MySQLi how to check if table exists? [duplicate] - php

Question

This question already has answers here:
MySQLi Table Exists
(5 answers)
Closed 3 years ago.
I want to create table by app if there's no such table. But doing it for the first time... Need some help, tho
//connecting...
$mysqli = new mysqli($db_params['host'], $db_params['login'], $db_params['pass'], $db_params['name']);
if ($mysqli->query("SHOW TABLES LIKE `products`")){
echo ' YES';
} else echo 'no';
It always says NO.

Answer 1

Read their documentation? https://dev.mysql.com/doc/refman/5.5/en/replication-features-create-if-not-exists.html Seems like you can do that easily:
CREATE TABLE IF NOT EXISTS `products`
This way you don't have to check first whether a table exists or not, you just create one if it doesn't.
And it seems like you have a syntax error, which is probably the reason why your code keeps returning "no". This should work:
SHOW TABLES LIKE 'products';
Just use single or double quotes, no backticks like `.
You use backticks (`) for table and column names, single (') or double quotes (") for strings, in this case you are giving a string so you should use single or double quotes.

Answer 2

In order to create a table if it not exists, you can use
CREATE TABLE IF NOT EXISTS

Answer 3

Use PHP DESCRIBE statement.
if(mysql_query("DESCRIBE `table_name`")) {
// Exists
}

Answer 4

This solution works for me JUST FINE:
<?php
// connect to the "tests" database
$conn = new mysqli('localhost', 'root', 'pass', 'tests');
// check connection
if (mysqli_connect_errno()) {
exit('Connect failed: '. mysqli_connect_error());
}
// SQL query
$sql = "SHOW TABLES IN `tests`";
// perform the query and store the result
$result = $conn->query($sql);
// if the $result not False, and contains at least one row
if($result !== false) {
// if at least one table in result
if($result->num_rows > 0) {
// traverse the $result and output the name of the table(s)
while($row = $result->fetch_assoc()) {
echo '<br />'. $row['Tables_in_tests'];
}
}
else echo 'There is no table in "tests"';
}
else echo 'Unable to check the "tests", error - '. $conn->error;
$conn->close();
?>
For a complete and more examples, here the source : http://coursesweb.net/php-mysql/check-table-exists-database_t