
WHERE id = id_from_select_random_statement
People who "know" SQL will look for declarative solutions and will shun procedural code. Flagging rows is a "smell" for procedural code.
Is the set of Items static (never changes) or stable (rarely changes)? If yes, it would be easier to do a one-off exercise of generating a lookup table of values from now until the end of time, rather than scheduling a proc to running daily to look for unused flags and update the flag for today and clear all flags if all have been used etc.
Create a table of sequential dates between today and a far future date representing the lifetime of your application (you could consider omitting non-business days, of course). Add a column(s) referencing the key in you Items table (ensure you opt for ON DELETE NO ACTION referential action just in case those Items prove not to be static!) Then randomly assign the whole set of Items one per day until each has been used once. Repeat again for the whole set of Items until the table is full. You could easily generate this data using a spreadsheet and import it (or pure SQL if you are hardcore ;)
Quick example using Standard SQL:
Say there are only five Items in the set:
CREATE TABLE Items
(
item_ID INTEGER NOT NULL UNIQUE
);
INSERT INTO Items (item_ID)
VALUES (1),
(2),
(3),
(4),
(5);
You lookup table would be as simple as this:
CREATE TABLE ItemsOfTheDay
(
cal_date DATE NOT NULL UNIQUE,
item_ID INTEGER NOT NULL
REFERENCES Items (item_ID)
ON DELETE NO ACTION
ON UPDATE CASCADE
);
Starting with today, add the whole set of Items in random order:
INSERT INTO Items (item_ID)
VALUES ('2010-07-13', 2),
('2010-07-14', 4),
('2010-07-15', 5),
('2010-07-16', 1),
('2010-07-17', 3);
Then, starting with the most recent unfilled date, add the whole set of Items in (hopefully a different) random order:
INSERT INTO Items (item_ID)
VALUES ('2010-07-18', 1),
('2010-07-19', 3),
('2010-07-20', 4),
('2010-07-21', 5),
('2010-07-22', 2);
...and again...
INSERT INTO Items (item_ID)
VALUES ('2010-07-23', 2),
('2010-07-24', 3),
('2010-07-25', 5),
('2010-07-26', 1),
('2010-07-27', 4);
..and so on until the table is full.
Then it would then simply be a case of looking up today's date in the lookup table as and when required.
If the set of Items changes then the lookup table would obviously need to be regenerated, so you need to balance out the simplicity of design against the need for manual maintenance.
If you have fixed items you can add column
ALTER TABLE your_table ADD COLUMN item_day INT DEFAULT 0;
then selecting item use
WHERE item_day = DATE_FORMAT('%j')
If you get empty result then you can format new list of day items:
<?php
$qry = " UPDATE your_table SET item_day = 0";
$db->execute($qry);
// You only need 355 item to set as item of the day
for($i = 0; $i < 355; $i++) {
$qry = "UPDATE your_table SET item_day = ".($i+1)." WHERE item_day = 0 ORDER BY RAND() LIMIT 1";
$rs = $db->execute($qry);
// If no items left stop update
if (!$rs) { break; }
}
?>
Here's a stored procedure which selects a random row without using ORDER BY RAND(), and which resets the used flag once all items have been used:
DELIMITER //
DROP PROCEDURE IF EXISTS random_iotd//
CREATE PROCEDURE random_iotd()
BEGIN
# Reset used flag if all the rows have been used.
SELECT COUNT(*) INTO #used FROM iotd WHERE used = 1;
SELECT COUNT(*) INTO #rows FROM iotd;
IF (#used = #rows) THEN
UPDATE iotd SET used = 0;
END IF;
# Select a random number between 1 and the number of unused rows.
SELECT FLOOR(RAND() * (#rows - #used)) INTO #rand;
# Select the id of the row at position #rand.
PREPARE stmt FROM 'SELECT id INTO #id FROM iotd WHERE used = 0 LIMIT ?,1';
EXECUTE stmt USING #rand;
# Select the row where id = #id.
PREPARE stmt FROM 'SELECT id, item FROM iotd WHERE id = ?';
EXECUTE stmt USING #id;
# Update the row where id = #id.
PREPARE stmt FROM 'UPDATE iotd SET used = 1 WHERE id = ?';
EXECUTE stmt USING #id;
DEALLOCATE PREPARE stmt;
END;
//
DELIMITER ;
To use:
CALL random_iotd();
The procedure assumes a table structure like this:
CREATE TABLE `iotd` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`item` varchar(255) NOT NULL,
`used` BOOLEAN NOT NULL DEFAULT 0,
INDEX `used` (`used`),
PRIMARY KEY (`id`)
) ENGINE=InnoDB;
Here's one way to get the result from PHP (to keep things simple, error checking has been removed):
$mysqli = new mysqli('localhost', 'root', 'password', 'database');
$stmt = $mysqli->prepare('CALL random_iotd()');
$stmt->execute();
$stmt->bind_result($id, $item);
$stmt->fetch();
echo "$id, $item\n";
// 4, Item 4
UPADATE
This version should return the same result repeatedly on a given date. I've not really had time to test this, so be sure to do some testing of your own...
DELIMITER //
DROP PROCEDURE IF EXISTS random_iotd//
CREATE PROCEDURE random_iotd()
BEGIN
# Get today's item.
SET #id := NULL;
SELECT id INTO #id FROM iotd WHERE ts = CURRENT_DATE();
IF ISNULL(#id) THEN
# Reset used flag if all the rows have been used.
SELECT COUNT(*) INTO #used FROM iotd WHERE used = 1;
SELECT COUNT(*) INTO #rows FROM iotd;
IF (#used = #rows) THEN
UPDATE iotd SET used = 0;
END IF;
# Select a random number between 1 and the number of unused rows.
SELECT FLOOR(RAND() * (#rows - #used)) INTO #rand;
# Select the id of the row at position #rand.
PREPARE stmt FROM 'SELECT id INTO #id FROM iotd WHERE used = 0 LIMIT ?,1';
EXECUTE stmt USING #rand;
# Update the row where id = #id.
PREPARE stmt FROM 'UPDATE iotd SET used = 1, ts = CURRENT_DATE() WHERE id = ?';
EXECUTE stmt USING #id;
END IF;
# Select the row where id = #id.
PREPARE stmt FROM 'SELECT id, item FROM iotd WHERE id = ?';
EXECUTE stmt USING #id;
DEALLOCATE PREPARE stmt;
END;
//
DELIMITER ;
And the table structure:
CREATE TABLE `iotd` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`item` varchar(255) NOT NULL,
`used` BOOLEAN NOT NULL DEFAULT 0,
`ts` DATE DEFAULT 0,
INDEX `used` (`used`),
INDEX `ts` (`ts`),
PRIMARY KEY (`id`)
) ENGINE=InnoDB;
Why don't you use sequence?
Sequence serves your purpose easily...

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